↑ Up

cocATP---0.2.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : LCL579^1 : TPTP v6.1.0. Released v3.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n184.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:25:48 EDT 2014

% Result   : Theorem 0.37s
% Output   : Proof 0.37s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : LCL579^1 : TPTP v6.1.0. Released v3.6.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n184.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 10:00:11 CDT 2014
% % CPUTime  : 0.37 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (forall (X:fofType) (Y:fofType), ((forall (P:(fofType->Prop)), ((P X)->(P Y)))->(forall (P:(fofType->Prop)), ((P Y)->(P X))))) of role conjecture named a
% Conjecture to prove = (forall (X:fofType) (Y:fofType), ((forall (P:(fofType->Prop)), ((P X)->(P Y)))->(forall (P:(fofType->Prop)), ((P Y)->(P X))))):Prop
% Parameter fofType_DUMMY:fofType.
% We need to prove ['(forall (X:fofType) (Y:fofType), ((forall (P:(fofType->Prop)), ((P X)->(P Y)))->(forall (P:(fofType->Prop)), ((P Y)->(P X)))))']
% Parameter fofType:Type.
% Trying to prove (forall (X:fofType) (Y:fofType), ((forall (P:(fofType->Prop)), ((P X)->(P Y)))->(forall (P:(fofType->Prop)), ((P Y)->(P X)))))
% Found eq_sym0:=(eq_sym fofType):(forall (a:fofType) (b:fofType), ((((eq fofType) a) b)->(((eq fofType) b) a)))
% Found (eq_sym fofType) as proof of (forall (X:fofType) (Y:fofType), ((((eq fofType) X) Y)->(((eq fofType) Y) X)))
% Found (eq_sym fofType) as proof of (forall (X:fofType) (Y:fofType), ((((eq fofType) X) Y)->(((eq fofType) Y) X)))
% Found (eq_sym fofType) as proof of (forall (X:fofType) (Y:fofType), ((forall (P:(fofType->Prop)), ((P X)->(P Y)))->(forall (P:(fofType->Prop)), ((P Y)->(P X)))))
% Got proof (eq_sym fofType)
% Time elapsed = 0.062627s
% node=9 cost=-48.000000 depth=2
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% (eq_sym fofType)
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
%------------------------------------------------------------------------------