%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM632+3 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n007.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:56:52 PM UTC 2025 % Result : Theorem 5.75s 5.94s % Output : Proof 5.75s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.12/0.12 % Problem : NUM632+3 : TPTP v9.2.0. Released v4.0.0. % 0.12/0.14 % Command : duper %s % 0.13/0.35 % Computer : n007.cluster.edu % 0.13/0.35 % Model : x86_64 x86_64 % 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.35 % Memory : 8042.1875MB % 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.35 % CPULimit : 300 % 0.13/0.35 % WCLimit : 300 % 0.13/0.35 % DateTime : Fri Oct 3 06:51:23 EDT 2025 % 0.13/0.35 % CPUTime : % 5.75/5.94 SZS status Theorem for theBenchmark.p % 5.75/5.94 SZS output start Proof for theBenchmark.p % 5.75/5.94 Clause #110 (by assumption #[]): Eq (Eq (sdtlpdtrp0 xd xn) (szDzizrdt0 xd)) True % 5.75/5.94 Clause #112 (by assumption #[]): Eq (Eq (sdtlpdtrp0 xc xQ) (sdtlpdtrp0 xd xn)) True % 5.75/5.94 Clause #113 (by assumption #[]): Eq (Not (Eq (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd))) True % 5.75/5.94 Clause #319 (by clausification #[110]): Eq (sdtlpdtrp0 xd xn) (szDzizrdt0 xd) % 5.75/5.94 Clause #433 (by clausification #[113]): Eq (Eq (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd)) False % 5.75/5.94 Clause #434 (by clausification #[433]): Ne (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd) % 5.75/5.94 Clause #435 (by clausification #[112]): Eq (sdtlpdtrp0 xc xQ) (sdtlpdtrp0 xd xn) % 5.75/5.94 Clause #436 (by forward demodulation #[435, 319]): Eq (sdtlpdtrp0 xc xQ) (szDzizrdt0 xd) % 5.75/5.94 Clause #437 (by forward contextual literal cutting #[436, 434]): False % 5.75/5.94 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------