%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : ITP225_1 : TPTP v9.2.0. Released v8.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n018.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:51:35 PM UTC 2025 % Result : Theorem 87.69s 87.93s % Output : Proof 87.69s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.08/0.12 % Problem : ITP225_1 : TPTP v9.2.0. Released v8.0.0. % 0.08/0.14 % Command : duper %s % 0.14/0.35 % Computer : n018.cluster.edu % 0.14/0.35 % Model : x86_64 x86_64 % 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.35 % Memory : 8042.1875MB % 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.35 % CPULimit : 300 % 0.14/0.35 % WCLimit : 300 % 0.14/0.35 % DateTime : Fri Oct 3 00:42:08 EDT 2025 % 0.14/0.35 % CPUTime : % 87.69/87.93 SZS status Theorem for theBenchmark.p % 87.69/87.93 SZS output start Proof for theBenchmark.p % 87.69/87.93 Clause #3 (by assumption #[]): Eq (Eq m (aa_nat_nat suc na)) True % 87.69/87.93 Clause #10 (by assumption #[]): Eq (∀ (N : nat), pp (aa_nat_bool (aa_nat_fun_nat_bool ord_less_nat zero_zero_nat) (aa_nat_nat suc N))) True % 87.69/87.93 Clause #10125 (by assumption #[]): Eq (Not (pp (aa_nat_bool (aa_nat_fun_nat_bool ord_less_nat zero_zero_nat) m))) True % 87.69/87.93 Clause #10140 (by clausification #[3]): Eq m (aa_nat_nat suc na) % 87.69/87.93 Clause #10215 (by clausification #[10]): ∀ (a : nat), Eq (pp (aa_nat_bool (aa_nat_fun_nat_bool ord_less_nat zero_zero_nat) (aa_nat_nat suc a))) True % 87.69/87.93 Clause #10217 (by superposition #[10215, 10140]): Eq (pp (aa_nat_bool (aa_nat_fun_nat_bool ord_less_nat zero_zero_nat) m)) True % 87.69/87.93 Clause #12790 (by clausification #[10125]): Eq (pp (aa_nat_bool (aa_nat_fun_nat_bool ord_less_nat zero_zero_nat) m)) False % 87.69/87.93 Clause #12792 (by superposition #[12790, 10217]): Eq False True % 87.69/87.93 Clause #12801 (by clausification #[12792]): False % 87.69/87.93 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------