%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : NUM519+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n014.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:19:04 EDT 2022
% Result : Theorem 2.93s 3.11s
% Output : Refutation 2.93s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12 % Problem : NUM519+3 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.12 % Command : sos-script %s
% 0.12/0.33 % Computer : n014.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Wed Jul 6 08:18:52 EDT 2022
% 0.12/0.33 % CPUTime :
% 2.93/3.11
% 2.93/3.11 -------- PROOF --------
% 2.93/3.11 % SZS status Unsatisfiable
% 2.93/3.11 % SZS output start Refutation
% 2.93/3.11 ----- Otter 3.2, August 2001 -----
% 2.93/3.11 The process was started by sandbox on n014.cluster.edu,
% 2.93/3.11 Wed Jul 6 08:18:52 2022
% 2.93/3.11 The command was "./sos". The process ID is 20318.
% 2.93/3.11
% 2.93/3.11 set(prolog_style_variables).
% 2.93/3.11 set(auto).
% 2.93/3.11 dependent: set(auto1).
% 2.93/3.11 dependent: set(process_input).
% 2.93/3.11 dependent: clear(print_kept).
% 2.93/3.11 dependent: clear(print_new_demod).
% 2.93/3.11 dependent: clear(print_back_demod).
% 2.93/3.11 dependent: clear(print_back_sub).
% 2.93/3.11 dependent: set(control_memory).
% 2.93/3.11 dependent: assign(max_mem, 12000).
% 2.93/3.11 dependent: assign(pick_given_ratio, 4).
% 2.93/3.11 dependent: assign(stats_level, 1).
% 2.93/3.11 dependent: assign(pick_semantic_ratio, 3).
% 2.93/3.11 dependent: assign(sos_limit, 5000).
% 2.93/3.11 dependent: assign(max_weight, 60).
% 2.93/3.11 clear(print_given).
% 2.93/3.11
% 2.93/3.11 formula_list(usable).
% 2.93/3.11
% 2.93/3.11 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=11.
% 2.93/3.11
% 2.93/3.11 This ia a non-Horn set with equality. The strategy will be
% 2.93/3.11 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 2.93/3.11 unit deletion, with positive clauses in sos and nonpositive
% 2.93/3.11 clauses in usable.
% 2.93/3.11
% 2.93/3.11 dependent: set(knuth_bendix).
% 2.93/3.11 dependent: set(para_from).
% 2.93/3.11 dependent: set(para_into).
% 2.93/3.11 dependent: clear(para_from_right).
% 2.93/3.11 dependent: clear(para_into_right).
% 2.93/3.11 dependent: set(para_from_vars).
% 2.93/3.11 dependent: set(eq_units_both_ways).
% 2.93/3.11 dependent: set(dynamic_demod_all).
% 2.93/3.11 dependent: set(dynamic_demod).
% 2.93/3.11 dependent: set(order_eq).
% 2.93/3.11 dependent: set(back_demod).
% 2.93/3.11 dependent: set(lrpo).
% 2.93/3.11 dependent: set(hyper_res).
% 2.93/3.11 dependent: set(unit_deletion).
% 2.93/3.11 dependent: set(factor).
% 2.93/3.11
% 2.93/3.11 ------------> process usable:
% 2.93/3.11 Following clause subsumed by 21 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)|A=B| -sdtlseqdt0(A,B)| -aNaturalNumber0(C)|sdtpldt0(C,A)!=sdtpldt0(C,B).
% 2.93/3.11 Following clause subsumed by 22 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)|A=B| -sdtlseqdt0(A,B)| -aNaturalNumber0(C)|sdtpldt0(A,C)!=sdtpldt0(B,C).
% 2.93/3.11 Following clause subsumed by 23 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)| -aNaturalNumber0(C)|A=sz00|B=C| -sdtlseqdt0(B,C)|sdtasdt0(A,B)!=sdtasdt0(A,C).
% 2.93/3.11 Following clause subsumed by 24 during input processing: 0 [] {-} -aNaturalNumber0(A)| -aNaturalNumber0(B)| -aNaturalNumber0(C)|A=sz00|B=C| -sdtlseqdt0(B,C)|sdtasdt0(B,A)!=sdtasdt0(C,A).
% 2.93/3.11 Following clause subsumed by 287 during input processing: 0 [] {-} xk!=sz00.
% 2.93/3.11 Following clause subsumed by 288 during input processing: 0 [] {-} xk!=sz10.
% 2.93/3.11 430 back subsumes 424.
