%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : GEO206+2 : TPTP v8.1.0. Released v3.3.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 06:23:24 EDT 2022
% Result : Theorem 0.19s 0.44s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 7
% Syntax : Number of clauses : 13 ( 8 unt; 4 nHn; 13 RR)
% Number of literals : 22 ( 0 equ; 7 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-2 aty)
% Number of functors : 7 ( 7 usr; 6 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
~ apart_point_and_line(skc5,skc3),
file('GEO206+2.p',unknown),
[] ).
cnf(2,axiom,
~ convergent_lines(skc3,skc4),
file('GEO206+2.p',unknown),
[] ).
cnf(6,axiom,
distinct_lines(skc3,parallel_through_point(skc4,skc5)),
file('GEO206+2.p',unknown),
[] ).
cnf(7,axiom,
~ convergent_lines(parallel_through_point(u,v),u),
file('GEO206+2.p',unknown),
[] ).
cnf(8,axiom,
~ apart_point_and_line(u,parallel_through_point(v,u)),
file('GEO206+2.p',unknown),
[] ).
cnf(12,axiom,
( ~ convergent_lines(u,v)
| convergent_lines(v,w)
| convergent_lines(u,w) ),
file('GEO206+2.p',unknown),
[] ).
cnf(19,axiom,
( ~ distinct_lines(u,v)
| convergent_lines(u,v)
| apart_point_and_line(w,v)
| apart_point_and_line(w,u) ),
file('GEO206+2.p',unknown),
[] ).
cnf(22,plain,
( ~ convergent_lines(skc3,u)
| convergent_lines(u,skc4) ),
inference(res,[status(thm),theory(equality)],[12,2]),
[iquote('0:Res:12.1,2.0')] ).
cnf(32,plain,
( apart_point_and_line(u,skc3)
| apart_point_and_line(u,parallel_through_point(skc4,skc5))
| convergent_lines(skc3,parallel_through_point(skc4,skc5)) ),
inference(res,[status(thm),theory(equality)],[6,19]),
[iquote('0:Res:6.0,19.0')] ).
cnf(50,plain,
( apart_point_and_line(skc5,parallel_through_point(skc4,skc5))
| convergent_lines(skc3,parallel_through_point(skc4,skc5)) ),
inference(res,[status(thm),theory(equality)],[32,1]),
[iquote('0:Res:32.0,1.0')] ).
cnf(53,plain,
convergent_lines(skc3,parallel_through_point(skc4,skc5)),
inference(mrr,[status(thm)],[50,8]),
[iquote('0:MRR:50.0,8.0')] ).
cnf(70,plain,
convergent_lines(parallel_through_point(skc4,skc5),skc4),
inference(res,[status(thm),theory(equality)],[53,22]),
[iquote('0:Res:53.0,22.0')] ).
cnf(71,plain,
$false,
inference(mrr,[status(thm)],[70,7]),
[iquote('0:MRR:70.0,7.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : GEO206+2 : TPTP v8.1.0. Released v3.3.0.
% 0.07/0.13 % Command : run_spass %d %s
% 0.12/0.34 % Computer : n020.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Fri Jun 17 15:48:19 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.19/0.44
% 0.19/0.44 SPASS V 3.9
% 0.19/0.44 SPASS beiseite: Proof found.
% 0.19/0.44 % SZS status Theorem
% 0.19/0.44 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.44 SPASS derived 35 clauses, backtracked 0 clauses, performed 0 splits and kept 39 clauses.
% 0.19/0.44 SPASS allocated 85170 KBytes.
% 0.19/0.44 SPASS spent 0:00:00.08 on the problem.
% 0.19/0.44 0:00:00.03 for the input.
% 0.19/0.44 0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.44 0:00:00.00 for inferences.
% 0.19/0.44 0:00:00.00 for the backtracking.
% 0.19/0.44 0:00:00.00 for the reduction.
% 0.19/0.44
% 0.19/0.44
% 0.19/0.44 Here is a proof with depth 3, length 13 :
% 0.19/0.44 % SZS output start Refutation
% See solution above
% 0.19/0.44 Formulae used in the proof : con cp1 cp2 apart6 cup1
% 0.19/0.44
%------------------------------------------------------------------------------