%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : LCL646+1.001 : TPTP v9.3.1. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n012.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 11:50:09 AM UTC 2026
% Result : Theorem 0.07s 0.34s
% Output : Proof 0.07s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.01 % Problem : LCL646+1.001 : TPTP v9.3.1. Released v4.0.0.
% 0.00/0.02 % Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.03/0.29 % Computer : n012.cluster.edu
% 0.03/0.29 % Model : x86_64 x86_64
% 0.03/0.29 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.03/0.29 % Memory : 8046.5625MB
% 0.03/0.29 % OS : Linux 6.8.0-71-generic
% 0.03/0.29 % CPULimit : 300
% 0.03/0.29 % WCLimit : 300
% 0.03/0.29 % DateTime : Sun Sep 27 16:12:04 UTC 2026
% 0.03/0.29 % CPUTime :
% 0.03/0.29 Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.07/0.34 Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-every 2
% 0.07/0.34
% 0.07/0.34 % SZS status Theorem
% 0.07/0.34
% 0.07/0.35 % SZS output start Proof
% 0.07/0.35 Axiom 1 (main_2): r1(x, y2) = true.
% 0.07/0.35 Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 0.07/0.35 Axiom 3 (main_5): ifeq(r1(x, X), true, p2(X), true) = true.
% 0.07/0.35
% 0.07/0.35 Goal 1 (main_8): p2(y2) = true.
% 0.07/0.35 Proof:
% 0.07/0.35 p2(y2)
% 0.07/0.35 = { by axiom 2 (ifeq_axiom) R->L }
% 0.07/0.35 ifeq(true, true, p2(y2), true)
% 0.07/0.35 = { by axiom 1 (main_2) R->L }
% 0.07/0.35 ifeq(r1(x, y2), true, p2(y2), true)
% 0.07/0.35 = { by axiom 3 (main_5) }
% 0.07/0.35 true
% 0.07/0.35 % SZS output end Proof
% 0.07/0.35
% 0.07/0.35 RESULT: Theorem (the conjecture is true).
%------------------------------------------------------------------------------