%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : HEN001-5 : TPTP v8.1.0. Released v1.0.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 12:57:53 EDT 2022
% Result : Unsatisfiable 1.68s 1.89s
% Output : Refutation 1.68s
% Verified :
% SZS Type : Refutation
% Derivation depth : 1
% Number of leaves : 2
% Syntax : Number of clauses : 3 ( 3 unt; 0 nHn; 2 RR)
% Number of literals : 3 ( 2 equ; 1 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 4 ( 4 usr; 3 con; 0-2 aty)
% Number of variables : 1 ( 1 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(2,axiom,
divide(a,identity) != zero,
file('HEN001-5.p',unknown),
[] ).
cnf(10,axiom,
divide(A,identity) = zero,
file('HEN001-5.p',unknown),
[] ).
cnf(12,plain,
$false,
inference(binary,[status(thm)],[10,2]),
[iquote('binary,10.1,2.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : HEN001-5 : TPTP v8.1.0. Released v1.0.0.
% 0.07/0.13 % Command : otter-tptp-script %s
% 0.13/0.33 % Computer : n021.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 300
% 0.13/0.33 % DateTime : Wed Jul 27 08:53:08 EDT 2022
% 0.13/0.34 % CPUTime :
% 1.68/1.89
% 1.68/1.89 -------- PROOF --------
% 1.68/1.89 ----- Otter 3.3f, August 2004 -----
% 1.68/1.89 The process was started by sandbox2 on n021.cluster.edu,
% 1.68/1.89 Wed Jul 27 08:53:08 2022
% 1.68/1.89 The command was "./otter". The process ID is 11965.
% 1.68/1.89
% 1.68/1.89 set(prolog_style_variables).
% 1.68/1.89 set(auto).
% 1.68/1.89 dependent: set(auto1).
% 1.68/1.89 dependent: set(process_input).
% 1.68/1.89 dependent: clear(print_kept).
% 1.68/1.89 dependent: clear(print_new_demod).
% 1.68/1.89 dependent: clear(print_back_demod).
% 1.68/1.89 dependent: clear(print_back_sub).
% 1.68/1.89 dependent: set(control_memory).
% 1.68/1.89 dependent: assign(max_mem, 12000).
% 1.68/1.89 dependent: assign(pick_given_ratio, 4).
% 1.68/1.89 dependent: assign(stats_level, 1).
% 1.68/1.89 dependent: assign(max_seconds, 10800).
% 1.68/1.89 clear(print_given).
% 1.68/1.89
% 1.68/1.89 list(usable).
% 1.68/1.89 0 [] A=A.
% 1.68/1.89 0 [] divide(divide(X,Y),X)=zero.
% 1.68/1.89 0 [] divide(divide(divide(X,Z),divide(Y,Z)),divide(divide(X,Y),Z))=zero.
% 1.68/1.89 0 [] divide(zero,X)=zero.
% 1.68/1.89 0 [] divide(X,Y)!=zero|divide(Y,X)!=zero|X=Y.
% 1.68/1.89 0 [] divide(X,identity)=zero.
% 1.68/1.89 0 [] divide(a,identity)!=zero.
% 1.68/1.89 end_of_list.
% 1.68/1.89
% 1.68/1.89 SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=3.
% 1.68/1.89
% 1.68/1.89 This is a Horn set with equality. The strategy will be
% 1.68/1.89 Knuth-Bendix and hyper_res, with positive clauses in
% 1.68/1.89 sos and nonpositive clauses in usable.
% 1.68/1.89
% 1.68/1.89 dependent: set(knuth_bendix).
% 1.68/1.89 dependent: set(anl_eq).
% 1.68/1.89 dependent: set(para_from).
% 1.68/1.89 dependent: set(para_into).
% 1.68/1.89 dependent: clear(para_from_right).
% 1.68/1.89 dependent: clear(para_into_right).
% 1.68/1.89 dependent: set(para_from_vars).
% 1.68/1.89 dependent: set(eq_units_both_ways).
% 1.68/1.89 dependent: set(dynamic_demod_all).
% 1.68/1.89 dependent: set(dynamic_demod).
% 1.68/1.89 dependent: set(order_eq).
% 1.68/1.89 dependent: set(back_demod).
% 1.68/1.89 dependent: set(lrpo).
% 1.68/1.89 dependent: set(hyper_res).
% 1.68/1.89 dependent: clear(order_hyper).
% 1.68/1.89
% 1.68/1.89 ------------> process usable:
% 1.68/1.89 ** KEPT (pick-wt=13): 1 [] divide(A,B)!=zero|divide(B,A)!=zero|A=B.
% 1.68/1.89 ** KEPT (pick-wt=5): 2 [] divide(a,identity)!=zero.
% 1.68/1.89
% 1.68/1.89 ------------> process sos:
% 1.68/1.89 ** KEPT (pick-wt=3): 3 [] A=A.
% 1.68/1.89 ** KEPT (pick-wt=7): 4 [] divide(divide(A,B),A)=zero.
% 1.68/1.89 ---> New Demodulator: 5 [new_demod,4] divide(divide(A,B),A)=zero.
% 1.68/1.89 ** KEPT (pick-wt=15): 6 [] divide(divide(divide(A,B),divide(C,B)),divide(divide(A,C),B))=zero.
% 1.68/1.89 ---> New Demodulator: 7 [new_demod,6] divide(divide(divide(A,B),divide(C,B)),divide(divide(A,C),B))=zero.
% 1.68/1.89 ** KEPT (pick-wt=5): 8 [] divide(zero,A)=zero.
% 1.68/1.89 ---> New Demodulator: 9 [new_demod,8] divide(zero,A)=zero.
% 1.68/1.89 ** KEPT (pick-wt=5): 10 [] divide(A,identity)=zero.
% 1.68/1.89 ---> New Demodulator: 11 [new_demod,10] divide(A,identity)=zero.
% 1.68/1.89
% 1.68/1.89 ----> UNIT CONFLICT at 0.00 sec ----> 12 [binary,10.1,2.1] $F.
% 1.68/1.89
% 1.68/1.89 Length of proof is 0. Level of proof is 0.
% 1.68/1.89
% 1.68/1.89 ---------------- PROOF ----------------
% 1.68/1.89 % SZS status Unsatisfiable
% 1.68/1.89 % SZS output start Refutation
% See solution above
% 1.68/1.89 ------------ end of proof -------------
% 1.68/1.89
% 1.68/1.89
% 1.68/1.89 Search stopped by max_proofs option.
% 1.68/1.89
% 1.68/1.89
% 1.68/1.89 Search stopped by max_proofs option.
% 1.68/1.89
% 1.68/1.89 ============ end of search ============
% 1.68/1.89
% 1.68/1.89 -------------- statistics -------------
% 1.68/1.89 clauses given 0
% 1.68/1.89 clauses generated 0
% 1.68/1.89 clauses kept 7
% 1.68/1.89 clauses forward subsumed 0
% 1.68/1.89 clauses back subsumed 0
% 1.68/1.89 Kbytes malloced 976
% 1.68/1.89
% 1.68/1.89 ----------- times (seconds) -----------
% 1.68/1.89 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.68/1.89 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.68/1.89 wall-clock time 1 (0 hr, 0 min, 1 sec)
% 1.68/1.89
% 1.68/1.89 That finishes the proof of the theorem.
% 1.68/1.89
% 1.68/1.89 Process 11965 finished Wed Jul 27 08:53:09 2022
% 1.68/1.89 Otter interrupted
% 1.68/1.89 PROOF FOUND
%------------------------------------------------------------------------------