↑ Up

SOS---2.0.THM-Ref.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : GEO085+1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 06:18:00 EDT 2022

% Result   : Theorem 0.95s 1.14s
% Output   : Refutation 0.95s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : GEO085+1 : TPTP v8.1.0. Released v2.4.0.
% 0.06/0.12  % Command  : sos-script %s
% 0.12/0.33  % Computer : n026.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jun 18 10:17:54 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.35  ----- Otter 3.2, August 2001 -----
% 0.12/0.35  The process was started by sandbox2 on n026.cluster.edu,
% 0.12/0.35  Sat Jun 18 10:17:54 2022
% 0.12/0.35  The command was "./sos".  The process ID is 11881.
% 0.12/0.35  
% 0.12/0.35  set(prolog_style_variables).
% 0.12/0.35  set(auto).
% 0.12/0.35     dependent: set(auto1).
% 0.12/0.35     dependent: set(process_input).
% 0.12/0.35     dependent: clear(print_kept).
% 0.12/0.35     dependent: clear(print_new_demod).
% 0.12/0.35     dependent: clear(print_back_demod).
% 0.12/0.35     dependent: clear(print_back_sub).
% 0.12/0.35     dependent: set(control_memory).
% 0.12/0.35     dependent: assign(max_mem, 12000).
% 0.12/0.35     dependent: assign(pick_given_ratio, 4).
% 0.12/0.35     dependent: assign(stats_level, 1).
% 0.12/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35     dependent: assign(sos_limit, 5000).
% 0.12/0.35     dependent: assign(max_weight, 60).
% 0.12/0.35  clear(print_given).
% 0.12/0.35  
% 0.12/0.35  formula_list(usable).
% 0.12/0.35  
% 0.12/0.35  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=12.
% 0.12/0.35  
% 0.12/0.35  This ia a non-Horn set with equality.  The strategy will be
% 0.12/0.35  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.35  unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.35  clauses in usable.
% 0.12/0.35  
% 0.12/0.35     dependent: set(knuth_bendix).
% 0.12/0.35     dependent: set(para_from).
% 0.12/0.35     dependent: set(para_into).
% 0.12/0.35     dependent: clear(para_from_right).
% 0.12/0.35     dependent: clear(para_into_right).
% 0.12/0.35     dependent: set(para_from_vars).
% 0.12/0.35     dependent: set(eq_units_both_ways).
% 0.12/0.35     dependent: set(dynamic_demod_all).
% 0.12/0.35     dependent: set(dynamic_demod).
% 0.12/0.35     dependent: set(order_eq).
% 0.12/0.35     dependent: set(back_demod).
% 0.12/0.35     dependent: set(lrpo).
% 0.12/0.35     dependent: set(hyper_res).
% 0.12/0.35     dependent: set(unit_deletion).
% 0.12/0.35     dependent: set(factor).
% 0.12/0.35  
% 0.12/0.35  ------------> process usable:
% 0.12/0.35  
% 0.12/0.35  ------------> process sos:
% 0.12/0.35    Following clause subsumed by 59 during input processing: 0 [copy,59,flip.1] {-} A=A.
% 0.12/0.35  59 back subsumes 52.
% 0.12/0.35  59 back subsumes 51.
% 0.12/0.35  
% 0.12/0.35  ======= end of input processing =======
% 0.19/0.43  
% 0.19/0.43  Model 1 (0.00 seconds, 0 Inserts)
% 0.19/0.43  
% 0.19/0.43  Stopped by limit on number of solutions
% 0.19/0.43  
% 0.19/0.43  
% 0.19/0.43  -------------- Softie stats --------------
% 0.19/0.43  
% 0.19/0.43  UPDATE_STOP: 300
% 0.19/0.43  SFINDER_TIME_LIMIT: 2
% 0.19/0.43  SHORT_CLAUSE_CUTOFF: 4
% 0.19/0.43  number of clauses in intial UL: 47
% 0.19/0.43  number of clauses initially in problem: 58
% 0.19/0.43  percentage of clauses intially in UL: 81
% 0.19/0.43  percentage of distinct symbols occuring in initial UL: 91
% 0.19/0.43  percent of all initial clauses that are short: 100
% 0.19/0.43  absolute distinct symbol count: 23
% 0.19/0.43     distinct predicate count: 8
% 0.19/0.43     distinct function count: 14
% 0.19/0.43     distinct constant count: 1
% 0.19/0.43  
% 0.19/0.43  ---------- no more Softie stats ----------
% 0.19/0.43  
% 0.19/0.43  
% 0.19/0.43  
% 0.19/0.43  =========== start of search ===========
% 0.95/1.14  
% 0.95/1.14  -------- PROOF -------- 
% 0.95/1.14  % SZS status Theorem
% 0.95/1.14  % SZS output start Refutation
% 0.95/1.14  
% 0.95/1.14  Model 2 [ 8 1 10927 ] (0.00 seconds, 24581 Inserts)
% 0.95/1.14  
% 0.95/1.14  Stopped by limit on insertions
% 0.95/1.14  
% 0.95/1.14  Model 3 [ 8 3 16325 ] (0.00 seconds, 250000 Inserts)
% 0.95/1.14  
% 0.95/1.14  Stopped by limit on insertions
% 0.95/1.14  
% 0.95/1.14  Model 4 [ 8 3 18985 ] (0.00 seconds, 250000 Inserts)
% 0.95/1.14  
% 0.95/1.14  Stopped by limit on insertions
% 0.95/1.14  
% 0.95/1.14  Model 5 [ 18 1 2342 ] (0.00 seconds, 250000 Inserts)
% 0.95/1.14  
% 0.95/1.14  -----> EMPTY CLAUSE at   0.76 sec ----> 937 [hyper,858,37,604] {-} $F.
