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Twee---2.7.UNS-Prf.s

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%------------------------------------------------------------------------------
% File     : Twee---2.7
% Problem  : LCL212-3 : TPTP v9.3.1. Released v2.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue Sep 29 11:49:22 AM UTC 2026

% Result   : Unsatisfiable 0.15s 0.44s
% Output   : Proof 0.15s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : LCL212-3 : TPTP v9.3.1. Released v2.3.0.
% 0.00/0.05  % Command  : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.11/0.36  % Computer : n019.cluster.edu
% 0.11/0.36  % Model    : x86_64 x86_64
% 0.11/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.36  % Memory   : 8046.5625MB
% 0.11/0.36  % OS       : Linux 6.8.0-71-generic
% 0.11/0.36  % CPULimit : 300
% 0.11/0.36  % WCLimit  : 300
% 0.11/0.36  % DateTime : Sun Sep 27 15:26:48 UTC 2026
% 0.11/0.37  % CPUTime  : 
% 0.11/0.37  Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.15/0.44  Command-line arguments: --flatten-regeneralise
% 0.15/0.44  
% 0.15/0.44  % SZS status Unsatisfiable
% 0.15/0.44  
% 0.15/0.44  % SZS output start Proof
% 0.15/0.44  Axiom 1 (implies_definition): implies(X, Y) = or(not(X), Y).
% 0.15/0.44  Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 0.15/0.44  Axiom 3 (rule_1): ifeq(axiom(X), true, theorem(X), true) = true.
% 0.15/0.44  Axiom 4 (axiom_1_3): axiom(implies(X, or(Y, X))) = true.
% 0.15/0.44  Axiom 5 (rule_2): ifeq(theorem(implies(X, Y)), true, ifeq(theorem(X), true, theorem(Y), true), true) = true.
% 0.15/0.44  
% 0.15/0.44  Goal 1 (prove_this): theorem(implies(not(p), implies(q, implies(implies(p, q), q)))) = true.
% 0.15/0.44  Proof:
% 0.15/0.44    theorem(implies(not(p), implies(q, implies(implies(p, q), q))))
% 0.15/0.44  = { by axiom 2 (ifeq_axiom) R->L }
% 0.15/0.44    ifeq(true, true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true)
% 0.15/0.44  = { by axiom 3 (rule_1) R->L }
% 0.15/0.44    ifeq(ifeq(axiom(implies(q, implies(implies(p, q), q))), true, theorem(implies(q, implies(implies(p, q), q))), true), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true)
% 0.15/0.44  = { by axiom 1 (implies_definition) }
% 0.15/0.44    ifeq(ifeq(axiom(implies(q, or(not(implies(p, q)), q))), true, theorem(implies(q, implies(implies(p, q), q))), true), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true)
% 0.15/0.44  = { by axiom 4 (axiom_1_3) }
% 0.15/0.44    ifeq(ifeq(true, true, theorem(implies(q, implies(implies(p, q), q))), true), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true)
% 0.15/0.44  = { by axiom 2 (ifeq_axiom) }
% 0.15/0.44    ifeq(theorem(implies(q, implies(implies(p, q), q))), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true)
% 0.15/0.44  = { by axiom 2 (ifeq_axiom) R->L }
% 0.15/0.44    ifeq(true, true, ifeq(theorem(implies(q, implies(implies(p, q), q))), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true), true)
% 0.15/0.44  = { by axiom 3 (rule_1) R->L }
% 0.15/0.44    ifeq(ifeq(axiom(implies(implies(q, implies(implies(p, q), q)), implies(not(p), implies(q, implies(implies(p, q), q))))), true, theorem(implies(implies(q, implies(implies(p, q), q)), implies(not(p), implies(q, implies(implies(p, q), q))))), true), true, ifeq(theorem(implies(q, implies(implies(p, q), q))), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true), true)
% 0.15/0.44  = { by axiom 1 (implies_definition) }
% 0.15/0.44    ifeq(ifeq(axiom(implies(implies(q, implies(implies(p, q), q)), or(not(not(p)), implies(q, implies(implies(p, q), q))))), true, theorem(implies(implies(q, implies(implies(p, q), q)), implies(not(p), implies(q, implies(implies(p, q), q))))), true), true, ifeq(theorem(implies(q, implies(implies(p, q), q))), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true), true)
% 0.15/0.44  = { by axiom 4 (axiom_1_3) }
% 0.15/0.44    ifeq(ifeq(true, true, theorem(implies(implies(q, implies(implies(p, q), q)), implies(not(p), implies(q, implies(implies(p, q), q))))), true), true, ifeq(theorem(implies(q, implies(implies(p, q), q))), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true), true)
% 0.15/0.44  = { by axiom 2 (ifeq_axiom) }
% 0.15/0.44    ifeq(theorem(implies(implies(q, implies(implies(p, q), q)), implies(not(p), implies(q, implies(implies(p, q), q))))), true, ifeq(theorem(implies(q, implies(implies(p, q), q))), true, theorem(implies(not(p), implies(q, implies(implies(p, q), q)))), true), true)
% 0.15/0.44  = { by axiom 5 (rule_2) }
% 0.15/0.44    true
% 0.15/0.44  % SZS output end Proof
% 0.15/0.44  
% 0.15/0.44  RESULT: Unsatisfiable (the axioms are contradictory).
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