%------------------------------------------------------------------------------ % File : Etableau---0.67 % Problem : NUM424+3 : TPTP v8.1.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s % Computer : n010.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 600s % DateTime : Mon Jul 18 09:40:52 EDT 2022 % Result : Theorem 1.39s 0.58s % Output : CNFRefutation 1.39s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.06/0.11 % Problem : NUM424+3 : TPTP v8.1.0. Released v4.0.0. % 0.06/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s % 0.12/0.33 % Computer : n010.cluster.edu % 0.12/0.33 % Model : x86_64 x86_64 % 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.33 % Memory : 8042.1875MB % 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.33 % CPULimit : 300 % 0.12/0.33 % WCLimit : 600 % 0.12/0.33 % DateTime : Tue Jul 5 13:59:02 EDT 2022 % 0.12/0.33 % CPUTime : % 0.12/0.36 # No SInE strategy applied % 0.12/0.36 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_S2m % 0.12/0.36 # and selection function SelectCQArNTNpEqFirst. % 0.12/0.36 # % 0.12/0.36 # Presaturation interreduction done % 0.12/0.36 # Number of axioms: 41 Number of unprocessed: 41 % 0.12/0.36 # Tableaux proof search. % 0.12/0.36 # APR header successfully linked. % 0.12/0.36 # Hello from C++ % 0.12/0.37 # The folding up rule is enabled... % 0.12/0.37 # Local unification is enabled... % 0.12/0.37 # Any saturation attempts will use folding labels... % 0.12/0.37 # 41 beginning clauses after preprocessing and clausification % 0.12/0.37 # Creating start rules for all 7 conjectures. % 0.12/0.37 # There are 7 start rule candidates: % 0.12/0.37 # Found 12 unit axioms. % 0.12/0.37 # Unsuccessfully attempted saturation on 1 start tableaux, moving on. % 0.12/0.37 # 7 start rule tableaux created. % 0.12/0.37 # 29 extension rule candidate clauses % 0.12/0.37 # 12 unit axiom clauses % 0.12/0.37 % 0.12/0.37 # Requested 8, 32 cores available to the main process. % 0.12/0.37 # There are not enough tableaux to fork, creating more from the initial 7 % 0.12/0.37 # Returning from population with 54 new_tableaux and 0 remaining starting tableaux. % 0.12/0.37 # We now have 54 tableaux to operate on % 1.39/0.58 # There were 2 total branch saturation attempts. % 1.39/0.58 # There were 0 of these attempts blocked. % 1.39/0.58 # There were 0 deferred branch saturation attempts. % 1.39/0.58 # There were 0 free duplicated saturations. % 1.39/0.58 # There were 2 total successful branch saturations. % 1.39/0.58 # There were 0 successful branch saturations in interreduction. % 1.39/0.58 # There were 0 successful branch saturations on the branch. % 1.39/0.58 # There were 2 successful branch saturations after the branch. % 1.39/0.58 # SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 1.39/0.58 # SZS output start for /export/starexec/sandbox/benchmark/theBenchmark.p % 1.39/0.58 # Begin clausification derivation % 1.39/0.58 % 1.39/0.58 # End clausification derivation % 1.39/0.58 # Begin listing active clauses obtained from FOF to CNF conversion % 1.39/0.58 cnf(i_0_35, hypothesis, (aInteger0(xa))). % 1.39/0.58 cnf(i_0_34, hypothesis, (aInteger0(xb))). % 1.39/0.58 cnf(i_0_33, hypothesis, (aInteger0(xq))). % 1.39/0.58 cnf(i_0_42, negated_conjecture, (aInteger0(esk2_0))). % 1.39/0.58 cnf(i_0_2, plain, (aInteger0(sz00))). % 1.39/0.58 cnf(i_0_3, plain, (aInteger0(sz10))). % 1.39/0.58 cnf(i_0_39, negated_conjecture, (sdteqdtlpzmzozddtrp0(xa,xb,xq))). % 1.39/0.58 cnf(i_0_41, negated_conjecture, (sdtpldt0(xa,smndt0(xb))=sdtasdt0(xq,esk2_0))). % 1.39/0.58 cnf(i_0_40, negated_conjecture, (aDivisorOf0(xq,sdtasdt0(xq,esk2_0)))). % 1.39/0.58 cnf(i_0_32, hypothesis, (xq!=sz00)). % 1.39/0.58 cnf(i_0_36, negated_conjecture, (~sdteqdtlpzmzozddtrp0(xb,xa,xq))). % 1.39/0.58 cnf(i_0_37, negated_conjecture, (~aDivisorOf0(xq,sdtpldt0(xb,smndt0(xa))))). % 1.39/0.58 cnf(i_0_27, plain, (~aDivisorOf0(sz00,X1)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_28, plain, (aInteger0(X1)|~aDivisorOf0(X1,X2)|~aInteger0(X2))). % 1.39/0.58 cnf(i_0_38, negated_conjecture, (sdtasdt0(xq,X1)!