%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM627+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:28:17 EDT 2022
% Result : Theorem 0.83s 1.04s
% Output : Refutation 0.83s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 7
% Syntax : Number of clauses : 15 ( 8 unt; 1 nHn; 15 RR)
% Number of literals : 30 ( 0 equ; 22 neg)
% Maximal clause size : 4 ( 2 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 6 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(28,axiom,
aElementOf0(xn,szNzAzT0),
file('NUM627+1.p',unknown),
[] ).
cnf(32,axiom,
aElementOf0(xm,szNzAzT0),
file('NUM627+1.p',unknown),
[] ).
cnf(80,axiom,
( ~ aElementOf0(u,szNzAzT0)
| aElementOf0(szszuzczcdt0(u),szNzAzT0) ),
file('NUM627+1.p',unknown),
[] ).
cnf(86,axiom,
~ aSubsetOf0(sdtlpdtrp0(xN,xn),sdtlpdtrp0(xN,xm)),
file('NUM627+1.p',unknown),
[] ).
cnf(96,axiom,
~ aSubsetOf0(sdtlpdtrp0(xN,xm),sdtlpdtrp0(xN,szszuzczcdt0(xn))),
file('NUM627+1.p',unknown),
[] ).
cnf(128,axiom,
( ~ aElementOf0(u,szNzAzT0)
| ~ aElementOf0(v,szNzAzT0)
| sdtlseqdt0(v,u)
| sdtlseqdt0(szszuzczcdt0(u),v) ),
file('NUM627+1.p',unknown),
[] ).
cnf(156,axiom,
( ~ sdtlseqdt0(u,v)
| ~ aElementOf0(u,szNzAzT0)
| ~ aElementOf0(v,szNzAzT0)
| aSubsetOf0(sdtlpdtrp0(xN,v),sdtlpdtrp0(xN,u)) ),
file('NUM627+1.p',unknown),
[] ).
cnf(2367,plain,
( ~ sdtlseqdt0(xm,xn)
| ~ aElementOf0(xm,szNzAzT0)
| ~ aElementOf0(xn,szNzAzT0) ),
inference(res,[status(thm),theory(equality)],[156,86]),
[iquote('0:Res:156.3,86.0')] ).
cnf(2368,plain,
( ~ sdtlseqdt0(szszuzczcdt0(xn),xm)
| ~ aElementOf0(szszuzczcdt0(xn),szNzAzT0)
| ~ aElementOf0(xm,szNzAzT0) ),
inference(res,[status(thm),theory(equality)],[156,96]),
[iquote('0:Res:156.3,96.0')] ).
cnf(2369,plain,
~ sdtlseqdt0(xm,xn),
inference(mrr,[status(thm)],[2367,32,28]),
[iquote('0:MRR:2367.1,2367.2,32.0,28.0')] ).
cnf(2370,plain,
( ~ sdtlseqdt0(szszuzczcdt0(xn),xm)
| ~ aElementOf0(szszuzczcdt0(xn),szNzAzT0) ),
inference(mrr,[status(thm)],[2368,32]),
[iquote('0:MRR:2368.2,32.0')] ).
cnf(2562,plain,
( ~ aElementOf0(xn,szNzAzT0)
| ~ aElementOf0(xm,szNzAzT0)
| ~ aElementOf0(szszuzczcdt0(xn),szNzAzT0)
| sdtlseqdt0(xm,xn) ),
inference(res,[status(thm),theory(equality)],[128,2370]),
[iquote('0:Res:128.3,2370.0')] ).
cnf(2563,plain,
~ aElementOf0(szszuzczcdt0(xn),szNzAzT0),
inference(mrr,[status(thm)],[2562,28,32,2369]),
[iquote('0:MRR:2562.0,2562.1,2562.3,28.0,32.0,2369.0')] ).
cnf(2564,plain,
~ aElementOf0(xn,szNzAzT0),
inference(res,[status(thm),theory(equality)],[80,2563]),
[iquote('0:Res:80.1,2563.0')] ).
cnf(2565,plain,
$false,
inference(mrr,[status(thm)],[2564,28]),
[iquote('0:MRR:2564.0,28.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11 % Problem : NUM627+1 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.12 % Command : run_spass %d %s
% 0.11/0.33 % Computer : n016.cluster.edu
% 0.11/0.33 % Model : x86_64 x86_64
% 0.11/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33 % Memory : 8042.1875MB
% 0.11/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33 % CPULimit : 300
% 0.11/0.33 % WCLimit : 600
% 0.11/0.33 % DateTime : Tue Jul 5 05:50:18 EDT 2022
% 0.11/0.33 % CPUTime :
% 0.83/1.04
% 0.83/1.04 SPASS V 3.9
% 0.83/1.04 SPASS beiseite: Proof found.
% 0.83/1.04 % SZS status Theorem
% 0.83/1.04 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.83/1.04 SPASS derived 1740 clauses, backtracked 238 clauses, performed 5 splits and kept 1172 clauses.
% 0.83/1.04 SPASS allocated 101132 KBytes.
% 0.83/1.04 SPASS spent 0:00:00.68 on the problem.
% 0.83/1.04 0:00:00.04 for the input.
% 0.83/1.04 0:00:00.26 for the FLOTTER CNF translation.
% 0.83/1.04 0:00:00.03 for inferences.
% 0.83/1.04 0:00:00.00 for the backtracking.
% 0.83/1.04 0:00:00.30 for the reduction.
% 0.83/1.04
% 0.83/1.04
% 0.83/1.04 Here is a proof with depth 3, length 15 :
% 0.83/1.04 % SZS output start Refutation
% See solution above
% 0.83/1.04 Formulae used in the proof : m__5309 m__5389 mSuccNum m__5461 m__5442 mLessTotal m__3754
% 0.83/1.04
%------------------------------------------------------------------------------