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Otter---3.3.UNS-Ref.s

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%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP033-4 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:55:55 EDT 2022

% Result   : Unsatisfiable 1.83s 2.05s
% Output   : Refutation 1.83s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   11 (   8 unt;   0 nHn;   8 RR)
%            Number of literals    :   17 (   0 equ;   7 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-3 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-1 aty)
%            Number of variables   :    8 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(4,axiom,
    ( ~ subgroup_member(A)
    | ~ subgroup_member(B)
    | ~ product(A,inverse(B),C)
    | subgroup_member(C) ),
    file('GRP033-4.p',unknown),
    [] ).

cnf(5,axiom,
    ( ~ subgroup_member(A)
    | subgroup_member(j(A)) ),
    file('GRP033-4.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ product(j(A),A,j(A))
    | ~ product(A,j(A),j(A))
    | ~ subgroup_member(A) ),
    file('GRP033-4.p',unknown),
    [] ).

cnf(8,axiom,
    product(identity,A,A),
    file('GRP033-4.p',unknown),
    [] ).

cnf(9,axiom,
    product(A,identity,A),
    file('GRP033-4.p',unknown),
    [] ).

cnf(11,axiom,
    product(A,inverse(A),identity),
    file('GRP033-4.p',unknown),
    [] ).

cnf(13,axiom,
    subgroup_member(a),
    file('GRP033-4.p',unknown),
    [] ).

cnf(14,plain,
    subgroup_member(j(a)),
    inference(hyper,[status(thm)],[13,5]),
    [iquote('hyper,13,5')] ).

cnf(16,plain,
    subgroup_member(j(j(a))),
    inference(hyper,[status(thm)],[14,5]),
    [iquote('hyper,14,5')] ).

cnf(36,plain,
    subgroup_member(identity),
    inference(hyper,[status(thm)],[11,4,16,16]),
    [iquote('hyper,11,4,16,16')] ).

