%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM550+3 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n016.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:56:42 PM UTC 2025 % Result : Theorem 5.55s 5.76s % Output : Proof 5.55s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.13 % Problem : NUM550+3 : TPTP v9.2.0. Released v4.0.0. % 0.07/0.14 % Command : duper %s % 0.15/0.36 % Computer : n016.cluster.edu % 0.15/0.36 % Model : x86_64 x86_64 % 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.15/0.36 % Memory : 8042.1875MB % 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64 % 0.15/0.36 % CPULimit : 300 % 0.15/0.36 % WCLimit : 300 % 0.15/0.36 % DateTime : Fri Oct 3 07:13:38 EDT 2025 % 0.15/0.36 % CPUTime : % 5.55/5.76 SZS status Theorem for theBenchmark.p % 5.55/5.76 SZS output start Proof for theBenchmark.p % 5.55/5.76 Clause #23 (by assumption #[]): Eq (aElementOf0 sz00 szNzAzT0) True % 5.55/5.76 Clause #51 (by assumption #[]): Eq (Eq (slbdtrb0 sz00) slcrc0) True % 5.55/5.76 Clause #55 (by assumption #[]): Eq (∀ (W0 : Iota), aElementOf0 W0 szNzAzT0 → Eq (sbrdtbr0 (slbdtrb0 W0)) W0) True % 5.55/5.76 Clause #61 (by assumption #[]): Eq (And (And (aSet0 xS) (aSet0 xT)) (Ne xk sz00)) True % 5.55/5.76 Clause #65 (by assumption #[]): Eq (And (And (aSet0 xQ) (isFinite0 xQ)) (Eq (sbrdtbr0 xQ) xk)) True % 5.55/5.76 Clause #66 (by assumption #[]): Eq (Not (Not (And (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0)))) True % 5.55/5.76 Clause #83 (by clausification #[51]): Eq (slbdtrb0 sz00) slcrc0 % 5.55/5.76 Clause #201 (by clausification #[55]): ∀ (a : Iota), Eq (aElementOf0 a szNzAzT0 → Eq (sbrdtbr0 (slbdtrb0 a)) a) True % 5.55/5.76 Clause #202 (by clausification #[201]): ∀ (a : Iota), Or (Eq (aElementOf0 a szNzAzT0) False) (Eq (Eq (sbrdtbr0 (slbdtrb0 a)) a) True) % 5.55/5.76 Clause #203 (by clausification #[202]): ∀ (a : Iota), Or (Eq (aElementOf0 a szNzAzT0) False) (Eq (sbrdtbr0 (slbdtrb0 a)) a) % 5.55/5.76 Clause #204 (by superposition #[203, 23]): Or (Eq (sbrdtbr0 (slbdtrb0 sz00)) sz00) (Eq False True) % 5.55/5.76 Clause #207 (by clausification #[204]): Eq (sbrdtbr0 (slbdtrb0 sz00)) sz00 % 5.55/5.76 Clause #208 (by forward demodulation #[207, 83]): Eq (sbrdtbr0 slcrc0) sz00 % 5.55/5.76 Clause #356 (by clausification #[61]): Eq (Ne xk sz00) True % 5.55/5.76 Clause #358 (by clausification #[356]): Ne xk sz00 % 5.55/5.76 Clause #956 (by clausification #[65]): Eq (Eq (sbrdtbr0 xQ) xk) True % 5.55/5.76 Clause #958 (by clausification #[956]): Eq (sbrdtbr0 xQ) xk % 5.55/5.76 Clause #988 (by clausification #[66]): Eq (Not (And (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0))) False % 5.55/5.76 Clause #989 (by clausification #[988]): Eq (And (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0)) True % 5.55/5.76 Clause #990 (by clausification #[989]): Eq (Eq xQ slcrc0) True % 5.55/5.76 Clause #992 (by clausification #[990]): Eq xQ slcrc0 % 5.55/5.76 Clause #994 (by backward demodulation #[992, 958]): Eq (sbrdtbr0 slcrc0) xk % 5.55/5.76 Clause #1019 (by superposition #[994, 208]): Eq xk sz00 % 5.55/5.76 Clause #1020 (by forward contextual literal cutting #[1019, 358]): False % 5.55/5.76 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------