↑ Up

SOS---2.0.UNS-Ref.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : COL075-2 : TPTP v8.1.0. Released v1.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Fri Jul 15 00:42:11 EDT 2022

% Result   : Unsatisfiable 0.19s 0.41s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11  % Problem  : COL075-2 : TPTP v8.1.0. Released v1.2.0.
% 0.07/0.12  % Command  : sos-script %s
% 0.12/0.33  % Computer : n025.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Tue May 31 12:27:58 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.35  ----- Otter 3.2, August 2001 -----
% 0.12/0.35  The process was started by sandbox2 on n025.cluster.edu,
% 0.12/0.35  Tue May 31 12:27:58 2022
% 0.12/0.35  The command was "./sos".  The process ID is 17765.
% 0.12/0.35  
% 0.12/0.35  set(prolog_style_variables).
% 0.12/0.35  set(auto).
% 0.12/0.35     dependent: set(auto1).
% 0.12/0.35     dependent: set(process_input).
% 0.12/0.35     dependent: clear(print_kept).
% 0.12/0.35     dependent: clear(print_new_demod).
% 0.12/0.35     dependent: clear(print_back_demod).
% 0.12/0.35     dependent: clear(print_back_sub).
% 0.12/0.35     dependent: set(control_memory).
% 0.12/0.35     dependent: assign(max_mem, 12000).
% 0.12/0.35     dependent: assign(pick_given_ratio, 4).
% 0.12/0.35     dependent: assign(stats_level, 1).
% 0.12/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35     dependent: assign(sos_limit, 5000).
% 0.12/0.35     dependent: assign(max_weight, 60).
% 0.12/0.35  clear(print_given).
% 0.12/0.35  
% 0.12/0.35  list(usable).
% 0.12/0.35  
% 0.12/0.35  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 0.12/0.35  
% 0.12/0.35  All clauses are units, and equality is present; the
% 0.12/0.35  strategy will be Knuth-Bendix with positive clauses in sos.
% 0.12/0.35  
% 0.12/0.35     dependent: set(knuth_bendix).
% 0.12/0.35     dependent: set(para_from).
% 0.12/0.35     dependent: set(para_into).
% 0.12/0.35     dependent: clear(para_from_right).
% 0.12/0.35     dependent: clear(para_into_right).
% 0.12/0.35     dependent: set(para_from_vars).
% 0.12/0.35     dependent: set(eq_units_both_ways).
% 0.12/0.35     dependent: set(dynamic_demod_all).
% 0.12/0.35     dependent: set(dynamic_demod).
% 0.12/0.35     dependent: set(order_eq).
% 0.12/0.35     dependent: set(back_demod).
% 0.12/0.35     dependent: set(lrpo).
% 0.12/0.35  
% 0.12/0.35  ------------> process usable:
% 0.12/0.35  
% 0.12/0.35  ------------> process sos:
% 0.12/0.35    Following clause subsumed by 5 during input processing: 0 [copy,5,flip.1] {-} A=A.
% 0.12/0.35    Following clause subsumed by 4 during input processing: 0 [copy,6,flip.1] {-} apply(apply(apply(abstraction,A),B),C)=apply(apply(A,apply(k,C)),apply(B,C)).
% 0.12/0.35  
% 0.12/0.35  ======= end of input processing =======
% 0.19/0.39  
% 0.19/0.39  Model 1 (0.00 seconds, 0 Inserts)
% 0.19/0.39  
% 0.19/0.39  Stopped by limit on number of solutions
% 0.19/0.39  
% 0.19/0.39  
% 0.19/0.39  -------------- Softie stats --------------
% 0.19/0.39  
% 0.19/0.39  UPDATE_STOP: 300
% 0.19/0.39  SFINDER_TIME_LIMIT: 2
% 0.19/0.39  SHORT_CLAUSE_CUTOFF: 4
% 0.19/0.39  number of clauses in intial UL: 1
% 0.19/0.39  number of clauses initially in problem: 6
% 0.19/0.39  percentage of clauses intially in UL: 16
% 0.19/0.39  percentage of distinct symbols occuring in initial UL: 66
% 0.19/0.39  percent of all initial clauses that are short: 100
% 0.19/0.39  absolute distinct symbol count: 6
% 0.19/0.39     distinct predicate count: 1
% 0.19/0.39     distinct function count: 3
% 0.19/0.39     distinct constant count: 2
% 0.19/0.39  
% 0.19/0.39  ---------- no more Softie stats ----------
% 0.19/0.39  
% 0.19/0.39  
% 0.19/0.39  
% 0.19/0.39  =========== start of search ===========
% 0.19/0.41  
% 0.19/0.41  -------- PROOF -------- 
% 0.19/0.41  % SZS status Unsatisfiable
% 0.19/0.41  % SZS output start Refutation
% 0.19/0.41  
% 0.19/0.41  ----> UNIT CONFLICT at   0.03 sec ----> 178 [binary,177.1,5.1] {-} $F.
