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SPASS---3.9.THM-Ref.s

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : COM022+4 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Fri Jul 15 01:44:22 EDT 2022

% Result   : Theorem 0.81s 1.02s
% Output   : Refutation 0.81s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : COM022+4 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n007.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Thu Jun 16 19:48:12 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.81/1.02  
% 0.81/1.02  SPASS V 3.9 
% 0.81/1.02  SPASS beiseite: Proof found.
% 0.81/1.02  % SZS status Theorem
% 0.81/1.02  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.81/1.02  SPASS derived 2212 clauses, backtracked 1475 clauses, performed 59 splits and kept 3094 clauses.
% 0.81/1.02  SPASS allocated 99423 KBytes.
% 0.81/1.02  SPASS spent	0:00:00.67 on the problem.
% 0.81/1.02  		0:00:00.04 for the input.
% 0.81/1.02  		0:00:00.08 for the FLOTTER CNF translation.
% 0.81/1.02  		0:00:00.01 for inferences.
% 0.81/1.02  		0:00:00.01 for the backtracking.
% 0.81/1.02  		0:00:00.43 for the reduction.
% 0.81/1.02  
% 0.81/1.02  
% 0.81/1.02  Here is a proof with depth 3, length 40 :
% 0.81/1.02  % SZS output start Refutation
% 0.81/1.02  6[0:Inp] ||  -> aElement0(skc20)*.
% 0.81/1.02  18[0:Inp] ||  -> aElement0(xb)*.
% 0.81/1.02  19[0:Inp] ||  -> aElement0(xc)*.
% 0.81/1.02  28[0:Inp] ||  -> sdtmndtasgtdt0(xa,xR,xb)*.
% 0.81/1.02  39[0:Inp] || SkC0 -> aReductOfIn0(skc13,xa,xR)*.
% 0.81/1.02  47[0:Inp] || SkC0 -> sdtmndtasgtdt0(xb,xR,skc20)*.
% 0.81/1.02  48[0:Inp] || SkC0 -> sdtmndtasgtdt0(xc,xR,skc20)*.
% 0.81/1.02  50[0:Inp] || sdtmndtplgtdt0(xa,xR,xb)* -> SkC1.
% 0.81/1.02  51[0:Inp] || equal(xb,u) -> SkP2(u)*.
% 0.81/1.02  53[0:Inp] ||  -> equal(xb,xa) sdtmndtplgtdt0(xa,xR,xb)*.
% 0.81/1.02  54[0:Inp] ||  -> equal(xc,xa) sdtmndtplgtdt0(xa,xR,xc)*.
% 0.81/1.02  56[0:Inp] || sdtmndtplgtdt0(xb,xR,u)* -> SkP2(u).
% 0.81/1.02  57[0:Inp] || sdtmndtasgtdt0(xb,xR,u)* -> SkP2(u).
% 0.81/1.02  60[0:Inp] || SkC1 sdtmndtplgtdt0(xa,xR,xc)* -> SkC0.
% 0.81/1.02  71[0:Inp] SkP2(u) aElement0(u) || equal(xc,u)* -> .
% 0.81/1.02  78[0:Inp] SkP2(u) aElement0(u) || sdtmndtasgtdt0(xc,xR,u)* -> .
% 0.81/1.02  316[1:Spt:39.0] || SkC0* -> .
% 0.81/1.02  317[1:MRR:60.2,316.0] || SkC1 sdtmndtplgtdt0(xa,xR,xc)* -> .
% 0.81/1.02  321[2:Spt:54.0] ||  -> equal(xc,xa)**.
% 0.81/1.02  341[2:Rew:321.0,78.2] SkP2(u) aElement0(u) || sdtmndtasgtdt0(xa,xR,u)* -> .
% 0.81/1.02  481[2:Res:28.0,341.2] SkP2(xb) aElement0(xb) ||  -> .
% 0.81/1.02  483[2:SSi:481.1,18.0] SkP2(xb) ||  -> .
% 0.81/1.02  485[2:SoR:483.0,51.1] || equal(xb,xb)* -> .
% 0.81/1.02  486[2:Obv:485.0] ||  -> .
% 0.81/1.02  487[2:Spt:486.0,54.0,321.0] || equal(xc,xa)** -> .
% 0.81/1.02  488[2:Spt:486.0,54.1] ||  -> sdtmndtplgtdt0(xa,xR,xc)*.
% 0.81/1.02  489[2:MRR:317.1,488.0] || SkC1* -> .
% 0.81/1.02  490[2:MRR:50.1,489.0] || sdtmndtplgtdt0(xa,xR,xb)* -> .
% 0.81/1.02  492[2:MRR:53.1,490.0] ||  -> equal(xb,xa)**.
% 0.81/1.02  496[2:Rew:492.0,56.0] || sdtmndtplgtdt0(xa,xR,u)* -> SkP2(u).
% 0.81/1.02  517[2:Res:488.0,496.0] ||  -> SkP2(xc)*.
% 0.81/1.02  531[2:EmS:71.0,71.1,517.0,19.0] || equal(xc,xc)* -> .
% 0.81/1.02  565[2:Obv:531.0] ||  -> .
% 0.81/1.02  568[1:Spt:565.0,39.0,316.0] ||  -> SkC0*.
% 0.81/1.02  569[1:Spt:565.0,39.1] ||  -> aReductOfIn0(skc13,xa,xR)*.
% 0.81/1.02  570[1:MRR:48.0,568.0] ||  -> sdtmndtasgtdt0(xc,xR,skc20)*.
% 0.81/1.02  571[1:MRR:47.0,568.0] ||  -> sdtmndtasgtdt0(xb,xR,skc20)*.
% 0.81/1.02  2680[1:Res:571.0,57.0] ||  -> SkP2(skc20)*.
% 0.81/1.02  3037[1:Res:570.0,78.2] SkP2(skc20) aElement0(skc20) ||  -> .
% 0.81/1.02  3038[1:SSi:3037.1,3037.0,2680.0,6.0,2680.0,6.0] ||  -> .
% 0.81/1.02  % SZS output end Refutation
% 0.81/1.02  Formulae used in the proof : m__ m__731
% 0.81/1.02  
%------------------------------------------------------------------------------