%------------------------------------------------------------------------------
% File : ConnectPP---0.7.2
% Problem : LAT388+1 : TPTP v9.3.1. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : /export/starexec/sandbox/solver/bin/connect++ --verbosity 1 --no-colour --tptp-proof --schedule default --timeout 300 /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Sep 24 08:48:28 AM UTC 2026
% Result : Theorem 0.21s 0.46s
% Output : Proof 0.21s
% Verified :
% SZS Type : Refutation
% Derivation depth : 7
% Number of leaves : 2
% Syntax : Number of formulae : 12 ( 10 unt; 0 def)
% Number of atoms : 14 ( 0 equ)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 8 ( 6 ~; 0 |; 2 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 3 ( 2 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-3 aty)
% Number of functors : 4 ( 4 usr; 4 con; 0-0 aty)
% Number of variables : 6 ( 1 sgn 3 !; 2 ?)
% Comments :
%------------------------------------------------------------------------------
fof(m__1330,hypothesis,
( aSupremumOfIn0(xp,xT,xS)
& aFixedPointOf0(xp,xf) ),
file('theBenchmark.p',m__1330) ).
fof(m__,conjecture,
? [W0] : aSupremumOfIn0(W0,xT,xS),
file('theBenchmark.p',m__) ).
fof(f_30_1,plain,
( aSupremumOfIn0(xp,xT,xS)
& aFixedPointOf0(xp,xf) ),
inference(fof_nnf,[status(thm)],[m__1330]) ).
cnf(f_30_3,plain,
aSupremumOfIn0(xp,xT,xS),
inference(clausify,[status(thm)],[f_30_1]) ).
fof(f_31_1,negated_conjecture,
~ ? [W0] : aSupremumOfIn0(W0,xT,xS),
inference(negate,[status(cth)],[m__]) ).
fof(f_31_2,negated_conjecture,
! [W0] : ~ aSupremumOfIn0(W0,xT,xS),
inference(fof_nnf,[status(thm)],[f_31_1]) ).
fof(f_31_3,negated_conjecture,
! [U_82] : ~ aSupremumOfIn0(U_82,xT,xS),
inference(variable_rename,[status(thm)],[f_31_2]) ).
fof(f_31_4,negated_conjecture,
! [U_82] : ~ aSupremumOfIn0(U_82,xT,xS),
inference(definitional_conversion,[status(esa)],[f_31_3]) ).
cnf(f_31_5,negated_conjecture,
~ aSupremumOfIn0(U_82,xT,xS),
inference(clausify,[status(thm)],[f_31_4]) ).
cnf(t1,plain,
~ aSupremumOfIn0(xp,xT,xS),
inference(start,[status(thm),parent(0:0)],[f_31_5]) ).
cnf(t2,plain,
aSupremumOfIn0(xp,xT,xS),
inference(extension,[status(thm),parent(t1:1)],[f_30_3]) ).
cnf(t3,plain,
$false,
inference(connection,[status(thm),parent(t2:1)],[t2:1,t1:1]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : LAT388+1 : TPTP v9.3.1. Released v4.0.0.
% 0.00/0.03 This is a FOF_THM_RFO_SEQ problem
% 0.00/0.04 % Command : /export/starexec/sandbox/solver/bin/connect++ --verbosity 1 --no-colour --tptp-proof --schedule default --timeout 300 /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.09/0.36 % Computer : n003.cluster.edu
% 0.09/0.36 % Model : x86_64 x86_64
% 0.09/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.36 % Memory : 8046.5625MB
% 0.09/0.36 % OS : Linux 6.8.0-71-generic
% 0.09/0.36 % CPULimit : 300
% 0.09/0.36 % WCLimit : 300
% 0.09/0.36 % DateTime : Sat Sep 19 13:53:58 UTC 2026
% 0.09/0.37 % CPUTime :
% 0.21/0.46 % SZS status Theorem for theBenchmark
% 0.21/0.46 % SZS output start Proof for theBenchmark
% See solution above
%------------------------------------------------------------------------------