% 2.93/3.11 430 back subsumes 418.
% 2.93/3.11 430 back subsumes 412.
% 2.93/3.11 430 back subsumes 394.
% 2.93/3.11 460 back subsumes 457.
% 2.93/3.11 460 back subsumes 454.
% 2.93/3.11 460 back subsumes 451.
% 2.93/3.11 460 back subsumes 442.
% 2.93/3.11 511 back subsumes 505.
% 2.93/3.11 511 back subsumes 499.
% 2.93/3.11 511 back subsumes 493.
% 2.93/3.11 511 back subsumes 475.
% 2.93/3.11 541 back subsumes 538.
% 2.93/3.11 541 back subsumes 535.
% 2.93/3.11 541 back subsumes 532.
% 2.93/3.11 541 back subsumes 523.
% 2.93/3.11 592 back subsumes 586.
% 2.93/3.11 592 back subsumes 580.
% 2.93/3.11 592 back subsumes 574.
% 2.93/3.11 592 back subsumes 556.
% 2.93/3.11 622 back subsumes 619.
% 2.93/3.11 622 back subsumes 616.
% 2.93/3.11 622 back subsumes 613.
% 2.93/3.11 622 back subsumes 604.
% 2.93/3.11 673 back subsumes 667.
% 2.93/3.11 673 back subsumes 661.
% 2.93/3.11 673 back subsumes 655.
% 2.93/3.11 673 back subsumes 637.
% 2.93/3.11 703 back subsumes 700.
% 2.93/3.11 703 back subsumes 697.
% 2.93/3.11 703 back subsumes 694.
% 2.93/3.11 703 back subsumes 685.
% 2.93/3.11 754 back subsumes 748.
% 2.93/3.11 754 back subsumes 742.
% 2.93/3.11 754 back subsumes 736.
% 2.93/3.11 754 back subsumes 718.
% 2.93/3.11 784 back subsumes 781.
% 2.93/3.11 784 back subsumes 778.
% 2.93/3.11 784 back subsumes 775.
% 2.93/3.11 784 back subsumes 766.
% 2.93/3.11 835 back subsumes 829.
% 2.93/3.11 835 back subsumes 823.
% 2.93/3.11 835 back subsumes 817.
% 2.93/3.11 835 back subsumes 799.
% 2.93/3.11 865 back subsumes 862.
% 2.93/3.11 865 back subsumes 859.
% 2.93/3.11 865 back subsumes 856.
% 2.93/3.11 865 back subsumes 847.
% 2.93/3.11 916 back subsumes 910.
% 2.93/3.11 916 back subsumes 904.
% 2.93/3.11 916 back subsumes 898.
% 2.93/3.11 916 back subsumes 880.
% 2.93/3.11 946 back subsumes 943.
% 2.93/3.11 946 back subsumes 940.
% 2.93/3.11 946 back subsumes 937.
% 2.93/3.11 946 back subsumes 928.
% 2.93/3.11
% 2.93/3.11 ------------> process sos:
% 2.93/3.11
% 2.93/3.11 -----> EMPTY CLAUSE at 2.76 sec ----> 1454 [copy,1453,unit_del,298,301] {-} $F.
% 2.93/3.11
% 2.93/3.11 Length of proof is 0. Level of proof is 0.
% 2.93/3.11
% 2.93/3.11 ---------------- PROOF ----------------
% 2.93/3.11 % SZS status Theorem
% 2.93/3.11 % SZS output start Refutation
% 2.93/3.11
% 2.93/3.11 298 [] {-} -doDivides0(xr,xn).
% 2.93/3.11 301 [] {-} -doDivides0(xr,xm).
% 2.93/3.11 1453 [] {-} doDivides0(xr,xn)|doDivides0(xr,xm).
% 2.93/3.11 1454 [copy,1453,unit_del,298,301] {-} $F.
% 2.93/3.11
% 2.93/3.11 % SZS output end Refutation
% 2.93/3.11 ------------ end of proof -------------
% 2.93/3.11
% 2.93/3.11
% 2.93/3.11 Search stopped by max_proofs option.
% 2.93/3.11
% 2.93/3.11
% 2.93/3.11 Search stopped by max_proofs option.
% 2.93/3.11
% 2.93/3.11 ============ end of search ============
% 2.93/3.11
% 2.93/3.11 That finishes the proof of the theorem.
% 2.93/3.11
% 2.93/3.11 Process 20318 finished Wed Jul 6 08:18:55 2022
%------------------------------------------------------------------------------