% 0.19/0.41  
% 0.19/0.41  Length of proof is 5.  Level of proof is 4.
% 0.19/0.41  
% 0.19/0.41  ---------------- PROOF ----------------
% 0.19/0.41  % SZS status Unsatisfiable
% 0.19/0.41  % SZS output start Refutation
% 0.19/0.41  
% 0.19/0.41  1 [] {+} apply(apply(A,b(A)),c(A))!=apply(b(A),b(A)).
% 0.19/0.41  3,2 [] {-} apply(apply(k,A),B)=A.
% 0.19/0.41  4 [] {-} apply(apply(apply(abstraction,A),B),C)=apply(apply(A,apply(k,C)),apply(B,C)).
% 0.19/0.41  5 [] {+} A=A.
% 0.19/0.41  6 [copy,4,flip.1] {-} apply(apply(A,apply(k,B)),apply(C,B))=apply(apply(apply(abstraction,A),C),B).
% 0.19/0.41  12 [para_from,4.1.1,1.1.1.1] {+} apply(apply(apply(A,apply(k,b(apply(apply(abstraction,A),B)))),apply(B,b(apply(apply(abstraction,A),B)))),c(apply(apply(abstraction,A),B)))!=apply(b(apply(apply(abstraction,A),B)),b(apply(apply(abstraction,A),B))).
% 0.19/0.41  19 [para_into,6.1.1.2,2.1.1] {-} apply(apply(A,apply(k,B)),C)=apply(apply(apply(abstraction,A),apply(k,C)),B).
% 0.19/0.41  27 [copy,19,flip.1] {-} apply(apply(apply(abstraction,A),apply(k,B)),C)=apply(apply(A,apply(k,C)),B).
% 0.19/0.41  177 [para_into,12.1.1,27.1.1,demod,3] {-} apply(b(apply(apply(abstraction,abstraction),k)),b(apply(apply(abstraction,abstraction),k)))!=apply(b(apply(apply(abstraction,abstraction),k)),b(apply(apply(abstraction,abstraction),k))).
% 0.19/0.41  178 [binary,177.1,5.1] {-} $F.
% 0.19/0.41  
% 0.19/0.41  % SZS output end Refutation
% 0.19/0.41  ------------ end of proof -------------
% 0.19/0.41  
% 0.19/0.41  
% 0.19/0.41  Search stopped by max_proofs option.
% 0.19/0.41  
% 0.19/0.41  
% 0.19/0.41  Search stopped by max_proofs option.
% 0.19/0.41  
% 0.19/0.41  ============ end of search ============
% 0.19/0.41  
% 0.19/0.41  ----------- soft-scott stats ----------
% 0.19/0.41  
% 0.19/0.41  true clauses given           3      (14.3%)
% 0.19/0.41  false clauses given         18
% 0.19/0.41  
% 0.19/0.41        FALSE     TRUE
% 0.19/0.41    15  1         0
% 0.19/0.41    17  2         0
% 0.19/0.41    19  11        1
% 0.19/0.41    20  0         1
% 0.19/0.41    21  2         0
% 0.19/0.41    23  6         0
% 0.19/0.41    25  18        0
% 0.19/0.41    26  0         1
% 0.19/0.41    27  20        0
% 0.19/0.41    28  5         0
% 0.19/0.41    29  6         2
% 0.19/0.41    32  0         2
% 0.19/0.41    34  1         0
% 0.19/0.41    35  0         1
% 0.19/0.41    36  3         1
% 0.19/0.41    38  4         2
% 0.19/0.41    39  0         1
% 0.19/0.41    40  5         0
% 0.19/0.41    41  0         2
% 0.19/0.41    42  1         0
% 0.19/0.41    43  0         2
% 0.19/0.41    45  0         4
% 0.19/0.41    46  1         0
% 0.19/0.41    48  3         1
% 0.19/0.41    49  1         0
% 0.19/0.41    50  0         1
% 0.19/0.41    52  2         0
% 0.19/0.41    54  1         0
% 0.19/0.41    57  0         1
% 0.19/0.41    60  1         0
% 0.19/0.41  tot:  94        23      (19.7% true)
% 0.19/0.41  
% 0.19/0.41  
% 0.19/0.41  Model 1 (0.00 seconds, 0 Inserts)
% 0.19/0.41  
% 0.19/0.41  That finishes the proof of the theorem.
% 0.19/0.41  
% 0.19/0.41  Process 17765 finished Tue May 31 12:27:58 2022
%------------------------------------------------------------------------------