%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM635^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n151.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:13 EST 2018 % Result : Theorem 0.53s % Output : Proof 0.53s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM635^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.03 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.03/0.22 % Computer : n151.star.cs.uiowa.edu % 0.03/0.22 % Model : x86_64 x86_64 % 0.03/0.22 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.03/0.22 % Memory : 32218.625MB % 0.03/0.22 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.03/0.22 % CPULimit : 300 % 0.03/0.22 % DateTime : Fri Jan 5 11:14:15 CST 2018 % 0.03/0.22 % CPUTime : % 0.03/0.26 Python 2.7.13 % 0.53/0.89 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.53/0.89 FOF formula (<kernel.Constant object at 0x2b12528f3f38>, <kernel.Type object at 0x2b1251ea3e60>) of role type named nat_type % 0.53/0.89 Using role type % 0.53/0.89 Declaring nat:Type % 0.53/0.89 FOF formula (<kernel.Constant object at 0x2b12528f3b48>, <kernel.Constant object at 0x2b1251ea3f80>) of role type named x % 0.53/0.89 Using role type % 0.53/0.89 Declaring x:nat % 0.53/0.89 FOF formula (<kernel.Constant object at 0x2b12528f3f38>, <kernel.Constant object at 0x2b1251ea3c68>) of role type named y % 0.53/0.89 Using role type % 0.53/0.89 Declaring y:nat % 0.53/0.89 FOF formula (not (((eq nat) x) y)) of role axiom named n % 0.53/0.89 A new axiom: (not (((eq nat) x) y)) % 0.53/0.89 FOF formula (<kernel.Constant object at 0x2b12528f3f38>, <kernel.DependentProduct object at 0x2b12529190e0>) of role type named suc % 0.53/0.89 Using role type % 0.53/0.89 Declaring suc:(nat->nat) % 0.53/0.89 FOF formula (forall (Xx:nat) (Xy:nat), ((((eq nat) (suc Xx)) (suc Xy))->(((eq nat) Xx) Xy))) of role axiom named ax4 % 0.53/0.89 A new axiom: (forall (Xx:nat) (Xy:nat), ((((eq nat) (suc Xx)) (suc Xy))->(((eq nat) Xx) Xy))) % 0.53/0.89 FOF formula (not (((eq nat) (suc x)) (suc y))) of role conjecture named satz1 % 0.53/0.89 Conjecture to prove = (not (((eq nat) (suc x)) (suc y))):Prop % 0.53/0.89 We need to prove ['(not (((eq nat) (suc x)) (suc y)))'] % 0.53/0.89 Parameter nat:Type. % 0.53/0.89 Parameter x:nat. % 0.53/0.89 Parameter y:nat. % 0.53/0.89 Axiom n:(not (((eq nat) x) y)). % 0.53/0.89 Parameter suc:(nat->nat). % 0.53/0.89 Axiom ax4:(forall (Xx:nat) (Xy:nat), ((((eq nat) (suc Xx)) (suc Xy))->(((eq nat) Xx) Xy))). % 0.53/0.89 Trying to prove (not (((eq nat) (suc x)) (suc y))) % 0.53/0.89 Found x0:(((eq nat) (suc x)) (suc y)) % 0.53/0.89 Found x0 as proof of (((eq nat) (suc x)) (suc y)) % 0.53/0.89 Found (ax400 x0) as proof of (((eq nat) x) y) % 0.53/0.89 Found ((ax40 y) x0) as proof of (((eq nat) x) y) % 0.53/0.89 Found (((ax4 x) y) x0) as proof of (((eq nat) x) y) % 0.53/0.89 Found (((ax4 x) y) x0) as proof of (((eq nat) x) y) % 0.53/0.89 Found (n (((ax4 x) y) x0)) as proof of False % 0.53/0.89 Found (fun (x0:(((eq nat) (suc x)) (suc y)))=> (n (((ax4 x) y) x0))) as proof of False % 0.53/0.89 Found (fun (x0:(((eq nat) (suc x)) (suc y)))=> (n (((ax4 x) y) x0))) as proof of (not (((eq nat) (suc x)) (suc y))) % 0.53/0.89 Got proof (fun (x0:(((eq nat) (suc x)) (suc y)))=> (n (((ax4 x) y) x0))) % 0.53/0.89 Time elapsed = 0.181126s % 0.53/0.89 node=28 cost=70.000000 depth=7 % 0.53/0.89:::::::::::::::::::::: % 0.53/0.89 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.53/0.89 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.53/0.89 (fun (x0:(((eq nat) (suc x)) (suc y)))=> (n (((ax4 x) y) x0))) % 0.53/0.89 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------