%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM544+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n013.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:27:20 EDT 2022
% Result : Theorem 0.46s 0.66s
% Output : Refutation 0.46s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 7
% Syntax : Number of clauses : 14 ( 8 unt; 0 nHn; 14 RR)
% Number of literals : 24 ( 0 equ; 14 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 4 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 5 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(6,axiom,
aElementOf0(skc3,xS),
file('NUM544+2.p',unknown),
[] ).
cnf(11,axiom,
aElementOf0(szmzazxdt0(xS),xS),
file('NUM544+2.p',unknown),
[] ).
cnf(19,axiom,
~ aElementOf0(skc3,slbdtrb0(szszuzczcdt0(szmzazxdt0(xS)))),
file('NUM544+2.p',unknown),
[] ).
cnf(26,axiom,
( ~ aElementOf0(u,xS)
| aElementOf0(u,szNzAzT0) ),
file('NUM544+2.p',unknown),
[] ).
cnf(27,axiom,
( ~ aElementOf0(u,xS)
| sdtlseqdt0(u,szmzazxdt0(xS)) ),
file('NUM544+2.p',unknown),
[] ).
cnf(69,axiom,
( ~ aElementOf0(u,szNzAzT0)
| ~ sdtlseqdt0(szszuzczcdt0(u),szszuzczcdt0(szmzazxdt0(xS)))
| aElementOf0(u,slbdtrb0(szszuzczcdt0(szmzazxdt0(xS)))) ),
file('NUM544+2.p',unknown),
[] ).
cnf(72,axiom,
( ~ sdtlseqdt0(u,v)
| ~ aElementOf0(v,szNzAzT0)
| ~ aElementOf0(u,szNzAzT0)
| sdtlseqdt0(szszuzczcdt0(u),szszuzczcdt0(v)) ),
file('NUM544+2.p',unknown),
[] ).
cnf(136,plain,
sdtlseqdt0(skc3,szmzazxdt0(xS)),
inference(res,[status(thm),theory(equality)],[6,27]),
[iquote('0:Res:6.0,27.0')] ).
cnf(137,plain,
aElementOf0(skc3,szNzAzT0),
inference(res,[status(thm),theory(equality)],[6,26]),
[iquote('0:Res:6.0,26.0')] ).
cnf(156,plain,
aElementOf0(szmzazxdt0(xS),szNzAzT0),
inference(res,[status(thm),theory(equality)],[11,26]),
[iquote('0:Res:11.0,26.0')] ).
cnf(238,plain,
( ~ aElementOf0(skc3,szNzAzT0)
| ~ sdtlseqdt0(szszuzczcdt0(skc3),szszuzczcdt0(szmzazxdt0(xS))) ),
inference(res,[status(thm),theory(equality)],[69,19]),
[iquote('0:Res:69.2,19.0')] ).
cnf(271,plain,
~ sdtlseqdt0(szszuzczcdt0(skc3),szszuzczcdt0(szmzazxdt0(xS))),
inference(mrr,[status(thm)],[238,137]),
[iquote('0:MRR:238.0,137.0')] ).
cnf(1668,plain,
( ~ sdtlseqdt0(skc3,szmzazxdt0(xS))
| ~ aElementOf0(szmzazxdt0(xS),szNzAzT0)
| ~ aElementOf0(skc3,szNzAzT0) ),
inference(res,[status(thm),theory(equality)],[72,271]),
[iquote('0:Res:72.3,271.0')] ).
cnf(1670,plain,
$false,
inference(mrr,[status(thm)],[1668,136,156,137]),
[iquote('0:MRR:1668.0,1668.1,1668.2,136.0,156.0,137.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : NUM544+2 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13 % Command : run_spass %d %s
% 0.13/0.34 % Computer : n013.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Tue Jul 5 02:56:59 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.46/0.66
% 0.46/0.66 SPASS V 3.9
% 0.46/0.66 SPASS beiseite: Proof found.
% 0.46/0.66 % SZS status Theorem
% 0.46/0.66 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.46/0.66 SPASS derived 1172 clauses, backtracked 221 clauses, performed 5 splits and kept 890 clauses.
% 0.46/0.66 SPASS allocated 99131 KBytes.
% 0.46/0.66 SPASS spent 0:00:00.30 on the problem.
% 0.46/0.66 0:00:00.04 for the input.
% 0.46/0.66 0:00:00.10 for the FLOTTER CNF translation.
% 0.46/0.66 0:00:00.01 for inferences.
% 0.46/0.66 0:00:00.00 for the backtracking.
% 0.46/0.66 0:00:00.10 for the reduction.
% 0.46/0.66
% 0.46/0.66
% 0.46/0.66 Here is a proof with depth 2, length 14 :
% 0.46/0.66 % SZS output start Refutation
% See solution above
% 0.46/0.66 Formulae used in the proof : m__ m__1986 mSuccLess
% 0.46/0.66
%------------------------------------------------------------------------------