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Vampire-SAT---5.0.1.THM-Ref.s

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%------------------------------------------------------------------------------
% File     : Vampire-SAT---5.0.1
% Problem  : NUM429+3 : TPTP v9.3.1. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_vampire /export/starexec/sandbox/benchmark/theBenchmark.p 300 SAT

% Computer : n016.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue Sep 29 12:24:16 PM UTC 2026

% Result   : Theorem 0.12s 0.45s
% Output   : Refutation 0.12s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    2
% Syntax   : Number of formulae    :   12 (   4 unt;   0 def)
%            Number of atoms       :   38 (  12 equ)
%            Maximal formula atoms :    8 (   3 avg)
%            Number of connectives :   34 (   8   ~;   3   |;  23   &)
%                                         (   0 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    8 (   4 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    5 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :    9 (   9 usr;   6 con; 0-2 aty)
%            Number of variables   :    9 (   3   !;   6   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f23,axiom,
    ( ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xa,smndt0(xb)) )
    & aDivisorOf0(xq,sdtpldt0(xa,smndt0(xb)))
    & sdteqdtlpzmzozddtrp0(xa,xb,xq)
    & ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xb,smndt0(xc)) )
    & aDivisorOf0(xq,sdtpldt0(xb,smndt0(xc)))
    & sdteqdtlpzmzozddtrp0(xb,xc,xq) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__853) ).

fof(f24,conjecture,
    ? [X0] :
      ( aInteger0(X0)
      & sdtasdt0(xq,X0) = sdtpldt0(xa,smndt0(xb)) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__) ).

fof(f25,negated_conjecture,
    ~ ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xa,smndt0(xb)) ),
    inference(negated_conjecture,[status(cth)],[f24]) ).

fof(f27,plain,
    ( ? [X0] :
        ( aInteger0(X0)
        & sdtasdt0(xq,X0) = sdtpldt0(xa,smndt0(xb)) )
    & aDivisorOf0(xq,sdtpldt0(xa,smndt0(xb)))
    & sdteqdtlpzmzozddtrp0(xa,xb,xq)
    & ? [X1] :
        ( aInteger0(X1)
        & sdtpldt0(xb,smndt0(xc)) = sdtasdt0(xq,X1) )
    & aDivisorOf0(xq,sdtpldt0(xb,smndt0(xc)))
    & sdteqdtlpzmzozddtrp0(xb,xc,xq) ),
    inference(rectify,[],[f23]) ).

fof(f57,plain,
    ! [X0] :
      ( ~ aInteger0(X0)
      | sdtasdt0(xq,X0) != sdtpldt0(xa,smndt0(xb)) ),
    inference(ennf_transformation,[],[f25]) ).

fof(f63,plain,
    ( aInteger0(sK1)
    & sdtpldt0(xa,smndt0(xb)) = sdtasdt0(xq,sK1)
    & aDivisorOf0(xq,sdtpldt0(xa,smndt0(xb)))
    & sdteqdtlpzmzozddtrp0(xa,xb,xq)
    & aInteger0(sK2)
    & sdtpldt0(xb,smndt0(xc)) = sdtasdt0(xq,sK2)
    & aDivisorOf0(xq,sdtpldt0(xb,smndt0(xc)))
    & sdteqdtlpzmzozddtrp0(xb,xc,xq) ),
    inference(skolemize,[status(esa),new_symbols(skolem,[sK1,sK2]),skolemize(X0,sK1),skolemize(X1,sK2)],[f27]) ).

fof(f106,plain,
    sdtpldt0(xa,smndt0(xb)) = sdtasdt0(xq,sK1),
    inference(cnf_transformation,[],[f63]) ).

fof(f107,plain,
    aInteger0(sK1),
    inference(cnf_transformation,[],[f63]) ).

fof(f108,plain,
    ! [X0] :
      ( sdtasdt0(xq,X0) != sdtpldt0(xa,smndt0(xb))
      | ~ aInteger0(X0) ),
    inference(cnf_transformation,[],[f57]) ).

fof(f129,plain,
    ! [X0] :
      ( sdtasdt0(xq,X0) != sdtasdt0(xq,sK1)
      | ~ aInteger0(X0) ),
    inference(superposition,[],[f108,f106]) ).

fof(f133,plain,
    ~ aInteger0(sK1),
    inference(equality_resolution,[],[f129]) ).

fof(f134,plain,
    $false,
    inference(forward_subsumption_resolution,[],[f133,f107]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM429+3 : TPTP v9.3.1. Released v4.0.0.
% 0.00/0.06  % Command  : run_vampire /export/starexec/sandbox/benchmark/theBenchmark.p 300 SAT
% 0.12/0.39  % Computer : n016.cluster.edu
% 0.12/0.39  % Model    : x86_64 x86_64
% 0.12/0.39  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.39  % Memory   : 8046.5625MB
% 0.12/0.39  % OS       : Linux 6.8.0-71-generic
% 0.12/0.39  % CPULimit : 300
% 0.12/0.39  % WCLimit  : 300
% 0.12/0.39  % DateTime : Sun Sep 27 19:57:47 UTC 2026
% 0.12/0.39  % CPUTime  : 
% 0.12/0.39  Running run_vampire /export/starexec/sandbox/benchmark/theBenchmark.p 300 SAT
% 0.12/0.41  Running first-order model finding
% 0.12/0.41  Running: /export/starexec/sandbox/solver/bin/vampire-ho --input_syntax tptp --output_axiom_names on --mode casc --intent sat -m 16384 --cores 7 -t 300 /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.45  % (2953804)Will run a generic schedule for satisfiability detection.
% 0.12/0.45  % (2953811)dis+10_161_sil=256000:plsq=on:plsqr=61199697,1048576:gs=on:alpa=true:sac=on:slsq=on:cn=on:random_seed=1910216762:i=88024:add=on:rawr=on_2999 on theBenchmark for (2999ds/88024Mi)
% 0.12/0.45  % (2953811) found proof, printing to "/export/starexec/sandbox/tmp/vampire-proof-2953804-2953811"...
% 0.12/0.45  % (2953811)...printing done.
% 0.12/0.45  % (2953810)% WARNING: option uhcvi not known.
% 0.12/0.45  % (2953811)Refutation found. Thanks to Tanya!
% 0.12/0.45  % SZS status Theorem for theBenchmark
% 0.12/0.45  % SZS output start Proof for theBenchmark
% See solution above
% 0.12/0.45  % (2953811)------------------------------
% 0.12/0.45  % (2953811)Version: Vampire 5.0.1 (Release build, commit 5ef7c2677 on 2026-07-16 16:54:09 +0200)
% 0.12/0.45  % (2953811)Linked with Z3 4.14.0.0 3c47fd96cf5645d0c42b2c819d9e9a84380aa721 z3-4.8.4-9178-g3c47fd96c
% 0.12/0.45  % (2953811)CaDiCaL version: 2.1.3
% 0.12/0.45  % (2953811)Termination reason: Refutation
% 0.12/0.45  % (2953811)Time elapsed: 0.002 s
% 0.12/0.45  % (2953811)Peak memory usage: 12 MB
% 0.12/0.45  % (2953811)Instructions burned: 3 (million)
% 0.12/0.45  % (2953804)Success in time 0.026 s
% 0.12/0.45  % Vampire exiting
%------------------------------------------------------------------------------