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Otter---3.3.UNS-Ref.s

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%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : COL004-3 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:47:58 EDT 2022

% Result   : Unsatisfiable 1.66s 1.86s
% Output   : Refutation 1.66s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    3
% Syntax   : Number of clauses     :   10 (  10 unt;   0 nHn;   4 RR)
%            Number of literals    :   10 (   9 equ;   3 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    9 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   4 con; 0-2 aty)
%            Number of variables   :   16 (   4 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    apply(apply(apply(apply(s,apply(k,apply(s,apply(apply(s,k),k)))),apply(apply(s,apply(apply(s,k),k)),apply(apply(s,k),k))),x),y) != apply(y,apply(apply(x,x),y)),
    file('COL004-3.p',unknown),
    [] ).

cnf(3,axiom,
    apply(apply(apply(s,A),B),C) = apply(apply(A,C),apply(B,C)),
    file('COL004-3.p',unknown),
    [] ).

cnf(5,axiom,
    apply(apply(k,A),B) = A,
    file('COL004-3.p',unknown),
    [] ).

cnf(6,plain,
    apply(apply(A,B),apply(C,B)) = apply(apply(apply(s,A),C),B),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[3])]),
    [iquote('copy,3,flip.1')] ).

cnf(7,plain,
    apply(apply(apply(s,apply(apply(s,k),k)),apply(apply(apply(s,apply(apply(s,k),k)),apply(apply(s,k),k)),x)),y) != apply(y,apply(apply(x,x),y)),
    inference(demod,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[3,1]),5]),
    [iquote('para_from,3.1.1,1.1.1.1,demod,5')] ).

cnf(16,plain,
    apply(apply(apply(s,k),A),B) = B,
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[6,5])]),
    [iquote('para_into,6.1.1,4.1.1,flip.1')] ).

cnf(31,plain,
    apply(A,apply(B,A)) = apply(apply(apply(s,apply(apply(s,k),C)),B),A),
    inference(para_from,[status(thm),theory(equality)],[16,6]),
    [iquote('para_from,15.1.1,6.1.1.1')] ).

cnf(33,plain,
    apply(apply(apply(s,apply(apply(s,k),A)),B),C) = apply(C,apply(B,C)),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[31])]),
    [iquote('copy,31,flip.1')] ).

cnf(34,plain,
    apply(apply(apply(s,apply(apply(s,k),k)),apply(x,x)),y) != apply(y,apply(apply(x,x),y)),
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[7,3]),16,16]),
    [iquote('para_into,7.1.1.1.2,3.1.1,demod,16,16')] ).

