%------------------------------------------------------------------------------ % File : Crossbow---0.1 % Problem : LCL655+1.001 : TPTP v9.3.1. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : do_Crossbow---0.1 %s % Computer : n016.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8046.5625MB % OS : Linux 6.8.0-71-generic % CPULimit : 300s % WCLimit : 300s % DateTime : Mon Sep 7 11:17:41 AM UTC 2026 % Result : CounterSatisfiable 5.25s 5.55s % Output : FiniteModel 5.25s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.05 % Problem : LCL655+1.001 : TPTP v9.3.1. Released v4.0.0. % 0.00/0.06 % Command : do_Crossbow---0.1 %s % 0.17/0.44 % Computer : n016.cluster.edu % 0.17/0.44 % Model : x86_64 x86_64 % 0.17/0.44 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.17/0.44 % Memory : 8046.5625MB % 0.17/0.44 % OS : Linux 6.8.0-71-generic % 0.17/0.44 % CPULimit : 300 % 0.17/0.44 % WCLimit : 300 % 0.17/0.44 % DateTime : Fri Sep 4 22:02:28 UTC 2026 % 0.17/0.44 % CPUTime : % 0.17/0.44 /export/starexec/sandbox/solver/bin % 0.17/0.45 crossbow.opt % 0.17/0.45 do_Crossbow---0.1 % 0.17/0.45 eprover % 0.17/0.45 runsolver % 0.17/0.45 starexec_run_Crossbow---0.1 % 5.25/5.55 % SZS status CounterSatisfiable for theBenchmark.p % 5.25/5.55 % SZS output start FiniteModel for theBenchmark.p % 5.25/5.55 % domain size: 2 % 5.25/5.55 fof(interp, fi_domain, ![X] : (X = 0 | X = 1)). % 5.25/5.55 fof(interp, fi_functors, esk10_0 = 0). % 5.25/5.55 fof(interp, fi_functors, esk11_0 = 1). % 5.25/5.55 fof(interp, fi_functors, esk12_0 = 0). % 5.25/5.55 fof(interp, fi_functors, esk1_0 = 0). % 5.25/5.55 fof(interp, fi_functors, esk2_3(0, 0, 0) = 0 & esk2_3(0, 0, 1) = 0 & % 5.25/5.55 esk2_3(0, 1, 0) = 0 & % 5.25/5.55 esk2_3(0, 1, 1) = 0 & % 5.25/5.55 esk2_3(1, 0, 0) = 0 & % 5.25/5.55 esk2_3(1, 0, 1) = 0 & % 5.25/5.55 esk2_3(1, 1, 0) = 0 & % 5.25/5.55 esk2_3(1, 1, 1) = 0). % 5.25/5.55 fof(interp, fi_functors, esk3_1(0) = 0 & esk3_1(1) = 1). % 5.25/5.55 fof(interp, fi_functors, esk4_1(0) = 0 & esk4_1(1) = 1). % 5.25/5.55 fof(interp, fi_functors, esk5_1(0) = 1 & esk5_1(1) = 1). % 5.25/5.55 fof(interp, fi_functors, esk6_1(0) = 0 & esk6_1(1) = 0). % 5.25/5.55 fof(interp, fi_functors, esk7_3(0, 0, 0) = 1 & esk7_3(0, 0, 1) = 1 & % 5.25/5.55 esk7_3(0, 1, 0) = 0 & % 5.25/5.55 esk7_3(0, 1, 1) = 1 & % 5.25/5.55 esk7_3(1, 0, 0) = 0 & % 5.25/5.55 esk7_3(1, 0, 1) = 0 & % 5.25/5.55 esk7_3(1, 1, 0) = 0 & % 5.25/5.55 esk7_3(1, 1, 1) = 1). % 5.25/5.55 fof(interp, fi_functors, esk8_1(0) = 1 & esk8_1(1) = 1). % 5.25/5.55 fof(interp, fi_functors, esk9_1(0) = 0 & esk9_1(1) = 1). % 5.25/5.55 fof(interp, fi_predicates, ~p1(0) & p1(1)). % 5.25/5.55 fof(interp, fi_predicates, r1(0, 0) & r1(0, 1) & ~r1(1, 0) & r1(1, 1)). % 5.25/5.55 % SZS output end FiniteModel for theBenchmark.p % 5.25/5.55 % 1 lemma(s) from E % 5.25/5.55 % cnf(cl, axiom, p1(esk11_0)). % 5.25/5.55 % 43 pred(s) % 5.25/5.55 % 12 func(s) % 5.25/5.55 % 1 sort(s) % 5.25/5.55 % 66 clause(s) % 5.25/5.55 % Instantiating 1 (5053 ms) % 5.25/5.55 % Solving (5054 ms) % 5.25/5.55 % Instantiating 2 (5054 ms) % 5.25/5.55 % Solving (5055 ms) % 5.25/5.55 % % 5.25/5.55 % 1 model found (5055 ms) %------------------------------------------------------------------------------