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Twee---2.7.UNS-Prf.s

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%------------------------------------------------------------------------------
% File     : Twee---2.7
% Problem  : COL080-2 : TPTP v9.3.1. Released v1.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue Sep 29 09:37:24 AM UTC 2026

% Result   : Unsatisfiable 0.07s 0.14s
% Output   : Proof 0.07s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.01  % Problem  : COL080-2 : TPTP v9.3.1. Released v1.2.0.
% 0.00/0.02  % Command  : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.00/0.09  % Computer : n012.cluster.edu
% 0.00/0.09  % Model    : x86_64 x86_64
% 0.00/0.09  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.00/0.09  % Memory   : 8046.5625MB
% 0.00/0.09  % OS       : Linux 6.8.0-71-generic
% 0.00/0.09  % CPULimit : 300
% 0.00/0.09  % WCLimit  : 300
% 0.00/0.09  % DateTime : Mon Sep 28 21:34:18 UTC 2026
% 0.00/0.09  % CPUTime  : 
% 0.00/0.09  Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.07/0.14  Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-every 2
% 0.07/0.14  
% 0.07/0.14  % SZS status Unsatisfiable
% 0.07/0.14  
% 0.07/0.14  % SZS output start Proof
% 0.07/0.14  Axiom 1 (k_definition): apply(k(X), Y) = X.
% 0.07/0.14  Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 0.07/0.14  Axiom 3 (abstraction): apply(apply(apply(abstraction, X), Y), Z) = apply(apply(X, k(Z)), apply(Y, Z)).
% 0.07/0.14  Axiom 4 (extensionality2): ifeq(apply(X, n(X, Y)), apply(Y, n(X, Y)), X, Y) = Y.
% 0.07/0.14  
% 0.07/0.14  Goal 1 (prove_TRC2b): k(b) = apply(abstraction, apply(abstraction, k(b))).
% 0.07/0.14  Proof:
% 0.07/0.14    k(b)
% 0.07/0.14  = { by axiom 2 (ifeq_axiom) R->L }
% 0.07/0.14    ifeq(b, b, k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 4 (extensionality2) R->L }
% 0.07/0.14    ifeq(b, ifeq(apply(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(b, n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b), k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 3 (abstraction) }
% 0.07/0.14    ifeq(b, ifeq(apply(apply(apply(abstraction, k(b)), k(n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b))), apply(n(k(b), apply(abstraction, apply(abstraction, k(b)))), n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b))), apply(b, n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b), k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 3 (abstraction) }
% 0.07/0.14    ifeq(b, ifeq(apply(apply(k(b), k(apply(n(k(b), apply(abstraction, apply(abstraction, k(b)))), n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)))), apply(k(n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(n(k(b), apply(abstraction, apply(abstraction, k(b)))), n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)))), apply(b, n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b), k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 1 (k_definition) }
% 0.07/0.14    ifeq(b, ifeq(apply(b, apply(k(n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(n(k(b), apply(abstraction, apply(abstraction, k(b)))), n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)))), apply(b, n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b), k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 1 (k_definition) }
% 0.07/0.14    ifeq(b, ifeq(apply(b, n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(b, n(apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b)), apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), b), k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 2 (ifeq_axiom) }
% 0.07/0.14    ifeq(b, apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 1 (k_definition) R->L }
% 0.07/0.14    ifeq(apply(k(b), n(k(b), apply(abstraction, apply(abstraction, k(b))))), apply(apply(abstraction, apply(abstraction, k(b))), n(k(b), apply(abstraction, apply(abstraction, k(b))))), k(b), apply(abstraction, apply(abstraction, k(b))))
% 0.07/0.14  = { by axiom 4 (extensionality2) }
% 0.07/0.14    apply(abstraction, apply(abstraction, k(b)))
% 0.07/0.14  % SZS output end Proof
% 0.07/0.14  
% 0.07/0.14  RESULT: Unsatisfiable (the axioms are contradictory).
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