cnf(35,plain,
    $false,
    inference(binary,[status(thm)],[34,33]),
    [iquote('binary,34.1,33.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : COL004-3 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n028.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 02:34:03 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.66/1.86  ----- Otter 3.3f, August 2004 -----
% 1.66/1.86  The process was started by sandbox on n028.cluster.edu,
% 1.66/1.86  Wed Jul 27 02:34:03 2022
% 1.66/1.86  The command was "./otter".  The process ID is 17613.
% 1.66/1.86  
% 1.66/1.86  set(prolog_style_variables).
% 1.66/1.86  set(auto).
% 1.66/1.86     dependent: set(auto1).
% 1.66/1.86     dependent: set(process_input).
% 1.66/1.86     dependent: clear(print_kept).
% 1.66/1.86     dependent: clear(print_new_demod).
% 1.66/1.86     dependent: clear(print_back_demod).
% 1.66/1.86     dependent: clear(print_back_sub).
% 1.66/1.86     dependent: set(control_memory).
% 1.66/1.86     dependent: assign(max_mem, 12000).
% 1.66/1.86     dependent: assign(pick_given_ratio, 4).
% 1.66/1.86     dependent: assign(stats_level, 1).
% 1.66/1.86     dependent: assign(max_seconds, 10800).
% 1.66/1.86  clear(print_given).
% 1.66/1.86  
% 1.66/1.86  list(usable).
% 1.66/1.86  0 [] A=A.
% 1.66/1.86  0 [] apply(apply(apply(s,X),Y),Z)=apply(apply(X,Z),apply(Y,Z)).
% 1.66/1.86  0 [] apply(apply(k,X),Y)=X.
% 1.66/1.86  0 [] apply(apply(apply(apply(s,apply(k,apply(s,apply(apply(s,k),k)))),apply(apply(s,apply(apply(s,k),k)),apply(apply(s,k),k))),x),y)!=apply(y,apply(apply(x,x),y)).
% 1.66/1.86  end_of_list.
% 1.66/1.86  
% 1.66/1.86  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.66/1.86  
% 1.66/1.86  All clauses are units, and equality is present; the
% 1.66/1.86  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.66/1.86  
% 1.66/1.86     dependent: set(knuth_bendix).
% 1.66/1.86     dependent: set(anl_eq).
% 1.66/1.86     dependent: set(para_from).
% 1.66/1.86     dependent: set(para_into).
% 1.66/1.86     dependent: clear(para_from_right).
% 1.66/1.86     dependent: clear(para_into_right).
% 1.66/1.86     dependent: set(para_from_vars).
% 1.66/1.86     dependent: set(eq_units_both_ways).
% 1.66/1.86     dependent: set(dynamic_demod_all).
% 1.66/1.86     dependent: set(dynamic_demod).
% 1.66/1.86     dependent: set(order_eq).
% 1.66/1.86     dependent: set(back_demod).
% 1.66/1.86     dependent: set(lrpo).
% 1.66/1.86  
% 1.66/1.86  ------------> process usable:
% 1.66/1.86  ** KEPT (pick-wt=37): 1 [] apply(apply(apply(apply(s,apply(k,apply(s,apply(apply(s,k),k)))),apply(apply(s,apply(apply(s,k),k)),apply(apply(s,k),k))),x),y)!=apply(y,apply(apply(x,x),y)).
% 1.66/1.86  
% 1.66/1.86  ------------> process sos:
% 1.66/1.86  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.66/1.86  ** KEPT (pick-wt=15): 3 [] apply(apply(apply(s,A),B),C)=apply(apply(A,C),apply(B,C)).
% 1.66/1.86  ** KEPT (pick-wt=7): 4 [] apply(apply(k,A),B)=A.
% 1.66/1.86  ---> New Demodulator: 5 [new_demod,4] apply(apply(k,A),B)=A.
% 1.66/1.86    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.66/1.86  ** KEPT (pick-wt=15): 6 [copy,3,flip.1] apply(apply(A,B),apply(C,B))=apply(apply(apply(s,A),C),B).
% 1.66/1.86  >>>> Starting back demodulation with 5.
% 1.66/1.86    Following clause subsumed by 3 during input processing: 0 [copy,6,flip.1] apply(apply(apply(s,A),B),C)=apply(apply(A,C),apply(B,C)).
% 1.66/1.86  
% 1.66/1.86  ======= end of input processing =======
% 1.66/1.86  
% 1.66/1.86  =========== start of search ===========
% 1.66/1.86  
% 1.66/1.86  -------- PROOF -------- 
% 1.66/1.86  
% 1.66/1.86  ----> UNIT CONFLICT at   0.00 sec ----> 35 [binary,34.1,33.1] $F.
% 1.66/1.86  
% 1.66/1.86  Length of proof is 6.  Level of proof is 4.
% 1.66/1.86  
% 1.66/1.86  ---------------- PROOF ----------------
% 1.66/1.86  % SZS status Unsatisfiable
% 1.66/1.86  % SZS output start Refutation
% See solution above
% 1.66/1.86  ------------ end of proof -------------
% 1.66/1.86  
% 1.66/1.86  
% 1.66/1.86  Search stopped by max_proofs option.
% 1.66/1.86  
% 1.66/1.86  
% 1.66/1.86  Search stopped by max_proofs option.
% 1.66/1.86  
% 1.66/1.86  ============ end of search ============
% 1.66/1.86  
% 1.66/1.86  -------------- statistics -------------
% 1.66/1.86  clauses given                  6
% 1.66/1.86  clauses generated             30
% 1.66/1.86  clauses kept                  29
% 1.66/1.86  clauses forward subsumed      27
% 1.66/1.86  clauses back subsumed          0
% 1.66/1.86  Kbytes malloced              976
% 1.66/1.86  
% 1.66/1.86  ----------- times (seconds) -----------
% 1.66/1.86  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.66/1.86  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.66/1.86  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.66/1.86  
% 1.66/1.86  That finishes the proof of the theorem.
% 1.66/1.86  
% 1.66/1.86  Process 17613 finished Wed Jul 27 02:34:05 2022
% 1.66/1.86  Otter interrupted
% 1.66/1.86  PROOF FOUND
%------------------------------------------------------------------------------