↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : LAT388+4 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 07:53:33 PM UTC 2025

% Result   : Theorem 4.56s 4.73s
% Output   : Proof 4.56s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13  % Problem    : LAT388+4 : TPTP v9.2.0. Released v4.0.0.
% 0.03/0.14  % Command    : duper %s
% 0.15/0.36  % Computer : n010.cluster.edu
% 0.15/0.36  % Model    : x86_64 x86_64
% 0.15/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36  % Memory   : 8042.1875MB
% 0.15/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36  % CPULimit   : 300
% 0.15/0.36  % WCLimit    : 300
% 0.15/0.36  % DateTime   : Thu Oct  2 18:38:23 EDT 2025
% 0.15/0.36  % CPUTime    : 
% 4.56/4.73  SZS status Theorem for theBenchmark.p
% 4.56/4.73  SZS output start Proof for theBenchmark.p
% 4.56/4.73  Clause #29 (by assumption #[]): Eq
% 4.56/4.73    (And
% 4.56/4.73      (And
% 4.56/4.73        (And
% 4.56/4.73          (And (And (And (aElementOf0 xp (szDzozmdt0 xf)) (Eq (sdtlpdtrp0 xf xp) xp)) (aFixedPointOf0 xp xf))
% 4.56/4.73            (∀ (W0 : Iota), aElementOf0 W0 xT → sdtlseqdt0 W0 xp))
% 4.56/4.73          (aUpperBoundOfIn0 xp xT xS))
% 4.56/4.73        (∀ (W0 : Iota),
% 4.56/4.73          Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0)) (aUpperBoundOfIn0 W0 xT xS) →
% 4.56/4.73            sdtlseqdt0 xp W0))
% 4.56/4.73      (aSupremumOfIn0 xp xT xS))
% 4.56/4.73    True
% 4.56/4.73  Clause #30 (by assumption #[]): Eq
% 4.56/4.73    (Not
% 4.56/4.73      (Exists fun W0 =>
% 4.56/4.73        Or
% 4.56/4.73          (And
% 4.56/4.73            (And (aElementOf0 W0 xS)
% 4.56/4.73              (Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0))
% 4.56/4.73                (aUpperBoundOfIn0 W0 xT xS)))
% 4.56/4.73            (∀ (W1 : Iota),
% 4.56/4.73              And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.56/4.73                  (aUpperBoundOfIn0 W1 xT xS) →
% 4.56/4.73                sdtlseqdt0 W0 W1))
% 4.56/4.73          (aSupremumOfIn0 W0 xT xS)))
% 4.56/4.73    True
% 4.56/4.73  Clause #343 (by clausification #[29]): Eq (aSupremumOfIn0 xp xT xS) True
% 4.56/4.73  Clause #354 (by clausification #[30]): Eq
% 4.56/4.73    (Exists fun W0 =>
% 4.56/4.73      Or
% 4.56/4.73        (And
% 4.56/4.73          (And (aElementOf0 W0 xS)
% 4.56/4.73            (Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0))
% 4.56/4.73              (aUpperBoundOfIn0 W0 xT xS)))
% 4.56/4.73          (∀ (W1 : Iota),
% 4.56/4.73            And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.56/4.73                (aUpperBoundOfIn0 W1 xT xS) →
% 4.56/4.73              sdtlseqdt0 W0 W1))
% 4.56/4.73        (aSupremumOfIn0 W0 xT xS))
% 4.56/4.73    False
% 4.56/4.73  Clause #355 (by clausification #[354]): ∀ (a : Iota),
% 4.56/4.73    Eq
% 4.56/4.73      (Or
% 4.56/4.73        (And
% 4.56/4.73          (And (aElementOf0 a xS)
% 4.56/4.73            (Or (And (aElementOf0 a xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 a)) (aUpperBoundOfIn0 a xT xS)))
% 4.56/4.73          (∀ (W1 : Iota),
% 4.56/4.73            And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.56/4.73                (aUpperBoundOfIn0 W1 xT xS) →
% 4.56/4.73              sdtlseqdt0 a W1))
% 4.56/4.73        (aSupremumOfIn0 a xT xS))
% 4.56/4.73      False
% 4.56/4.73  Clause #356 (by clausification #[355]): ∀ (a : Iota), Eq (aSupremumOfIn0 a xT xS) False
% 4.56/4.73  Clause #358 (by superposition #[356, 343]): Eq False True
% 4.56/4.73  Clause #359 (by clausification #[358]): False
% 4.56/4.73  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------