% 0.95/1.14  
% 0.95/1.14  Length of proof is 6.  Level of proof is 4.
% 0.95/1.14  
% 0.95/1.14  ---------------- PROOF ----------------
% 0.95/1.14  % SZS status Theorem
% 0.95/1.14  % SZS output start Refutation
% 0.95/1.14  
% 0.95/1.14  26 [] {+} -closed(A)| -end_point(B,A).
% 0.95/1.14  27 [] {+} -open(A)|end_point($f7(A),A).
% 0.95/1.14  35 [] {+} -end_point(A,B)|end_point($f11(B,A),B).
% 0.95/1.14  36 [] {-} -end_point(A,B)|A!=$f11(B,A).
% 0.95/1.14  37 [copy,36,flip.2] {+} -end_point(A,B)|$f11(B,A)!=A.
% 0.95/1.14  42 [] {+} A=B| -end_point(A,$c1)| -end_point(B,$c1).
% 0.95/1.14  55 [] {+} closed(A)|end_point($f6(A),A).
% 0.95/1.14  58 [] {-} open($c1).
% 0.95/1.14  75 [hyper,58,27] {-} end_point($f7($c1),$c1).
% 0.95/1.14  100 [hyper,75,35] {-} end_point($f11($c1,$f7($c1)),$c1).
% 0.95/1.14  604 [hyper,55,26,75] {-} end_point($f6($c1),$c1).
% 0.95/1.14  662,661 [hyper,604,42,75] {+} $f7($c1)=$f6($c1).
% 0.95/1.14  858 [hyper,100,42,604,demod,662,flip.1] {-} $f11($c1,$f6($c1))=$f6($c1).
% 0.95/1.14  937 [hyper,858,37,604] {-} $F.
% 0.95/1.14  
% 0.95/1.14  % SZS output end Refutation
% 0.95/1.14  ------------ end of proof -------------
% 0.95/1.14  
% 0.95/1.14  
% 0.95/1.14  Search stopped by max_proofs option.
% 0.95/1.14  
% 0.95/1.14  
% 0.95/1.14  Search stopped by max_proofs option.
% 0.95/1.14  
% 0.95/1.14  ============ end of search ============
% 0.95/1.14  
% 0.95/1.14  ----------- soft-scott stats ----------
% 0.95/1.14  
% 0.95/1.14  true clauses given           2      (13.3%)
% 0.95/1.14  false clauses given         13
% 0.95/1.14  
% 0.95/1.14        FALSE     TRUE
% 0.95/1.14     4  1         0
% 0.95/1.14     5  0         1
% 0.95/1.14     6  2         6
% 0.95/1.14     8  1         2
% 0.95/1.14     9  1         2
% 0.95/1.14    10  1         21
% 0.95/1.14    11  3         2
% 0.95/1.14    12  10        22
% 0.95/1.14    13  2         0
% 0.95/1.14    14  14        12
% 0.95/1.14    15  12        7
% 0.95/1.14    16  16        8
% 0.95/1.14    17  6         12
% 0.95/1.14    18  23        24
% 0.95/1.14    19  22        21
% 0.95/1.14    20  35        22
% 0.95/1.14    21  15        0
% 0.95/1.14    22  26        10
% 0.95/1.14    23  30        14
% 0.95/1.14    24  5         3
% 0.95/1.14    25  33        12
% 0.95/1.14    26  13        4
% 0.95/1.14    27  19        10
% 0.95/1.14    28  9         0
% 0.95/1.14    29  17        14
% 0.95/1.14    30  8         6
% 0.95/1.14    31  31        18
% 0.95/1.14    32  9         1
% 0.95/1.14    33  6         9
% 0.95/1.14    34  16        3
% 0.95/1.14    35  10        17
% 0.95/1.14    36  4         10
% 0.95/1.14    37  25        19
% 0.95/1.14    38  2         3
% 0.95/1.14    39  12        7
% 0.95/1.14    40  9         10
% 0.95/1.14    41  0         9
% 0.95/1.14    42  3         11
% 0.95/1.14    43  12        3
% 0.95/1.14    45  6         2
% 0.95/1.14    46  6         18
% 0.95/1.14    50  1         1
% 0.95/1.14    51  0         6
% 0.95/1.14    52  6         3
% 0.95/1.14    56  2         0
% 0.95/1.14  tot:  484       385      (44.3% true)
% 0.95/1.14  
% 0.95/1.14  
% 0.95/1.14  Model 5 [ 18 1 2342 ] (0.00 seconds, 250000 Inserts)
% 0.95/1.14  
% 0.95/1.14  That finishes the proof of the theorem.
% 0.95/1.14  
% 0.95/1.14  Process 11881 finished Sat Jun 18 10:17:55 2022
%------------------------------------------------------------------------------