↑ Up

SPASS---3.9.THM-Ref.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : LCL674+1.005 : TPTP v9.3.1. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Mon Sep  7 01:08:08 PM UTC 2026

% Result   : Theorem 0.66s 0.94s
% Output   : Refutation 0.66s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : LCL674+1.005 : TPTP v9.3.1. Released v4.0.0.
% 0.00/0.04  % Command  : run_spass %d %s
% 0.08/0.35  % Computer : n013.cluster.edu
% 0.08/0.35  % Model    : x86_64 x86_64
% 0.08/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.35  % Memory   : 8046.5625MB
% 0.08/0.35  % OS       : Linux 6.8.0-71-generic
% 0.08/0.35  % CPULimit : 300
% 0.08/0.35  % WCLimit  : 300
% 0.08/0.35  % DateTime : Sat Sep  5 02:05:20 UTC 2026
% 0.08/0.35  % CPUTime  : 
% 0.66/0.94  
% 0.66/0.94  SPASS V 3.9 
% 0.66/0.94  SPASS beiseite: Proof found.
% 0.66/0.94  % SZS status Theorem
% 0.66/0.94  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.66/0.94  SPASS derived 457 clauses, backtracked 0 clauses, performed 0 splits and kept 417 clauses.
% 0.66/0.94  SPASS allocated 98407 KBytes.
% 0.66/0.94  SPASS spent	0:00:00.57 on the problem.
% 0.66/0.94  		0:00:00.06 for the input.
% 0.66/0.94  		0:00:00.06 for the FLOTTER CNF translation.
% 0.66/0.94  		0:00:00.02 for inferences.
% 0.66/0.94  		0:00:00.00 for the backtracking.
% 0.66/0.94  		0:00:00.39 for the reduction.
% 0.66/0.94  
% 0.66/0.94  
% 0.66/0.94  Here is a proof with depth 4, length 23 :
% 0.66/0.94  % SZS output start Refutation
% 0.66/0.94  1[0:Inp] ||  -> p100(skc1)*.
% 0.66/0.94  2[0:Inp] || p101(skc1)* -> .
% 0.66/0.94  3[0:Inp] ||  -> r1(u,u)*.
% 0.66/0.94  5[0:Inp] ||  -> r1(u,skf18(u))*r.
% 0.66/0.94  7[0:Inp] ||  -> r1(u,skf16(u))*r.
% 0.66/0.94  14[0:Inp] || r1(skc1,u) -> p3(u)*.
% 0.66/0.94  19[0:Inp] p102(u) || r1(skc1,u) -> p101(u)*.
% 0.66/0.94  21[0:Inp] || r1(u,v)* r1(v,w)* -> r1(u,w)*.
% 0.66/0.94  34[0:Inp] p100(u) || r1(skc1,u) -> p101(u) p101(skf18(u))*.
% 0.66/0.94  46[0:Inp] p101(u) || p3(skf16(u))* r1(skc1,u) -> p102(u).
% 0.66/0.94  50[0:Inp] p100(u) || p102(skf18(u))* r1(skc1,u) -> p101(u).
% 0.66/0.94  128[0:Res:19.2,2.0] p102(skc1) || r1(skc1,skc1)* -> .
% 0.66/0.94  129[0:MRR:128.1,3.0] p102(skc1) ||  -> .
% 0.66/0.94  138[0:Res:14.1,46.1] p101(u) || r1(skc1,skf16(u))*r r1(skc1,u) -> p102(u).
% 0.66/0.94  723[0:Res:7.0,138.1] p101(skc1) || r1(skc1,skc1) -> p102(skc1)*.
% 0.66/0.94  724[0:NCh:21.2,21.1,138.1,7.0] p101(u) || r1(skc1,u) r1(skc1,u) -> p102(u)*.
% 0.66/0.94  725[0:MRR:723.1,723.2,3.0,129.0] p101(skc1) ||  -> .
% 0.66/0.94  726[0:Obv:724.1] p101(u) || r1(skc1,u) -> p102(u)*.
% 0.66/0.94  740[0:Res:726.2,50.1] p101(skf18(u)) p100(u) || r1(skc1,skf18(u))*r r1(skc1,u) -> p101(u).
% 0.66/0.94  741[0:MRR:740.0,34.3] p100(u) || r1(skc1,skf18(u))*r r1(skc1,u) -> p101(u).
% 0.66/0.94  743[0:Res:5.0,741.1] p100(skc1) || r1(skc1,skc1) -> p101(skc1)*.
% 0.66/0.94  745[0:SSi:743.0,1.0] || r1(skc1,skc1) -> p101(skc1)*.
% 0.66/0.94  746[0:MRR:745.0,745.1,3.0,725.0] ||  -> .
% 0.66/0.94  % SZS output end Refutation
% 0.66/0.94  Formulae used in the proof : main reflexivity transitivity
% 0.66/0.94  
%------------------------------------------------------------------------------