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Etableau---0.67.THM-CRf.s

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%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : ALG198+1 : TPTP v8.1.0. Released v2.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 14 16:51:55 EDT 2022

% Result   : Theorem 0.20s 0.39s
% Output   : CNFRefutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    1
% Syntax   : Number of formulae    :    6 (   3 unt;   0 def)
%            Number of atoms       :   45 (  44 equ)
%            Maximal formula atoms :   14 (   7 avg)
%            Number of connectives :   64 (  25   ~;   0   |;  39   &)
%                                         (   0 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   16 (   8 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   7 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn   0   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(co1,conjecture,
    ~ ( op(e0,e0) != e0
      & op(e1,e1) != e1
      & op(e2,e2) != e2
      & op(e3,e3) != e3
      & op(e4,e4) != e4
      & op(e5,e5) != e5
      & op(e6,e6) != e6
      & op(e0,e0) = e0
      & op(e1,e1) = e1
      & op(e2,e2) = e2
      & op(e3,e3) = e3
      & op(e4,e4) = e4
      & op(e5,e5) = e5
      & op(e6,e6) = e6 ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',co1) ).

fof(c_0_1,negated_conjecture,
    ~ ~ ( op(e0,e0) != e0
        & op(e1,e1) != e1
        & op(e2,e2) != e2
        & op(e3,e3) != e3
        & op(e4,e4) != e4
        & op(e5,e5) != e5
        & op(e6,e6) != e6
        & op(e0,e0) = e0
        & op(e1,e1) = e1
        & op(e2,e2) = e2
        & op(e3,e3) = e3
        & op(e4,e4) = e4
        & op(e5,e5) = e5
        & op(e6,e6) = e6 ),
    inference(assume_negation,[status(cth)],[co1]) ).

fof(c_0_2,negated_conjecture,
    ( op(e0,e0) != e0
    & op(e1,e1) != e1
    & op(e2,e2) != e2
    & op(e3,e3) != e3
    & op(e4,e4) != e4
    & op(e5,e5) != e5
    & op(e6,e6) != e6
    & op(e0,e0) = e0
    & op(e1,e1) = e1
    & op(e2,e2) = e2
    & op(e3,e3) = e3
    & op(e4,e4) = e4
    & op(e5,e5) = e5
    & op(e6,e6) = e6 ),
    inference(fof_nnf,[status(thm)],[c_0_1]) ).

cnf(c_0_3,negated_conjecture,
    op(e0,e0) != e0,
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_4,negated_conjecture,
    op(e0,e0) = e0,
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_5,negated_conjecture,
    $false,
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_3,c_0_4])]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : ALG198+1 : TPTP v8.1.0. Released v2.7.0.
% 0.03/0.13  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.14/0.34  % Computer : n017.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit : 300
% 0.14/0.34  % WCLimit  : 600
% 0.14/0.34  % DateTime : Wed Jun  8 18:02:48 EDT 2022
% 0.14/0.34  % CPUTime  : 
% 0.20/0.39  # No SInE strategy applied
% 0.20/0.39  # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.20/0.39  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.20/0.39  #
% 0.20/0.39  # Presaturation interreduction done
% 0.20/0.39  
% 0.20/0.39  # Proof found!
% 0.20/0.39  # SZS status Theorem
% 0.20/0.39  # SZS output start CNFRefutation
% See solution above
% 0.20/0.39  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------