=sdtpldt0(xb,smndt0(xa))|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_4, plain, (aInteger0(smndt0(X1))|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_19, plain, (sdtasdt0(sz00,X1)=sz00|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_9, plain, (sdtpldt0(sz00,X1)=X1|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_15, plain, (sdtasdt0(sz10,X1)=X1|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_10, plain, (sdtpldt0(X1,sz00)=X1|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_16, plain, (sdtasdt0(X1,sz10)=X1|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_20, plain, (sdtasdt0(X1,sz00)=sz00|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_5, plain, (aInteger0(sdtpldt0(X1,X2))|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_6, plain, (aInteger0(sdtasdt0(X1,X2))|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_11, plain, (sdtpldt0(smndt0(X1),X1)=sz00|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_12, plain, (sdtpldt0(X1,smndt0(X1))=sz00|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_21, plain, (sdtasdt0(X1,smndt0(sz10))=smndt0(X1)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_22, plain, (sdtasdt0(smndt0(sz10),X1)=smndt0(X1)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_26, plain, (aInteger0(esk1_2(X1,X2))|~aDivisorOf0(X2,X1)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_31, plain, (X1=sz00|sdteqdtlpzmzozddtrp0(X2,X2,X1)|~aInteger0(X1)|~aInteger0(X2))). % 1.39/0.58 cnf(i_0_23, plain, (X1=sz00|X2=sz00|sdtasdt0(X1,X2)!=sz00|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_25, plain, (sdtasdt0(X1,esk1_2(X2,X1))=X2|~aDivisorOf0(X1,X2)|~aInteger0(X2))). % 1.39/0.58 cnf(i_0_8, plain, (sdtpldt0(X1,X2)=sdtpldt0(X2,X1)|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_14, plain, (sdtasdt0(X1,X2)=sdtasdt0(X2,X1)|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_7, plain, (sdtpldt0(sdtpldt0(X1,X2),X3)=sdtpldt0(X1,sdtpldt0(X2,X3))|~aInteger0(X3)|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_13, plain, (sdtasdt0(sdtasdt0(X1,X2),X3)=sdtasdt0(X1,sdtasdt0(X2,X3))|~aInteger0(X3)|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_24, plain, (X1=sz00|aDivisorOf0(X1,sdtasdt0(X1,X2))|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_18, plain, (sdtpldt0(sdtasdt0(X1,X2),sdtasdt0(X1,X3))=sdtasdt0(X1,sdtpldt0(X2,X3))|~aInteger0(X3)|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_29, plain, (X1=sz00|sdteqdtlpzmzozddtrp0(X2,X3,X1)|~aDivisorOf0(X1,sdtpldt0(X2,smndt0(X3)))|~aInteger0(X3)|~aInteger0(X2)|~aInteger0(X1))). % 1.39/0.58 cnf(i_0_30, plain, (X1=sz00|aDivisorOf0(X1,sdtpldt0(X2,smndt0(X3)))|~sdteqdtlpzmzozddtrp0(X2,X3,X1)|~aInteger0(X1)|~aInteger0(X3)|~aInteger0(X2))). % 1.39/0.58 cnf(i_0_17, plain, (sdtpldt0(sdtasdt0(X1,X2),sdtasdt0(X3,X2))=sdtasdt0(sdtpldt0(X1,X3),X2)|~aInteger0(X2)|~aInteger0(X3)|~aInteger0(X1))). % 1.39/0.58 # End listing active clauses. There is an equivalent clause to each of these in the clausification! % 1.39/0.58 # Begin printing tableau % 1.39/0.58 # Found 5 steps % 1.39/0.58 cnf(i_0_40, negated_conjecture, (aDivisorOf0(xq,sdtasdt0(xq,esk2_0))), inference(start_rule)). % 1.39/0.58 cnf(i_0_49, plain, (aDivisorOf0(xq,sdtasdt0(xq,esk2_0))), inference(extension_rule, [i_0_26])). % 1.39/0.58 cnf(i_0_350, plain, (aInteger0(esk1_2(sdtasdt0(xq,esk2_0),xq))), inference(extension_rule, [i_0_27])). % 1.39/0.58 cnf(i_0_352, plain, (~aInteger0(sdtasdt0(xq,esk2_0))), inference(etableau_closure_rule, [i_0_352, ...])). % 1.39/0.58 cnf(i_0_1197, plain, (~aDivisorOf0(sz00,esk1_2(sdtasdt0(xq,esk2_0),xq))), inference(etableau_closure_rule, [i_0_1197, ...])). % 1.39/0.58 # End printing tableau % 1.39/0.58 # SZS output end % 1.39/0.58 # Branches closed with saturation will be marked with an "s" % 1.39/0.58 # Child (21921) has found a proof. % 1.39/0.58 % 1.39/0.58 # Proof search is over... % 1.39/0.58 # Freeing feature tree %------------------------------------------------------------------------------