%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : DAT159^1 : TPTP v9.2.0. Released v7.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n028.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:47:14 PM UTC 2025 % Result : Theorem 6.55s 6.73s % Output : Proof 6.55s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.11/0.12 % Problem : DAT159^1 : TPTP v9.2.0. Released v7.0.0. % 0.11/0.13 % Command : duper %s % 0.14/0.34 % Computer : n028.cluster.edu % 0.14/0.34 % Model : x86_64 x86_64 % 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.34 % Memory : 8042.1875MB % 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.34 % CPULimit : 300 % 0.14/0.34 % WCLimit : 300 % 0.14/0.34 % DateTime : Thu Oct 2 21:49:38 EDT 2025 % 0.14/0.34 % CPUTime : % 6.55/6.73 SZS status Theorem for theBenchmark.p % 6.55/6.73 SZS output start Proof for theBenchmark.p % 6.55/6.73 Clause #0 (by assumption #[]): Eq (Not (hammin1195055315smooth (zero_zero nat))) True % 6.55/6.73 Clause #1 (by assumption #[]): Eq (∀ (N : nat), Eq (Ne N (zero_zero nat)) (ord_less nat (zero_zero nat) N)) True % 6.55/6.73 Clause #298 (by assumption #[]): Eq (hammin1195055315smooth n) True % 6.55/6.73 Clause #299 (by assumption #[]): Eq (Not (ord_less nat (zero_zero nat) n)) True % 6.55/6.73 Clause #300 (by clausification #[0]): Eq (hammin1195055315smooth (zero_zero nat)) False % 6.55/6.73 Clause #301 (by clausification #[1]): ∀ (a : nat), Eq (Eq (Ne a (zero_zero nat)) (ord_less nat (zero_zero nat) a)) True % 6.55/6.73 Clause #302 (by clausification #[301]): ∀ (a : nat), Eq (Ne a (zero_zero nat)) (ord_less nat (zero_zero nat) a) % 6.55/6.73 Clause #304 (by clausify Prop equality #[302]): ∀ (a : nat), Or (Eq (Ne a (zero_zero nat)) False) (Eq (ord_less nat (zero_zero nat) a) True) % 6.55/6.73 Clause #316 (by clausification #[304]): ∀ (a : nat), Or (Eq (ord_less nat (zero_zero nat) a) True) (Eq a (zero_zero nat)) % 6.55/6.73 Clause #1828 (by clausification #[299]): Eq (ord_less nat (zero_zero nat) n) False % 6.55/6.73 Clause #1829 (by superposition #[1828, 316]): Or (Eq False True) (Eq n (zero_zero nat)) % 6.55/6.73 Clause #1840 (by clausification #[1829]): Eq n (zero_zero nat) % 6.55/6.73 Clause #1841 (by backward demodulation #[1840, 300]): Eq (hammin1195055315smooth n) False % 6.55/6.73 Clause #1867 (by superposition #[1841, 298]): Eq False True % 6.55/6.73 Clause #1964 (by clausification #[1867]): False % 6.55/6.73 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------