cnf(41,plain,
    $false,
    inference(hyper,[status(thm)],[36,6,9,8]),
    [iquote('hyper,36,6,9,8')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : GRP033-4 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.13/0.33  % Computer : n013.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 300
% 0.13/0.33  % DateTime : Wed Jul 27 05:13:45 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 1.83/2.05  ----- Otter 3.3f, August 2004 -----
% 1.83/2.05  The process was started by sandbox on n013.cluster.edu,
% 1.83/2.05  Wed Jul 27 05:13:45 2022
% 1.83/2.05  The command was "./otter".  The process ID is 31338.
% 1.83/2.05  
% 1.83/2.05  set(prolog_style_variables).
% 1.83/2.05  set(auto).
% 1.83/2.05     dependent: set(auto1).
% 1.83/2.05     dependent: set(process_input).
% 1.83/2.05     dependent: clear(print_kept).
% 1.83/2.05     dependent: clear(print_new_demod).
% 1.83/2.05     dependent: clear(print_back_demod).
% 1.83/2.05     dependent: clear(print_back_sub).
% 1.83/2.05     dependent: set(control_memory).
% 1.83/2.05     dependent: assign(max_mem, 12000).
% 1.83/2.05     dependent: assign(pick_given_ratio, 4).
% 1.83/2.05     dependent: assign(stats_level, 1).
% 1.83/2.05     dependent: assign(max_seconds, 10800).
% 1.83/2.05  clear(print_given).
% 1.83/2.05  
% 1.83/2.05  list(usable).
% 1.83/2.05  0 [] A=A.
% 1.83/2.05  0 [] product(identity,X,X).
% 1.83/2.05  0 [] product(X,identity,X).
% 1.83/2.05  0 [] product(inverse(X),X,identity).
% 1.83/2.05  0 [] product(X,inverse(X),identity).
% 1.83/2.05  0 [] product(X,Y,multiply(X,Y)).
% 1.83/2.05  0 [] -product(X,Y,Z)| -product(X,Y,W)|Z=W.
% 1.83/2.05  0 [] -product(X,Y,U)| -product(Y,Z,V)| -product(U,Z,W)|product(X,V,W).
% 1.83/2.05  0 [] -product(X,Y,U)| -product(Y,Z,V)| -product(X,V,W)|product(U,Z,W).
% 1.83/2.05  0 [] -subgroup_member(A)| -subgroup_member(B)| -product(A,inverse(B),C)|subgroup_member(C).
% 1.83/2.05  0 [] subgroup_member(a).
% 1.83/2.05  0 [] -subgroup_member(A)|subgroup_member(j(A)).
% 1.83/2.05  0 [] -product(j(A),A,j(A))| -product(A,j(A),j(A))| -subgroup_member(A).
% 1.83/2.05  end_of_list.
% 1.83/2.05  
% 1.83/2.05  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=4.
% 1.83/2.05  
% 1.83/2.05  This is a Horn set with equality.  The strategy will be
% 1.83/2.05  Knuth-Bendix and hyper_res, with positive clauses in
% 1.83/2.05  sos and nonpositive clauses in usable.
% 1.83/2.05  
% 1.83/2.05     dependent: set(knuth_bendix).
% 1.83/2.05     dependent: set(anl_eq).
% 1.83/2.05     dependent: set(para_from).
% 1.83/2.05     dependent: set(para_into).
% 1.83/2.05     dependent: clear(para_from_right).
% 1.83/2.05     dependent: clear(para_into_right).
% 1.83/2.05     dependent: set(para_from_vars).
% 1.83/2.05     dependent: set(eq_units_both_ways).
% 1.83/2.05     dependent: set(dynamic_demod_all).
% 1.83/2.05     dependent: set(dynamic_demod).
% 1.83/2.05     dependent: set(order_eq).
% 1.83/2.05     dependent: set(back_demod).
% 1.83/2.05     dependent: set(lrpo).
% 1.83/2.05     dependent: set(hyper_res).
% 1.83/2.05     dependent: clear(order_hyper).
% 1.83/2.05  
% 1.83/2.05  ------------> process usable:
% 1.83/2.05  ** KEPT (pick-wt=11): 1 [] -product(A,B,C)| -product(A,B,D)|C=D.
% 1.83/2.05  ** KEPT (pick-wt=16): 2 [] -product(A,B,C)| -product(B,D,E)| -product(C,D,F)|product(A,E,F).
% 1.83/2.05  ** KEPT (pick-wt=16): 3 [] -product(A,B,C)| -product(B,D,E)| -product(A,E,F)|product(C,D,F).
% 1.83/2.05  ** KEPT (pick-wt=11): 4 [] -subgroup_member(A)| -subgroup_member(B)| -product(A,inverse(B),C)|subgroup_member(C).
% 1.83/2.05  ** KEPT (pick-wt=5): 5 [] -subgroup_member(A)|subgroup_member(j(A)).
% 1.83/2.05  ** KEPT (pick-wt=14): 6 [] -product(j(A),A,j(A))| -product(A,j(A),j(A))| -subgroup_member(A).
% 1.83/2.05  
% 1.83/2.05  ------------> process sos:
% 1.83/2.05  ** KEPT (pick-wt=3): 7 [] A=A.
% 1.83/2.05  ** KEPT (pick-wt=4): 8 [] product(identity,A,A).
% 1.83/2.05  ** KEPT (pick-wt=4): 9 [] product(A,identity,A).
% 1.83/2.05  ** KEPT (pick-wt=5): 10 [] product(inverse(A),A,identity).
% 1.83/2.05  ** KEPT (pick-wt=5): 11 [] product(A,inverse(A),identity).
% 1.83/2.05  ** KEPT (pick-wt=6): 12 [] product(A,B,multiply(A,B)).
% 1.83/2.05  ** KEPT (pick-wt=2): 13 [] subgroup_member(a).
% 1.83/2.05    Following clause subsumed by 7 during input processing: 0 [copy,7,flip.1] A=A.
% 1.83/2.05  
% 1.83/2.05  ======= end of input processing =======
% 1.83/2.05  
% 1.83/2.05  =========== start of search ===========
% 1.83/2.05  
% 1.83/2.05  -------- PROOF -------- 
% 1.83/2.05  
% 1.83/2.05  -----> EMPTY CLAUSE at   0.00 sec ----> 41 [hyper,36,6,9,8] $F.
% 1.83/2.05  
% 1.83/2.05  Length of proof is 3.  Level of proof is 3.
% 1.83/2.05  
% 1.83/2.05  ---------------- PROOF ----------------
% 1.83/2.05  % SZS status Unsatisfiable
% 1.83/2.05  % SZS output start Refutation
% See solution above
% 1.83/2.05  ------------ end of proof -------------
% 1.83/2.05  
% 1.83/2.05  
% 1.83/2.05  Search stopped by max_proofs option.
% 1.83/2.05  
% 1.83/2.05  
% 1.83/2.05  Search stopped by max_proofs option.
% 1.83/2.05  
% 1.83/2.05  ============ end of search ============
% 1.83/2.05  
% 1.83/2.05  -------------- statistics -------------
% 1.83/2.05  clauses given                 10
% 1.83/2.05  clauses generated            141
% 1.83/2.05  clauses kept                  39
% 1.83/2.05  clauses forward subsumed     117
% 1.83/2.05  clauses back subsumed          1
% 1.83/2.05  Kbytes malloced              976
% 1.83/2.05  
% 1.83/2.05  ----------- times (seconds) -----------
% 1.83/2.05  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.83/2.05  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.83/2.05  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.83/2.05  
% 1.83/2.05  That finishes the proof of the theorem.
% 1.83/2.05  
% 1.83/2.05  Process 31338 finished Wed Jul 27 05:13:46 2022
% 1.83/2.05  Otter interrupted
% 1.83/2.05  PROOF FOUND
%------------------------------------------------------------------------------