↑ Up

Otter---3.3.UNS-Ref.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP526-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:11 EDT 2022

% Result   : Unsatisfiable 1.80s 2.03s
% Output   : Refutation 1.80s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    9
%            Number of leaves      :    4
% Syntax   : Number of clauses     :   18 (  18 unt;   0 nHn;   3 RR)
%            Number of literals    :   18 (  17 equ;   2 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    5 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   2 con; 0-2 aty)
%            Number of variables   :   34 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(multiply(inverse(b2),b2),a2) != a2,
    file('GRP526-1.p',unknown),
    [] ).

cnf(3,axiom,
    divide(A,divide(divide(A,B),divide(C,B))) = C,
    file('GRP526-1.p',unknown),
    [] ).

cnf(5,axiom,
    multiply(A,B) = divide(A,divide(divide(C,C),B)),
    file('GRP526-1.p',unknown),
    [] ).

cnf(6,axiom,
    inverse(A) = divide(divide(B,B),A),
    file('GRP526-1.p',unknown),
    [] ).

cnf(7,plain,
    divide(A,divide(divide(B,B),C)) = multiply(A,C),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[5])]),
    [iquote('copy,5,flip.1')] ).

cnf(8,plain,
    divide(divide(A,A),B) = inverse(B),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[6])]),
    [iquote('copy,6,flip.1')] ).

cnf(10,plain,
    multiply(multiply(divide(divide(A,A),b2),b2),a2) != a2,
    inference(para_from,[status(thm),theory(equality)],[6,1]),
    [iquote('para_from,6.1.1,1.1.1.1.1')] ).

cnf(11,plain,
    divide(inverse(divide(A,A)),B) = inverse(B),
    inference(para_into,[status(thm),theory(equality)],[8,8]),
    [iquote('para_into,8.1.1.1,8.1.1')] ).

cnf(35,plain,
    divide(A,inverse(divide(B,A))) = B,
    inference(para_into,[status(thm),theory(equality)],[3,8]),
    [iquote('para_into,3.1.1.2,8.1.1')] ).

cnf(45,plain,
    divide(inverse(divide(A,B)),inverse(A)) = B,
    inference(para_into,[status(thm),theory(equality)],[35,35]),
    [iquote('para_into,35.1.1.2.1,35.1.1')] ).

cnf(57,plain,
    inverse(inverse(divide(A,divide(B,B)))) = A,
    inference(para_into,[status(thm),theory(equality)],[35,8]),
    [iquote('para_into,35.1.1,8.1.1')] ).

cnf(68,plain,
    inverse(divide(A,B)) = divide(inverse(A),inverse(B)),
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[45,35])]),
    [iquote('para_into,45.1.1.1.1,35.1.1,flip.1')] ).

cnf(83,plain,
    inverse(inverse(A)) = A,
    inference(para_into,[status(thm),theory(equality)],[45,11]),
    [iquote('para_into,45.1.1,11.1.1')] ).

cnf(90,plain,
    divide(A,divide(B,B)) = A,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[57]),68,68,68,83,68,83,83]),
    [iquote('back_demod,57,demod,68,68,68,83,68,83,83')] ).

cnf(108,plain,
    divide(A,divide(A,B)) = B,
    inference(para_from,[status(thm),theory(equality)],[90,3]),
    [iquote('para_from,90.1.1,3.1.1.2')] ).

cnf(137,plain,
    multiply(divide(A,A),B) = B,
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[7,108])]),
    [iquote('para_into,7.1.1,108.1.1,flip.1')] ).

cnf(155,plain,
    multiply(multiply(divide(divide(A,A),B),B),C) = C,
    inference(para_into,[status(thm),theory(equality)],[137,7]),
    [iquote('para_into,137.1.1.1,7.1.1')] ).

