%------------------------------------------------------------------------------ % File : SPASS+T---2.2.22 % Problem : DAT051_1 : TPTP v8.1.0. Released v5.0.0. % Transfm : none % Format : tptp:raw % Command : spasst-tptp-script %s %d % Computer : n006.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 600s % DateTime : Sat Jul 16 01:31:58 EDT 2022 % Result : Theorem 0.82s 1.09s % Output : Refutation 0.82s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : DAT051_1 : TPTP v8.1.0. Released v5.0.0. % 0.03/0.12 % Command : spasst-tptp-script %s %d % 0.12/0.33 % Computer : n006.cluster.edu % 0.12/0.33 % Model : x86_64 x86_64 % 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.33 % Memory : 8042.1875MB % 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.33 % CPULimit : 300 % 0.12/0.33 % WCLimit : 600 % 0.12/0.33 % DateTime : Fri Jul 1 19:13:37 EDT 2022 % 0.12/0.33 % CPUTime : % 0.19/0.46 % Using integer theory % 0.82/1.09 % 0.82/1.09 % 0.82/1.09 % SZS status Theorem for /tmp/SPASST_8399_n006.cluster.edu % 0.82/1.09 % 0.82/1.09 SPASS V 2.2.22 in combination with yices. % 0.82/1.09 SPASS beiseite: Proof found by SPASS and SMT. % 0.82/1.09 Problem: /tmp/SPASST_8399_n006.cluster.edu % 0.82/1.09 SPASS derived 226 clauses, backtracked 11 clauses and kept 142 clauses. % 0.82/1.09 SPASS backtracked 2 times (1 times due to theory inconsistency). % 0.82/1.09 SPASS allocated 6460 KBytes. % 0.82/1.09 SPASS spent 0:00:00.03 on the problem. % 0.82/1.09 0:00:00.00 for the input. % 0.82/1.09 0:00:00.00 for the FLOTTER CNF translation. % 0.82/1.09 0:00:00.00 for inferences. % 0.82/1.09 0:00:00.00 for the backtracking. % 0.82/1.09 0:00:00.01 for the reduction. % 0.82/1.09 0:00:00.00 for interacting with the SMT procedure. % 0.82/1.09 % 0.82/1.09 % 0.82/1.09 % SZS output start CNFRefutation for /tmp/SPASST_8399_n006.cluster.edu % 0.82/1.09 % 0.82/1.09 % Here is a proof with depth 0, length 12 : % 0.82/1.09 4[0:Inp] || -> record(skc2)*. % 0.82/1.09 5[0:Inp] || -> isrecord(skc2)*. % 0.82/1.09 6[0:Inp] || -> isrecord(next(skc2))*. % 0.82/1.09 8[0:Inp] || record(U) -> record(split2(U))*. % 0.82/1.09 10[0:Inp] || record(U) -> record(next(U))*. % 0.82/1.09 15[0:Inp] || equal(times(2,length(split2(skc2))),length(skc2))** -> . % 0.82/1.09 18[0:Inp] || equal(times(2,length(split2(skc2))),minus(length(skc2),1))** -> . % 0.82/1.09 20(e)[0:Inp] || record(U) isrecord(U) isrecord(next(U))* -> isrecord(split2(U)). % 0.82/1.09 22(e)[0:Inp] || record(U) isrecord(U) -> equal(plus(length(next(U)),1),length(U))**. % 0.82/1.09 24(e)[0:Inp] || record(U) isrecord(U) isrecord(next(U)) -> equal(split2(next(next(U))),next(split2(U)))**. % 0.82/1.09 26[0:Inp] || -> equal(times(2,length(split2(next(next(skc2))))),length(next(next(skc2)))) equal(times(2,length(split2(next(next(skc2))))),minus(length(next(next(skc2))),1))**. % 0.82/1.09 445(e)[0:ThR:26,24,22,20,18,15,10,8,6,5,4] || -> . % 0.82/1.09 % 0.82/1.09 % SZS output end CNFRefutation for /tmp/SPASST_8399_n006.cluster.edu % 0.82/1.09 % 0.82/1.09 Formulae used in the proof : fof_record_type fof_co1 fof_split1_type fof_ax1 fof_ax2 fof_ax6 fof_ax7 fof_ax12 fof_ax8 % 0.82/1.09 % 0.82/1.09 SPASS+T ended %------------------------------------------------------------------------------