%------------------------------------------------------------------------------ % File : SPASS+T---2.2.22 % Problem : DAT030_1 : TPTP v8.1.0. Released v5.0.0. % Transfm : none % Format : tptp:raw % Command : spasst-tptp-script %s %d % Computer : n007.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 600s % DateTime : Sat Jul 16 01:31:51 EDT 2022 % Result : Theorem 0.76s 1.05s % Output : Refutation 0.76s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : DAT030_1 : TPTP v8.1.0. Released v5.0.0. % 0.03/0.13 % Command : spasst-tptp-script %s %d % 0.12/0.34 % Computer : n007.cluster.edu % 0.12/0.34 % Model : x86_64 x86_64 % 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.34 % Memory : 8042.1875MB % 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.34 % CPULimit : 300 % 0.12/0.34 % WCLimit : 600 % 0.12/0.34 % DateTime : Fri Jul 1 18:01:09 EDT 2022 % 0.12/0.34 % CPUTime : % 0.19/0.47 % Using integer theory % 0.76/1.05 % 0.76/1.05 % 0.76/1.05 % SZS status Theorem for /tmp/SPASST_30110_n007.cluster.edu % 0.76/1.05 % 0.76/1.05 SPASS V 2.2.22 in combination with yices. % 0.76/1.05 SPASS beiseite: Proof found by SPASS and SMT. % 0.76/1.05 Problem: /tmp/SPASST_30110_n007.cluster.edu % 0.76/1.05 SPASS derived 191 clauses, backtracked 4 clauses and kept 179 clauses. % 0.76/1.05 SPASS backtracked 3 times (1 times due to theory inconsistency). % 0.76/1.05 SPASS allocated 6436 KBytes. % 0.76/1.05 SPASS spent 0:00:00.03 on the problem. % 0.76/1.05 0:00:00.00 for the input. % 0.76/1.05 0:00:00.01 for the FLOTTER CNF translation. % 0.76/1.05 0:00:00.00 for inferences. % 0.76/1.05 0:00:00.00 for the backtracking. % 0.76/1.05 0:00:00.01 for the reduction. % 0.76/1.05 0:00:00.00 for interacting with the SMT procedure. % 0.76/1.05 % 0.76/1.05 % 0.76/1.05 % SZS output start CNFRefutation for /tmp/SPASST_30110_n007.cluster.edu % 0.76/1.05 % 0.76/1.05 % Here is a proof with depth 0, length 7 : % 0.76/1.05 5[0:Inp] || -> in(skc8,skc5)*. % 0.76/1.05 7[0:Inp] || greater(skc8,1)* -> . % 0.76/1.05 10[0:Inp] || in(U,skc4)* -> greater(U,0). % 0.76/1.05 12[0:Inp] || in(U,skc5)* -> in(skf2(V),skc4)*. % 0.76/1.05 13[0:Inp] || in(U,skc5)* -> in(skf3(V),skc4)*. % 0.76/1.05 15[0:Inp] || in(U,skc5) -> equal(plus(skf3(U),skf2(U)),U)**. % 0.76/1.05 327(e)[0:ThR:15,13,12,10,7,5] || -> . % 0.76/1.05 % 0.76/1.05 % SZS output end CNFRefutation for /tmp/SPASST_30110_n007.cluster.edu % 0.76/1.05 % 0.76/1.05 Formulae used in the proof : fof_co1 fof_ax1 fof_add_type fof_ax2 fof_ax3 % 0.76/1.05 % 0.76/1.05 SPASS+T ended %------------------------------------------------------------------------------