%------------------------------------------------------------------------------
% File : Prover9---2026-6A
% Problem : GEO017-3 : TPTP v9.3.1. Released v1.0.0.
% Transfm : none
% Format : tptp:raw
% Command : prover9 -casc 300 -f /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Sun Sep 27 07:16:46 AM UTC 2026
% Result : Unsatisfiable 0.09s 0.63s
% Output : CNFRefutation 0.09s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 5
% Syntax : Number of formulae : 14 ( 9 unt; 0 def)
% Number of atoms : 21 ( 0 equ)
% Maximal formula atoms : 3 ( 1 avg)
% Number of connectives : 17 ( 10 ~; 7 |; 0 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 10 ( 3 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-4 aty)
% Number of functors : 4 ( 4 usr; 4 con; 0-0 aty)
% Number of variables : 28 ( 0 sgn 12 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(reflexivity_for_equidistance,axiom,
! [VAR_0,VAR_1] : equidistant(VAR_0,VAR_1,VAR_1,VAR_0),
file('theBenchmark.p',reflexivity_for_equidistance) ).
cnf(c_1,plain,
equidistant(A,B,B,A),
inference(clausify,[status(thm)],[reflexivity_for_equidistance]) ).
fof(transitivity_for_equidistance,axiom,
! [VAR_0,VAR_1,VAR_2,VAR_3,VAR_4,VAR_5] :
( equidistant(VAR_2,VAR_3,VAR_4,VAR_5)
| ~ equidistant(VAR_0,VAR_1,VAR_4,VAR_5)
| ~ equidistant(VAR_0,VAR_1,VAR_2,VAR_3) ),
file('theBenchmark.p',transitivity_for_equidistance) ).
cnf(c_2,plain,
( equidistant(C,D,E,F)
| ~ equidistant(A,B,E,F)
| ~ equidistant(A,B,C,D) ),
inference(clausify,[status(thm)],[transitivity_for_equidistance]) ).
fof(d2,axiom,
! [VAR_0,VAR_1,VAR_2,VAR_3] :
( equidistant(VAR_2,VAR_3,VAR_0,VAR_1)
| ~ equidistant(VAR_0,VAR_1,VAR_2,VAR_3) ),
file('theBenchmark.p',d2) ).
cnf(c_20,plain,
( equidistant(C,D,A,B)
| ~ equidistant(A,B,C,D) ),
inference(clausify,[status(thm)],[d2]) ).
fof(u_to_v_equals_w_to_x,axiom,
equidistant(u,v,w,x),
file('theBenchmark.p',u_to_v_equals_w_to_x) ).
cnf(c_22,plain,
equidistant(u,v,w,x),
inference(clausify,[status(thm)],[u_to_v_equals_w_to_x]) ).
fof(prove_symmetry,axiom,
~ equidistant(u,v,x,w),
file('theBenchmark.p',prove_symmetry) ).
cnf(c_23,plain,
~ equidistant(u,v,x,w),
inference(clausify,[status(thm)],[prove_symmetry]) ).
cnf(c_100,plain,
equidistant(w,x,u,v),
inference(resolve,[status(thm)],[c_22,c_20]) ).
cnf(c_114,plain,
( equidistant(C,D,B,A)
| ~ equidistant(A,B,C,D) ),
inference(resolve,[status(thm)],[c_2,c_1]) ).
cnf(c_115,plain,
~ equidistant(w,x,u,v),
inference(resolve,[status(thm)],[c_114,c_23]) ).
cnf(c_113,plain,
$false,
inference(resolve,[status(thm)],[c_100,c_115]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.05 % Problem : GEO017-3 : TPTP v9.3.1. Released v1.0.0.
% 0.00/0.07 % Command : prover9 -casc 300 -f /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.09/0.61 % Computer : n003.cluster.edu
% 0.09/0.61 % Model : x86_64 x86_64
% 0.09/0.61 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.61 % Memory : 8046.5625MB
% 0.09/0.61 % OS : Linux 6.8.0-71-generic
% 0.09/0.61 % CPULimit : 300
% 0.09/0.61 % WCLimit : 300
% 0.09/0.61 % DateTime : Fri Sep 25 12:33:38 UTC 2026
% 0.09/0.61 % CPUTime :
% 0.09/0.61 % Prover9 (64) version 2026-6A, July 2026, CASC-J13.
% 0.09/0.61 % Process 175621 was started by sandbox on n003,
% 0.09/0.61 % Fri Sep 25 12:33:38 2026
% 0.09/0.61 % The command was "/export/starexec/sandbox/solver/bin/prover9 -casc 300 -f /export/starexec/sandbox/benchmark/theBenchmark.p".
% 0.09/0.62
% 0.09/0.62 % From the command line: assign(max_seconds, 300).
% 0.09/0.63
% 0.09/0.63 % SZS status Unsatisfiable for theBenchmark
% 0.09/0.63
% 0.09/0.63 % Proof 1 at 0.01 (+ 0.00) seconds.
% 0.09/0.63 % Length of proof is 7.
% 0.09/0.63 % Level of proof is 2.
% 0.09/0.63 % Maximum clause weight is 20.000.
% 0.09/0.63 % Given clauses 23.
% 0.09/0.63
% 0.09/0.63 % SZS output start CNFRefutation for theBenchmark
% See solution above
%------------------------------------------------------------------------------