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ConnectPP---0.7.2.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : ConnectPP---0.7.2
% Problem  : NUM514+3 : TPTP v9.3.1. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : /export/starexec/sandbox2/solver/bin/connect++ --verbosity 1 --no-colour --tptp-proof --schedule default --timeout 300 /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Sep 24 08:52:28 AM UTC 2026

% Result   : Theorem 148.47s 148.75s
% Output   : Proof 148.47s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :    3
% Syntax   : Number of formulae    :   18 (   7 unt;   0 def)
%            Number of atoms       :   50 (  24 equ)
%            Maximal formula atoms :    5 (   2 avg)
%            Number of connectives :   48 (  16   ~;   9   |;  22   &)
%                                         (   0 <=>;   1  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    7 (   3 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    4 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   5 con; 0-2 aty)
%            Number of variables   :    8 (   0 sgn   3   !;   2   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(m__2613,hypothesis,
    ( sdtasdt0(xp,sdtsldt0(xk,xr)) = sdtasdt0(sdtsldt0(xn,xr),xm)
    & xn = sdtasdt0(xr,sdtsldt0(xn,xr))
    & aNaturalNumber0(sdtsldt0(xn,xr))
    & xk = sdtasdt0(xr,sdtsldt0(xk,xr))
    & aNaturalNumber0(sdtsldt0(xk,xr)) ),
    file('theBenchmark.p',m__2613) ).

fof(m__,conjecture,
    ( ( xn = sdtasdt0(xr,sdtsldt0(xn,xr))
      & aNaturalNumber0(sdtsldt0(xn,xr)) )
   => ( doDivides0(xp,sdtasdt0(sdtsldt0(xn,xr),xm))
      | ? [W0] :
          ( sdtasdt0(sdtsldt0(xn,xr),xm) = sdtasdt0(xp,W0)
          & aNaturalNumber0(W0) ) ) ),
    file('theBenchmark.p',m__) ).

fof(f_55_1,plain,
    ( sdtasdt0(xp,sdtsldt0(xk,xr)) = sdtasdt0(sdtsldt0(xn,xr),xm)
    & xn = sdtasdt0(xr,sdtsldt0(xn,xr))
    & aNaturalNumber0(sdtsldt0(xn,xr))
    & xk = sdtasdt0(xr,sdtsldt0(xk,xr))
    & aNaturalNumber0(sdtsldt0(xk,xr)) ),
    inference(fof_nnf,[status(thm)],[m__2613]) ).

cnf(f_55_2,plain,
    aNaturalNumber0(sdtsldt0(xk,xr)),
    inference(clausify,[status(thm)],[f_55_1]) ).

cnf(f_55_6,plain,
    sdtasdt0(xp,sdtsldt0(xk,xr)) = sdtasdt0(sdtsldt0(xn,xr),xm),
    inference(clausify,[status(thm)],[f_55_1]) ).

fof(f_56_1,negated_conjecture,
    ( ~ ( doDivides0(xp,sdtasdt0(sdtsldt0(xn,xr),xm))
        | ? [W0] :
            ( sdtasdt0(sdtsldt0(xn,xr),xm) = sdtasdt0(xp,W0)
            & aNaturalNumber0(W0) ) )
    & xn = sdtasdt0(xr,sdtsldt0(xn,xr))
    & aNaturalNumber0(sdtsldt0(xn,xr)) ),
    inference(negate,[status(cth)],[m__]) ).

fof(f_56_2,negated_conjecture,
    ( ~ doDivides0(xp,sdtasdt0(sdtsldt0(xn,xr),xm))
    & ! [W0] :
        ( sdtasdt0(sdtsldt0(xn,xr),xm) != sdtasdt0(xp,W0)
        | ~ aNaturalNumber0(W0) )
    & xn = sdtasdt0(xr,sdtsldt0(xn,xr))
    & aNaturalNumber0(sdtsldt0(xn,xr)) ),
    inference(fof_nnf,[status(thm)],[f_56_1]) ).

