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SPASS---3.9.UNS-Ref.s

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : HEN008-5 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 13:03:09 EDT 2022

% Result   : Unsatisfiable 0.18s 0.40s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   12 (   8 unt;   0 nHn;  12 RR)
%            Number of literals    :   18 (   0 equ;   7 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    4 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   7 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    equal(divide(a,b),zero),
    file('HEN008-5.p',unknown),
    [] ).

cnf(2,axiom,
    ~ equal(divide(divide(a,c),divide(b,c)),zero),
    file('HEN008-5.p',unknown),
    [] ).

cnf(4,axiom,
    equal(divide(divide(divide(u,v),divide(w,v)),divide(divide(u,w),v)),zero),
    file('HEN008-5.p',unknown),
    [] ).

cnf(5,axiom,
    equal(divide(zero,u),zero),
    file('HEN008-5.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ equal(divide(u,v),zero)
    | ~ equal(divide(v,u),zero)
    | equal(v,u) ),
    file('HEN008-5.p',unknown),
    [] ).

cnf(21,plain,
    ( ~ equal(zero,zero)
    | ~ equal(divide(u,zero),zero)
    | equal(u,zero) ),
    inference(spl,[status(thm),theory(equality)],[5,6]),
    [iquote('0:SpL:5.0,6.0')] ).

cnf(25,plain,
    ( ~ equal(divide(u,zero),zero)
    | equal(u,zero) ),
    inference(obv,[status(thm),theory(equality)],[21]),
    [iquote('0:Obv:21.0')] ).

cnf(38,plain,
    equal(divide(divide(divide(a,u),divide(b,u)),divide(zero,u)),zero),
    inference(spr,[status(thm),theory(equality)],[1,4]),
    [iquote('0:SpR:1.0,4.0')] ).

cnf(55,plain,
    equal(divide(divide(divide(a,u),divide(b,u)),zero),zero),
    inference(rew,[status(thm),theory(equality)],[5,38]),
    [iquote('0:Rew:5.0,38.0')] ).

cnf(76,plain,
    ( ~ equal(zero,zero)
    | equal(divide(divide(a,u),divide(b,u)),zero) ),
    inference(spl,[status(thm),theory(equality)],[55,25]),
    [iquote('0:SpL:55.0,25.0')] ).

cnf(78,plain,
    equal(divide(divide(a,u),divide(b,u)),zero),
    inference(obv,[status(thm),theory(equality)],[76]),
    [iquote('0:Obv:76.0')] ).

cnf(79,plain,
    $false,
    inference(unc,[status(thm)],[78,2]),
    [iquote('0:UnC:78.0,2.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : HEN008-5 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n020.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Fri Jul  1 14:45:45 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.40  
% 0.18/0.40  SPASS V 3.9 
% 0.18/0.40  SPASS beiseite: Proof found.
% 0.18/0.40  % SZS status Theorem
% 0.18/0.40  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.18/0.40  SPASS derived 50 clauses, backtracked 0 clauses, performed 0 splits and kept 27 clauses.
% 0.18/0.40  SPASS allocated 63216 KBytes.
% 0.18/0.40  SPASS spent	0:00:00.06 on the problem.
% 0.18/0.40  		0:00:00.03 for the input.
% 0.18/0.40  		0:00:00.00 for the FLOTTER CNF translation.
% 0.18/0.40  		0:00:00.00 for inferences.
% 0.18/0.40  		0:00:00.00 for the backtracking.
% 0.18/0.40  		0:00:00.00 for the reduction.
% 0.18/0.40  
% 0.18/0.40  
% 0.18/0.40  Here is a proof with depth 2, length 12 :
% 0.18/0.40  % SZS output start Refutation
% See solution above
% 0.18/0.41  Formulae used in the proof : a_divide_b_is_zero prove_property_of_divide3 quotient_property zero_is_smallest divide_and_equal
% 0.18/0.41  
%------------------------------------------------------------------------------