%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM551+3 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n008.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:56:42 PM UTC 2025 % Result : Theorem 5.66s 5.89s % Output : Proof 5.66s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : NUM551+3 : TPTP v9.2.0. Released v4.0.0. % 0.03/0.13 % Command : duper %s % 0.12/0.34 % Computer : n008.cluster.edu % 0.12/0.34 % Model : x86_64 x86_64 % 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.34 % Memory : 8042.1875MB % 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.34 % CPULimit : 300 % 0.12/0.34 % WCLimit : 300 % 0.12/0.34 % DateTime : Fri Oct 3 07:39:38 EDT 2025 % 0.12/0.34 % CPUTime : % 5.66/5.89 SZS status Theorem for theBenchmark.p % 5.66/5.89 SZS output start Proof for theBenchmark.p % 5.66/5.89 Clause #2 (by assumption #[]): Eq (∀ (W0 : Iota), aSet0 W0 → ∀ (W1 : Iota), aElementOf0 W1 W0 → aElement0 W1) True % 5.66/5.89 Clause #65 (by assumption #[]): Eq (And (And (aSet0 xQ) (isFinite0 xQ)) (Eq (sbrdtbr0 xQ) xk)) True % 5.66/5.89 Clause #66 (by assumption #[]): Eq (Not (Or (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0))) True % 5.66/5.89 Clause #67 (by assumption #[]): Eq (Not (Exists fun W0 => And (aElement0 W0) (aElementOf0 W0 xQ))) True % 5.66/5.89 Clause #85 (by clausification #[2]): ∀ (a : Iota), Eq (aSet0 a → ∀ (W1 : Iota), aElementOf0 W1 a → aElement0 W1) True % 5.66/5.89 Clause #86 (by clausification #[85]): ∀ (a : Iota), Or (Eq (aSet0 a) False) (Eq (∀ (W1 : Iota), aElementOf0 W1 a → aElement0 W1) True) % 5.66/5.89 Clause #87 (by clausification #[86]): ∀ (a a_1 : Iota), Or (Eq (aSet0 a) False) (Eq (aElementOf0 a_1 a → aElement0 a_1) True) % 5.66/5.89 Clause #88 (by clausification #[87]): ∀ (a a_1 : Iota), Or (Eq (aSet0 a) False) (Or (Eq (aElementOf0 a_1 a) False) (Eq (aElement0 a_1) True)) % 5.66/5.89 Clause #952 (by clausification #[67]): Eq (Exists fun W0 => And (aElement0 W0) (aElementOf0 W0 xQ)) False % 5.66/5.89 Clause #953 (by clausification #[952]): ∀ (a : Iota), Eq (And (aElement0 a) (aElementOf0 a xQ)) False % 5.66/5.89 Clause #954 (by clausification #[953]): ∀ (a : Iota), Or (Eq (aElement0 a) False) (Eq (aElementOf0 a xQ) False) % 5.66/5.89 Clause #972 (by clausification #[65]): Eq (And (aSet0 xQ) (isFinite0 xQ)) True % 5.66/5.89 Clause #975 (by clausification #[972]): Eq (aSet0 xQ) True % 5.66/5.89 Clause #977 (by superposition #[975, 88]): ∀ (a : Iota), Or (Eq True False) (Or (Eq (aElementOf0 a xQ) False) (Eq (aElement0 a) True)) % 5.66/5.89 Clause #1000 (by clausification #[66]): Eq (Or (Not (Exists fun W0 => aElementOf0 W0 xQ)) (Eq xQ slcrc0)) False % 5.66/5.89 Clause #1002 (by clausification #[1000]): Eq (Not (Exists fun W0 => aElementOf0 W0 xQ)) False % 5.66/5.89 Clause #1063 (by clausification #[1002]): Eq (Exists fun W0 => aElementOf0 W0 xQ) True % 5.66/5.89 Clause #1064 (by clausification #[1063]): ∀ (a : Iota), Eq (aElementOf0 (skS.0 11 a) xQ) True % 5.66/5.89 Clause #1081 (by clausification #[977]): ∀ (a : Iota), Or (Eq (aElementOf0 a xQ) False) (Eq (aElement0 a) True) % 5.66/5.89 Clause #1082 (by superposition #[1081, 1064]): ∀ (a : Iota), Or (Eq (aElement0 (skS.0 11 a)) True) (Eq False True) % 5.66/5.89 Clause #1097 (by clausification #[1082]): ∀ (a : Iota), Eq (aElement0 (skS.0 11 a)) True % 5.66/5.89 Clause #1103 (by superposition #[1097, 954]): ∀ (a : Iota), Or (Eq True False) (Eq (aElementOf0 (skS.0 11 a) xQ) False) % 5.66/5.89 Clause #1137 (by clausification #[1103]): ∀ (a : Iota), Eq (aElementOf0 (skS.0 11 a) xQ) False % 5.66/5.89 Clause #1138 (by superposition #[1137, 1064]): Eq False True % 5.66/5.89 Clause #1139 (by clausification #[1138]): False % 5.66/5.89 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------