fof(f_56_3,negated_conjecture,
    ( ~ doDivides0(xp,sdtasdt0(sdtsldt0(xn,xr),xm))
    & ! [U_114] :
        ( sdtasdt0(sdtsldt0(xn,xr),xm) != sdtasdt0(xp,U_114)
        | ~ aNaturalNumber0(U_114) )
    & xn = sdtasdt0(xr,sdtsldt0(xn,xr))
    & aNaturalNumber0(sdtsldt0(xn,xr)) ),
    inference(variable_rename,[status(thm)],[f_56_2]) ).

fof(f_56_4,negated_conjecture,
    ( ~ doDivides0(xp,sdtasdt0(sdtsldt0(xn,xr),xm))
    & ! [U_114] :
        ( sdtasdt0(sdtsldt0(xn,xr),xm) != sdtasdt0(xp,U_114)
        | ~ aNaturalNumber0(U_114) )
    & xn = sdtasdt0(xr,sdtsldt0(xn,xr))
    & aNaturalNumber0(sdtsldt0(xn,xr)) ),
    inference(definitional_conversion,[status(esa)],[f_56_3]) ).

cnf(f_56_7,negated_conjecture,
    ( sdtasdt0(sdtsldt0(xn,xr),xm) != sdtasdt0(xp,U_114)
    | ~ aNaturalNumber0(U_114) ),
    inference(clausify,[status(thm)],[f_56_4]) ).

cnf(equality_2,axiom,
    ( Eq_x_1 = Eq_x_0
    | Eq_x_0 != Eq_x_1 ),
    theory(equality,[symmetry]) ).

cnf(t1,plain,
    ( sdtasdt0(sdtsldt0(xn,xr),xm) != sdtasdt0(xp,sdtsldt0(xk,xr))
    | ~ aNaturalNumber0(sdtsldt0(xk,xr)) ),
    inference(start,[status(thm),parent(0:0)],[f_56_7]) ).

cnf(t2,plain,
    aNaturalNumber0(sdtsldt0(xk,xr)),
    inference(extension,[status(thm),parent(t1:1)],[f_55_2]) ).

cnf(t3,plain,
    $false,
    inference(connection,[status(thm),parent(t2:1)],[t2:1,t1:1]) ).

cnf(t4,plain,
    ( sdtasdt0(xp,sdtsldt0(xk,xr)) != sdtasdt0(sdtsldt0(xn,xr),xm)
    | sdtasdt0(sdtsldt0(xn,xr),xm) = sdtasdt0(xp,sdtsldt0(xk,xr)) ),
    inference(extension,[status(thm),parent(t1:2)],[equality_2]) ).

cnf(t5,plain,
    $false,
    inference(connection,[status(thm),parent(t4:1)],[t4:1,t1:2]) ).

cnf(t6,plain,
    sdtasdt0(xp,sdtsldt0(xk,xr)) = sdtasdt0(sdtsldt0(xn,xr),xm),
    inference(extension,[status(thm),parent(t4:2)],[f_55_6]) ).

cnf(t7,plain,
    $false,
    inference(connection,[status(thm),parent(t6:1)],[t6:1,t4:2]) ).


%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM514+3 : TPTP v9.3.1. Released v4.0.0.
% 0.00/0.03  This is a FOF_THM_RFO_SEQ problem
% 0.00/0.04  % Command  : /export/starexec/sandbox2/solver/bin/connect++ --verbosity 1 --no-colour --tptp-proof --schedule default --timeout 300 /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.09/0.36  % Computer : n019.cluster.edu
% 0.09/0.36  % Model    : x86_64 x86_64
% 0.09/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.36  % Memory   : 8046.5625MB
% 0.09/0.36  % OS       : Linux 6.8.0-71-generic
% 0.09/0.36  % CPULimit : 300
% 0.09/0.36  % WCLimit  : 300
% 0.09/0.36  % DateTime : Sat Sep 19 18:40:50 UTC 2026
% 0.09/0.36  % CPUTime  : 
% 148.47/148.75  % SZS status Theorem for theBenchmark
% 148.47/148.75  % SZS output start Proof for theBenchmark
% See solution above
%------------------------------------------------------------------------------