↑ Up

ConnectPP---0.7.2.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : ConnectPP---0.7.2
% Problem  : MGT070+1 : TPTP v9.3.1. Released v9.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : /export/starexec/sandbox2/solver/bin/connect++ --verbosity 1 --no-colour --tptp-proof --schedule default --timeout 300 /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Sep 24 08:50:48 AM UTC 2026

% Result   : Theorem 0.31s 0.56s
% Output   : Proof 0.31s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    9
%            Number of leaves      :    3
% Syntax   : Number of formulae    :   26 (  14 unt;   0 def)
%            Number of atoms       :   50 (   0 equ)
%            Maximal formula atoms :    3 (   1 avg)
%            Number of connectives :   48 (  24   ~;  18   |;   5   &)
%                                         (   0 <=>;   1  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    7 (   3 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-3 aty)
%            Number of functors    :    2 (   2 usr;   2 con; 0-0 aty)
%            Number of variables   :   22 (   1 sgn  15   !;   2   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(completion_compat,axiom,
    ! [V,InfD,SupD] :
      ( ( leq(V,SupD)
        & leq(InfD,V) )
     => completion_compatible(V,InfD,SupD) ),
    file('MGT002+4.ax',completion_compat) ).

fof(h_sup_ub,hypothesis,
    ! [X] : leq(X,nsup),
    file('theBenchmark.p',h_sup_ub) ).

fof(unknown_sound_compatible,conjecture,
    ? [V] :
      ( completion_compatible(V,ninf,nsup)
      & leq(V,nsup)
      & leq(ninf,V) ),
    file('theBenchmark.p',unknown_sound_compatible) ).

fof(f_29_1,plain,
    ! [V,InfD,SupD] :
      ( completion_compatible(V,InfD,SupD)
      | ~ leq(V,SupD)
      | ~ leq(InfD,V) ),
    inference(fof_nnf,[status(thm)],[completion_compat]) ).

fof(f_29_2,plain,
    ! [U_117,U_116,U_115] :
      ( completion_compatible(U_117,U_116,U_115)
      | ~ leq(U_117,U_115)
      | ~ leq(U_116,U_117) ),
    inference(variable_rename,[status(thm)],[f_29_1]) ).

cnf(f_29_3,plain,
    ( completion_compatible(U_117,U_116,U_115)
    | ~ leq(U_117,U_115)
    | ~ leq(U_116,U_117) ),
    inference(clausify,[status(thm)],[f_29_2]) ).

fof(f_38_1,plain,
    ! [X] : leq(X,nsup),
    inference(fof_nnf,[status(thm)],[h_sup_ub]) ).

fof(f_38_2,plain,
    ! [U_142] : leq(U_142,nsup),
    inference(variable_rename,[status(thm)],[f_38_1]) ).

cnf(f_38_3,plain,
    leq(U_142,nsup),
    inference(clausify,[status(thm)],[f_38_2]) ).

fof(f_40_1,negated_conjecture,
    ~ ? [V] :
        ( completion_compatible(V,ninf,nsup)
        & leq(V,nsup)
        & leq(ninf,V) ),
    inference(negate,[status(cth)],[unknown_sound_compatible]) ).

fof(f_40_2,negated_conjecture,
    ! [V] :
      ( ~ completion_compatible(V,ninf,nsup)
      | ~ leq(V,nsup)
      | ~ leq(ninf,V) ),
    inference(fof_nnf,[status(thm)],[f_40_1]) ).

fof(f_40_3,negated_conjecture,
    ! [U_143] :
      ( ~ completion_compatible(U_143,ninf,nsup)
      | ~ leq(U_143,nsup)
      | ~ leq(ninf,U_143) ),
    inference(variable_rename,[status(thm)],[f_40_2]) ).

fof(f_40_4,negated_conjecture,
    ! [U_143] :
      ( ~ completion_compatible(U_143,ninf,nsup)
      | ~ leq(U_143,nsup)
      | ~ leq(ninf,U_143) ),
    inference(definitional_conversion,[status(esa)],[f_40_3]) ).

cnf(f_40_5,negated_conjecture,
    ( ~ completion_compatible(U_143,ninf,nsup)
    | ~ leq(U_143,nsup)
    | ~ leq(ninf,U_143) ),
    inference(clausify,[status(thm)],[f_40_4]) ).

cnf(t1,plain,
    ( ~ leq(nsup,nsup)
    | ~ completion_compatible(nsup,ninf,nsup)
    | ~ leq(ninf,nsup) ),
    inference(start,[status(thm),parent(0:0)],[f_40_5]) ).

cnf(t2,plain,
    leq(ninf,nsup),
    inference(extension,[status(thm),parent(t1:1)],[f_38_3]) ).

cnf(t3,plain,
    $false,
    inference(connection,[status(thm),parent(t2:1)],[t2:1,t1:1]) ).

cnf(l1,lemma,
    leq(ninf,nsup),
    inference(lemma,[status(cth),parent(t1:1),below(0:0)],[t1:1]) ).

cnf(t4,plain,
    ( ~ leq(nsup,nsup)
    | ~ leq(ninf,nsup)
    | completion_compatible(nsup,ninf,nsup) ),
    inference(extension,[status(thm),parent(t1:2)],[f_29_3]) ).

cnf(t5,plain,
    $false,
    inference(connection,[status(thm),parent(t4:1)],[t4:1,t1:2]) ).

cnf(t6,plain,
    leq(ninf,nsup),
    inference(lemma_extension,[status(thm),parent(t4:2)],[l1:1]) ).

cnf(t7,plain,
    $false,
    inference(connection,[status(thm),parent(t6:1)],[t6:1,t4:2]) ).

cnf(t8,plain,
    leq(nsup,nsup),
    inference(extension,[status(thm),parent(t4:3)],[f_38_3]) ).

cnf(t9,plain,
    $false,
    inference(connection,[status(thm),parent(t8:1)],[t8:1,t4:3]) ).

cnf(t10,plain,
    leq(nsup,nsup),
    inference(extension,[status(thm),parent(t1:3)],[f_38_3]) ).

cnf(t11,plain,
    $false,
    inference(connection,[status(thm),parent(t10:1)],[t10:1,t1:3]) ).


%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : MGT070+1 : TPTP v9.3.1. Released v9.3.0.
% 0.00/0.03  This is a FOF_THM_RFO_SEQ problem
% 0.00/0.04  % Command  : /export/starexec/sandbox2/solver/bin/connect++ --verbosity 1 --no-colour --tptp-proof --schedule default --timeout 300 /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.10/0.36  % Computer : n006.cluster.edu
% 0.10/0.36  % Model    : x86_64 x86_64
% 0.10/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.36  % Memory   : 8046.5625MB
% 0.10/0.36  % OS       : Linux 6.8.0-71-generic
% 0.10/0.36  % CPULimit : 300
% 0.10/0.36  % WCLimit  : 300
% 0.10/0.36  % DateTime : Sat Sep 19 16:18:57 UTC 2026
% 0.10/0.36  % CPUTime  : 
% 0.31/0.56  % SZS status Theorem for theBenchmark
% 0.31/0.56  % SZS output start Proof for theBenchmark
% See solution above
%------------------------------------------------------------------------------