cnf(157,plain,
    $false,
    inference(binary,[status(thm)],[155,10]),
    [iquote('binary,155.1,10.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.11  % Problem  : GRP526-1 : TPTP v8.1.0. Released v2.6.0.
% 0.08/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n025.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:37:30 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.80/2.03  ----- Otter 3.3f, August 2004 -----
% 1.80/2.03  The process was started by sandbox on n025.cluster.edu,
% 1.80/2.03  Wed Jul 27 05:37:30 2022
% 1.80/2.03  The command was "./otter".  The process ID is 2812.
% 1.80/2.03  
% 1.80/2.03  set(prolog_style_variables).
% 1.80/2.03  set(auto).
% 1.80/2.03     dependent: set(auto1).
% 1.80/2.03     dependent: set(process_input).
% 1.80/2.03     dependent: clear(print_kept).
% 1.80/2.03     dependent: clear(print_new_demod).
% 1.80/2.03     dependent: clear(print_back_demod).
% 1.80/2.03     dependent: clear(print_back_sub).
% 1.80/2.03     dependent: set(control_memory).
% 1.80/2.03     dependent: assign(max_mem, 12000).
% 1.80/2.03     dependent: assign(pick_given_ratio, 4).
% 1.80/2.03     dependent: assign(stats_level, 1).
% 1.80/2.03     dependent: assign(max_seconds, 10800).
% 1.80/2.03  clear(print_given).
% 1.80/2.03  
% 1.80/2.03  list(usable).
% 1.80/2.03  0 [] A=A.
% 1.80/2.03  0 [] divide(A,divide(divide(A,B),divide(C,B)))=C.
% 1.80/2.03  0 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.80/2.03  0 [] inverse(A)=divide(divide(B,B),A).
% 1.80/2.03  0 [] multiply(multiply(inverse(b2),b2),a2)!=a2.
% 1.80/2.03  end_of_list.
% 1.80/2.03  
% 1.80/2.03  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.80/2.03  
% 1.80/2.03  All clauses are units, and equality is present; the
% 1.80/2.03  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.80/2.03  
% 1.80/2.03     dependent: set(knuth_bendix).
% 1.80/2.03     dependent: set(anl_eq).
% 1.80/2.03     dependent: set(para_from).
% 1.80/2.03     dependent: set(para_into).
% 1.80/2.03     dependent: clear(para_from_right).
% 1.80/2.03     dependent: clear(para_into_right).
% 1.80/2.03     dependent: set(para_from_vars).
% 1.80/2.03     dependent: set(eq_units_both_ways).
% 1.80/2.03     dependent: set(dynamic_demod_all).
% 1.80/2.03     dependent: set(dynamic_demod).
% 1.80/2.03     dependent: set(order_eq).
% 1.80/2.03     dependent: set(back_demod).
% 1.80/2.03     dependent: set(lrpo).
% 1.80/2.03  
% 1.80/2.03  ------------> process usable:
% 1.80/2.03  ** KEPT (pick-wt=8): 1 [] multiply(multiply(inverse(b2),b2),a2)!=a2.
% 1.80/2.03  
% 1.80/2.03  ------------> process sos:
% 1.80/2.03  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.80/2.03  ** KEPT (pick-wt=11): 3 [] divide(A,divide(divide(A,B),divide(C,B)))=C.
% 1.80/2.03  ---> New Demodulator: 4 [new_demod,3] divide(A,divide(divide(A,B),divide(C,B)))=C.
% 1.80/2.03  ** KEPT (pick-wt=11): 5 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.80/2.03  ** KEPT (pick-wt=8): 6 [] inverse(A)=divide(divide(B,B),A).
% 1.80/2.03    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.80/2.03  >>>> Starting back demodulation with 4.
% 1.80/2.03  ** KEPT (pick-wt=11): 7 [copy,5,flip.1] divide(A,divide(divide(B,B),C))=multiply(A,C).
% 1.80/2.03  ** KEPT (pick-wt=8): 8 [copy,6,flip.1] divide(divide(A,A),B)=inverse(B).
% 1.80/2.03    Following clause subsumed by 5 during input processing: 0 [copy,7,flip.1] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.80/2.03    Following clause subsumed by 6 during input processing: 0 [copy,8,flip.1] inverse(A)=divide(divide(B,B),A).
% 1.80/2.03  
% 1.80/2.03  ======= end of input processing =======
% 1.80/2.03  
% 1.80/2.03  =========== start of search ===========
% 1.80/2.03  
% 1.80/2.03  -------- PROOF -------- 
% 1.80/2.03  
% 1.80/2.03  ----> UNIT CONFLICT at   0.00 sec ----> 157 [binary,155.1,10.1] $F.
% 1.80/2.03  
% 1.80/2.03  Length of proof is 13.  Level of proof is 8.
% 1.80/2.03  
% 1.80/2.03  ---------------- PROOF ----------------
% 1.80/2.03  % SZS status Unsatisfiable
% 1.80/2.03  % SZS output start Refutation
% See solution above
% 1.80/2.03  ------------ end of proof -------------
% 1.80/2.03  
% 1.80/2.03  
% 1.80/2.03  Search stopped by max_proofs option.
% 1.80/2.03  
% 1.80/2.03  
% 1.80/2.03  Search stopped by max_proofs option.
% 1.80/2.03  
% 1.80/2.03  ============ end of search ============
% 1.80/2.03  
% 1.80/2.03  -------------- statistics -------------
% 1.80/2.03  clauses given                 18
% 1.80/2.03  clauses generated            176
% 1.80/2.03  clauses kept                 105
% 1.80/2.03  clauses forward subsumed     172
% 1.80/2.03  clauses back subsumed          2
% 1.80/2.03  Kbytes malloced             1953
% 1.80/2.03  
% 1.80/2.03  ----------- times (seconds) -----------
% 1.80/2.03  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.80/2.03  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.80/2.03  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.80/2.03  
% 1.80/2.03  That finishes the proof of the theorem.
% 1.80/2.03  
% 1.80/2.03  Process 2812 finished Wed Jul 27 05:37:32 2022
% 1.80/2.03  Otter interrupted
% 1.80/2.03  PROOF FOUND
%------------------------------------------------------------------------------