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SPASS---3.9.THM-Ref.s

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM476+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:35 EDT 2022

% Result   : Theorem 0.47s 0.63s
% Output   : Refutation 0.47s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   13
%            Number of leaves      :   11
% Syntax   : Number of clauses     :   28 (  19 unt;   3 nHn;  28 RR)
%            Number of literals    :   37 (   0 equ;  12 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    5 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :   10 (  10 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(6,axiom,
    aNaturalNumber0(xn),
    file('NUM476+2.p',unknown),
    [] ).

cnf(8,axiom,
    aNaturalNumber0(skc4),
    file('NUM476+2.p',unknown),
    [] ).

cnf(10,axiom,
    ~ doDivides0(xl,xn),
    file('NUM476+2.p',unknown),
    [] ).

cnf(14,axiom,
    equal(sdtasdt0(xl,skc4),xm),
    file('NUM476+2.p',unknown),
    [] ).

cnf(15,axiom,
    doDivides0(xl,sdtpldt0(xm,xn)),
    file('NUM476+2.p',unknown),
    [] ).

cnf(17,axiom,
    ( aNaturalNumber0(sdtsldt0(xm,xl))
    | equal(xl,sz00) ),
    file('NUM476+2.p',unknown),
    [] ).

cnf(20,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(sdtpldt0(sz00,u),u) ),
    file('NUM476+2.p',unknown),
    [] ).

cnf(24,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(sdtasdt0(sz00,u),sz00) ),
    file('NUM476+2.p',unknown),
    [] ).

cnf(26,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ equal(sdtasdt0(xl,u),xn) ),
    file('NUM476+2.p',unknown),
    [] ).

cnf(33,axiom,
    ( aNaturalNumber0(sdtmndt0(sdtsldt0(sdtpldt0(xm,xn),xl),sdtsldt0(xm,xl)))
    | equal(xl,sz00) ),
    file('NUM476+2.p',unknown),
    [] ).

cnf(43,axiom,
    ( equal(xl,sz00)
    | equal(sdtasdt0(xl,sdtmndt0(sdtsldt0(sdtpldt0(xm,xn),xl),sdtsldt0(xm,xl))),xn) ),
    file('NUM476+2.p',unknown),
    [] ).

cnf(577,plain,
    equal(xl,sz00),
    inference(spt,[spt(split,[position(s1)])],[17]),
    [iquote('1:Spt:17.1')] ).

cnf(581,plain,
    ~ doDivides0(sz00,xn),
    inference(rew,[status(thm),theory(equality)],[577,10]),
    [iquote('1:Rew:577.0,10.0')] ).

cnf(582,plain,
    doDivides0(sz00,sdtpldt0(xm,xn)),
    inference(rew,[status(thm),theory(equality)],[577,15]),
    [iquote('1:Rew:577.0,15.0')] ).

cnf(583,plain,
    equal(sdtasdt0(sz00,skc4),xm),
    inference(rew,[status(thm),theory(equality)],[577,14]),
    [iquote('1:Rew:577.0,14.0')] ).

cnf(606,plain,
    ( ~ aNaturalNumber0(skc4)
    | equal(xm,sz00) ),
    inference(spr,[status(thm),theory(equality)],[583,24]),
    [iquote('1:SpR:583.0,24.1')] ).

cnf(608,plain,
    equal(xm,sz00),
    inference(ssi,[status(thm)],[606,8]),
    [iquote('1:SSi:606.0,8.0')] ).

cnf(612,plain,
    doDivides0(sz00,sdtpldt0(sz00,xn)),
    inference(rew,[status(thm),theory(equality)],[608,582]),
    [iquote('1:Rew:608.0,582.0')] ).

cnf(617,plain,
    ( ~ aNaturalNumber0(xn)
    | doDivides0(sz00,xn) ),
    inference(spr,[status(thm),theory(equality)],[20,612]),
    [iquote('1:SpR:20.1,612.0')] ).

cnf(618,plain,
    doDivides0(sz00,xn),
    inference(ssi,[status(thm)],[617,6]),
    [iquote('1:SSi:617.0,6.0')] ).

cnf(619,plain,
    $false,
    inference(mrr,[status(thm)],[618,581]),
    [iquote('1:MRR:618.0,581.0')] ).

cnf(620,plain,
    ~ equal(xl,sz00),
    inference(spt,[spt(split,[position(sa)])],[619,577]),
    [iquote('1:Spt:619.0,17.1,577.0')] ).

cnf(621,plain,
    aNaturalNumber0(sdtsldt0(xm,xl)),
    inference(spt,[spt(split,[position(s2)])],[17]),
    [iquote('1:Spt:619.0,17.0')] ).

cnf(625,plain,
    aNaturalNumber0(sdtmndt0(sdtsldt0(sdtpldt0(xm,xn),xl),sdtsldt0(xm,xl))),
    inference(mrr,[status(thm)],[33,620]),
    [iquote('1:MRR:33.1,620.0')] ).

cnf(628,plain,
    equal(sdtasdt0(xl,sdtmndt0(sdtsldt0(sdtpldt0(xm,xn),xl),sdtsldt0(xm,xl))),xn),
    inference(mrr,[status(thm)],[43,620]),
    [iquote('1:MRR:43.0,620.0')] ).

cnf(1058,plain,
    ( ~ aNaturalNumber0(sdtmndt0(sdtsldt0(sdtpldt0(xm,xn),xl),sdtsldt0(xm,xl)))
    | ~ equal(xn,xn) ),
    inference(spl,[status(thm),theory(equality)],[628,26]),
    [iquote('1:SpL:628.0,26.1')] ).

cnf(1059,plain,
    ~ aNaturalNumber0(sdtmndt0(sdtsldt0(sdtpldt0(xm,xn),xl),sdtsldt0(xm,xl))),
    inference(obv,[status(thm),theory(equality)],[1058]),
    [iquote('1:Obv:1058.1')] ).

cnf(1060,plain,
    $false,
    inference(ssi,[status(thm)],[1059,625]),
    [iquote('1:SSi:1059.0,625.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : NUM476+2 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.12  % Command  : run_spass %d %s
% 0.13/0.33  % Computer : n023.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Thu Jul  7 09:14:56 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.47/0.63  
% 0.47/0.63  SPASS V 3.9 
% 0.47/0.63  SPASS beiseite: Proof found.
% 0.47/0.63  % SZS status Theorem
% 0.47/0.63  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.47/0.63  SPASS derived 673 clauses, backtracked 291 clauses, performed 6 splits and kept 698 clauses.
% 0.47/0.63  SPASS allocated 98420 KBytes.
% 0.47/0.63  SPASS spent	0:00:00.28 on the problem.
% 0.47/0.63  		0:00:00.04 for the input.
% 0.47/0.63  		0:00:00.04 for the FLOTTER CNF translation.
% 0.47/0.63  		0:00:00.01 for inferences.
% 0.47/0.63  		0:00:00.00 for the backtracking.
% 0.47/0.63  		0:00:00.14 for the reduction.
% 0.47/0.63  
% 0.47/0.63  
% 0.47/0.63  Here is a proof with depth 1, length 28 :
% 0.47/0.63  % SZS output start Refutation
% See solution above
% 0.47/0.63  Formulae used in the proof : m__1324 m__1324_04 m__ m_AddZero m_MulZero
% 0.47/0.63  
%------------------------------------------------------------------------------