%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM635^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n022.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:56:53 PM UTC 2025 % Result : Theorem 4.91s 5.12s % Output : Proof 4.91s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.11 % Problem : NUM635^1 : TPTP v9.2.0. Released v3.7.0. % 0.07/0.13 % Command : duper %s % 0.12/0.33 % Computer : n022.cluster.edu % 0.12/0.33 % Model : x86_64 x86_64 % 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.33 % Memory : 8042.1875MB % 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.33 % CPULimit : 300 % 0.12/0.33 % WCLimit : 300 % 0.12/0.33 % DateTime : Fri Oct 3 08:39:23 EDT 2025 % 0.12/0.33 % CPUTime : % 4.91/5.12 SZS status Theorem for theBenchmark.p % 4.91/5.12 SZS output start Proof for theBenchmark.p % 4.91/5.12 Clause #0 (by assumption #[]): Eq (Ne x y) True % 4.91/5.12 Clause #1 (by assumption #[]): Eq (∀ (Xx Xy : nat), Eq (suc Xx) (suc Xy) → Eq Xx Xy) True % 4.91/5.12 Clause #2 (by assumption #[]): Eq (Not (Ne (suc x) (suc y))) True % 4.91/5.12 Clause #3 (by clausification #[0]): Ne x y % 4.91/5.12 Clause #4 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xy : nat), Eq (suc a) (suc Xy) → Eq a Xy) True % 4.91/5.12 Clause #5 (by clausification #[4]): ∀ (a a_1 : nat), Eq (Eq (suc a) (suc a_1) → Eq a a_1) True % 4.91/5.12 Clause #6 (by clausification #[5]): ∀ (a a_1 : nat), Or (Eq (Eq (suc a) (suc a_1)) False) (Eq (Eq a a_1) True) % 4.91/5.12 Clause #7 (by clausification #[6]): ∀ (a a_1 : nat), Or (Eq (Eq a a_1) True) (Ne (suc a) (suc a_1)) % 4.91/5.12 Clause #8 (by clausification #[7]): ∀ (a a_1 : nat), Or (Ne (suc a) (suc a_1)) (Eq a a_1) % 4.91/5.12 Clause #10 (by clausification #[2]): Eq (Ne (suc x) (suc y)) False % 4.91/5.12 Clause #11 (by clausification #[10]): Eq (suc x) (suc y) % 4.91/5.12 Clause #13 (by superposition #[11, 8]): ∀ (a : nat), Or (Ne (suc a) (suc y)) (Eq a x) % 4.91/5.12 Clause #14 (by equality resolution #[13]): Eq y x % 4.91/5.12 Clause #15 (by forward contextual literal cutting #[14, 3]): False % 4.91/5.12 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------