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Twee---2.7.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Twee---2.7
% Problem  : LCL664+1.001 : TPTP v9.3.1. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue Sep 29 11:50:15 AM UTC 2026

% Result   : Theorem 0.03s 0.42s
% Output   : Proof 0.03s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.02  % Problem  : LCL664+1.001 : TPTP v9.3.1. Released v4.0.0.
% 0.00/0.03  % Command  : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.09/0.36  % Computer : n026.cluster.edu
% 0.09/0.36  % Model    : x86_64 x86_64
% 0.09/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.36  % Memory   : 8046.5625MB
% 0.09/0.36  % OS       : Linux 6.8.0-71-generic
% 0.03/0.36  % CPULimit : 300
% 0.03/0.36  % WCLimit  : 300
% 0.03/0.36  % DateTime : Sun Sep 27 16:27:41 UTC 2026
% 0.03/0.36  % CPUTime  : 
% 0.03/0.36  Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.03/0.42  Command-line arguments: --flatten-regeneralise
% 0.03/0.42  
% 0.03/0.42  % SZS status Theorem
% 0.03/0.42  
% 0.03/0.42  % SZS output start Proof
% 0.03/0.42  Axiom 1 (main_2): r1(x, y2) = true.
% 0.03/0.42  Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 0.03/0.42  Axiom 3 (main_5): ifeq(r1(x, X), true, p12(X), true) = true.
% 0.03/0.42  
% 0.03/0.42  Goal 1 (main_8): p12(y2) = true.
% 0.03/0.42  Proof:
% 0.03/0.42    p12(y2)
% 0.03/0.42  = { by axiom 2 (ifeq_axiom) R->L }
% 0.03/0.42    ifeq(true, true, p12(y2), true)
% 0.03/0.42  = { by axiom 1 (main_2) R->L }
% 0.03/0.42    ifeq(r1(x, y2), true, p12(y2), true)
% 0.03/0.42  = { by axiom 3 (main_5) }
% 0.03/0.42    true
% 0.03/0.42  % SZS output end Proof
% 0.03/0.42  
% 0.03/0.42  RESULT: Theorem (the conjecture is true).
%------------------------------------------------------------------------------