%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : LCL579^2 : TPTP v6.1.0. Released v5.1.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n093.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32286.75MB % OS : Linux 2.6.32-431.20.3.el6.x86_64 % CPULimit : 300s % DateTime : Thu Jul 17 13:25:48 EDT 2014 % Result : Theorem 0.39s % Output : Proof 0.39s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----ERROR: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % % Problem : LCL579^2 : TPTP v6.1.0. Released v5.1.0. % % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % % Computer : n093.star.cs.uiowa.edu % % Model : x86_64 x86_64 % % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % % Memory : 32286.75MB % % OS : Linux 2.6.32-431.20.3.el6.x86_64 % % CPULimit : 300 % % DateTime : Thu Jul 17 10:00:16 CDT 2014 % % CPUTime : 0.39 % Python 2.7.5 % Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % FOF formula (<kernel.Constant object at 0x1fa0200>, <kernel.Constant object at 0x1f81320>) of role type named cY % Using role type % Declaring cY:fofType % FOF formula (<kernel.Constant object at 0x21ef5a8>, <kernel.Single object at 0x1f812d8>) of role type named cX % Using role type % Declaring cX:fofType % FOF formula ((forall (P:(fofType->Prop)), ((P cY)->(P cX)))->(forall (R:(fofType->Prop)), ((R cX)->(R cY)))) of role conjecture named cTHM76A % Conjecture to prove = ((forall (P:(fofType->Prop)), ((P cY)->(P cX)))->(forall (R:(fofType->Prop)), ((R cX)->(R cY)))):Prop % We need to prove ['((forall (P:(fofType->Prop)), ((P cY)->(P cX)))->(forall (R:(fofType->Prop)), ((R cX)->(R cY))))'] % Parameter fofType:Type. % Parameter cY:fofType. % Parameter cX:fofType. % Trying to prove ((forall (P:(fofType->Prop)), ((P cY)->(P cX)))->(forall (R:(fofType->Prop)), ((R cX)->(R cY)))) % Found eq_sym000:=(eq_sym00 cX):((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % Found (eq_sym00 cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % Found ((eq_sym0 cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % Found (((eq_sym fofType) cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % Found (((eq_sym fofType) cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) % Found (((eq_sym fofType) cY) cX) as proof of ((forall (P:(fofType->Prop)), ((P cY)->(P cX)))->(forall (R:(fofType->Prop)), ((R cX)->(R cY)))) % Got proof (((eq_sym fofType) cY) cX) % Time elapsed = 0.076729s % node=9 cost=-239.000000 depth=4 % :::::::::::::::::::::: % % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % (((eq_sym fofType) cY) cX) % % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % EOF %------------------------------------------------------------------------------