%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM578+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:27:43 EDT 2022
% Result : Theorem 0.72s 0.91s
% Output : Refutation 0.72s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 6
% Syntax : Number of clauses : 12 ( 7 unt; 2 nHn; 12 RR)
% Number of literals : 22 ( 0 equ; 12 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-2 aty)
% Number of functors : 9 ( 9 usr; 6 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(14,axiom,
aElementOf0(xi,szNzAzT0),
file('NUM578+3.p',unknown),
[] ).
cnf(15,axiom,
aElementOf0(xj,szNzAzT0),
file('NUM578+3.p',unknown),
[] ).
cnf(16,axiom,
~ equal(xj,xi),
file('NUM578+3.p',unknown),
[] ).
cnf(53,axiom,
equal(szmzizndt0(sdtlpdtrp0(xN,xj)),szmzizndt0(sdtlpdtrp0(xN,xi))),
file('NUM578+3.p',unknown),
[] ).
cnf(77,axiom,
( equal(xj,xi)
| sdtlseqdt0(szszuzczcdt0(xj),xi)
| sdtlseqdt0(szszuzczcdt0(xi),xj) ),
file('NUM578+3.p',unknown),
[] ).
cnf(190,axiom,
( ~ aElementOf0(u,szNzAzT0)
| ~ aElementOf0(v,szNzAzT0)
| ~ sdtlseqdt0(szszuzczcdt0(v),u)
| ~ equal(szmzizndt0(sdtlpdtrp0(xN,u)),szmzizndt0(sdtlpdtrp0(xN,v))) ),
file('NUM578+3.p',unknown),
[] ).
cnf(239,plain,
( sdtlseqdt0(szszuzczcdt0(xj),xi)
| sdtlseqdt0(szszuzczcdt0(xi),xj) ),
inference(mrr,[status(thm)],[77,16]),
[iquote('0:MRR:77.0,16.0')] ).
cnf(347,plain,
( ~ aElementOf0(xi,szNzAzT0)
| ~ sdtlseqdt0(szszuzczcdt0(xi),xj)
| ~ aElementOf0(xj,szNzAzT0) ),
inference(res,[status(thm),theory(equality)],[53,190]),
[iquote('0:Res:53.0,190.0')] ).
cnf(355,plain,
( ~ aElementOf0(xj,szNzAzT0)
| ~ sdtlseqdt0(szszuzczcdt0(xj),xi)
| ~ aElementOf0(xi,szNzAzT0) ),
inference(res,[status(thm),theory(equality)],[53,190]),
[iquote('0:Res:53.0,190.0')] ).
cnf(559,plain,
~ sdtlseqdt0(szszuzczcdt0(xi),xj),
inference(mrr,[status(thm)],[347,14,15]),
[iquote('0:MRR:347.0,347.2,14.0,15.0')] ).
cnf(560,plain,
sdtlseqdt0(szszuzczcdt0(xj),xi),
inference(mrr,[status(thm)],[239,559]),
[iquote('0:MRR:239.1,559.0')] ).
cnf(561,plain,
$false,
inference(mrr,[status(thm)],[355,15,560,14]),
[iquote('0:MRR:355.0,355.1,355.2,15.0,560.0,14.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : NUM578+3 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13 % Command : run_spass %d %s
% 0.14/0.34 % Computer : n003.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 600
% 0.14/0.34 % DateTime : Thu Jul 7 18:49:27 EDT 2022
% 0.14/0.34 % CPUTime :
% 0.72/0.91
% 0.72/0.91 SPASS V 3.9
% 0.72/0.91 SPASS beiseite: Proof found.
% 0.72/0.91 % SZS status Theorem
% 0.72/0.91 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.72/0.91 SPASS derived 251 clauses, backtracked 0 clauses, performed 0 splits and kept 255 clauses.
% 0.72/0.91 SPASS allocated 102749 KBytes.
% 0.72/0.91 SPASS spent 0:00:00.55 on the problem.
% 0.72/0.91 0:00:00.04 for the input.
% 0.72/0.91 0:00:00.45 for the FLOTTER CNF translation.
% 0.72/0.91 0:00:00.00 for inferences.
% 0.72/0.91 0:00:00.00 for the backtracking.
% 0.72/0.91 0:00:00.02 for the reduction.
% 0.72/0.91
% 0.72/0.91
% 0.72/0.91 Here is a proof with depth 1, length 12 :
% 0.72/0.91 % SZS output start Refutation
% See solution above
% 0.72/0.91 Formulae used in the proof : m__3856 m__ m__3856_02
% 0.72/0.91
%------------------------------------------------------------------------------