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cocATP---0.2.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : NUM635^2 : TPTP v7.0.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n046.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:13 EST 2018

% Result   : Theorem 0.80s
% Output   : Proof 0.80s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.04  % Problem  : NUM635^2 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.04  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.24  % Computer : n046.star.cs.uiowa.edu
% 0.02/0.24  % Model    : x86_64 x86_64
% 0.02/0.24  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.24  % Memory   : 32218.625MB
% 0.02/0.24  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.06/0.24  % CPULimit : 300
% 0.06/0.24  % DateTime : Fri Jan  5 11:14:00 CST 2018
% 0.06/0.24  % CPUTime  : 
% 0.08/3.25  Python 2.7.13
% 0.80/16.74  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.80/16.74  FOF formula (<kernel.Constant object at 0x2af407bf0c68>, <kernel.Constant object at 0x2af407bf07a0>) of role type named one_type
% 0.80/16.74  Using role type
% 0.80/16.74  Declaring one:fofType
% 0.80/16.74  FOF formula (<kernel.Constant object at 0x2af3fff84cb0>, <kernel.DependentProduct object at 0x2af407bf0d40>) of role type named succ_type
% 0.80/16.74  Using role type
% 0.80/16.74  Declaring succ:(fofType->fofType)
% 0.80/16.74  FOF formula (forall (X:fofType), (not (((eq fofType) (succ X)) one))) of role axiom named one_is_first
% 0.80/16.74  A new axiom: (forall (X:fofType), (not (((eq fofType) (succ X)) one)))
% 0.80/16.74  FOF formula (forall (X:fofType) (Y:fofType), ((((eq fofType) (succ X)) (succ Y))->(((eq fofType) X) Y))) of role axiom named succ_injective
% 0.80/16.74  A new axiom: (forall (X:fofType) (Y:fofType), ((((eq fofType) (succ X)) (succ Y))->(((eq fofType) X) Y)))
% 0.80/16.74  FOF formula (forall (M:(fofType->Prop)), (((and (M one)) (forall (X:fofType), ((M X)->(M (succ X)))))->(forall (Y:fofType), (M Y)))) of role axiom named induction
% 0.80/16.74  A new axiom: (forall (M:(fofType->Prop)), (((and (M one)) (forall (X:fofType), ((M X)->(M (succ X)))))->(forall (Y:fofType), (M Y))))
% 0.80/16.74  FOF formula (forall (X:fofType) (Y:fofType), ((not (((eq fofType) X) Y))->(not (((eq fofType) (succ X)) (succ Y))))) of role conjecture named satz1
% 0.80/16.74  Conjecture to prove = (forall (X:fofType) (Y:fofType), ((not (((eq fofType) X) Y))->(not (((eq fofType) (succ X)) (succ Y))))):Prop
% 0.80/16.74  We need to prove ['(forall (X:fofType) (Y:fofType), ((not (((eq fofType) X) Y))->(not (((eq fofType) (succ X)) (succ Y)))))']
% 0.80/16.74  Parameter fofType:Type.
% 0.80/16.74  Parameter one:fofType.
% 0.80/16.74  Parameter succ:(fofType->fofType).
% 0.80/16.74  Axiom one_is_first:(forall (X:fofType), (not (((eq fofType) (succ X)) one))).
% 0.80/16.74  Axiom succ_injective:(forall (X:fofType) (Y:fofType), ((((eq fofType) (succ X)) (succ Y))->(((eq fofType) X) Y))).
% 0.80/16.74  Axiom induction:(forall (M:(fofType->Prop)), (((and (M one)) (forall (X:fofType), ((M X)->(M (succ X)))))->(forall (Y:fofType), (M Y)))).
% 0.80/16.74  Trying to prove (forall (X:fofType) (Y:fofType), ((not (((eq fofType) X) Y))->(not (((eq fofType) (succ X)) (succ Y)))))
% 0.80/16.74  Found x0:(((eq fofType) (succ X)) (succ Y))
% 0.80/16.74  Found x0 as proof of (((eq fofType) (succ X)) (succ Y))
% 0.80/16.74  Found (succ_injective00 x0) as proof of (((eq fofType) X) Y)
% 0.80/16.74  Found ((succ_injective0 Y) x0) as proof of (((eq fofType) X) Y)
% 0.80/16.74  Found (((succ_injective X) Y) x0) as proof of (((eq fofType) X) Y)
% 0.80/16.74  Found (((succ_injective X) Y) x0) as proof of (((eq fofType) X) Y)
% 0.80/16.74  Found (x (((succ_injective X) Y) x0)) as proof of False
% 0.80/16.74  Found (fun (x0:(((eq fofType) (succ X)) (succ Y)))=> (x (((succ_injective X) Y) x0))) as proof of False
% 0.80/16.74  Found (fun (x:(not (((eq fofType) X) Y))) (x0:(((eq fofType) (succ X)) (succ Y)))=> (x (((succ_injective X) Y) x0))) as proof of (not (((eq fofType) (succ X)) (succ Y)))
% 0.80/16.74  Found (fun (Y:fofType) (x:(not (((eq fofType) X) Y))) (x0:(((eq fofType) (succ X)) (succ Y)))=> (x (((succ_injective X) Y) x0))) as proof of ((not (((eq fofType) X) Y))->(not (((eq fofType) (succ X)) (succ Y))))
% 0.80/16.74  Found (fun (X:fofType) (Y:fofType) (x:(not (((eq fofType) X) Y))) (x0:(((eq fofType) (succ X)) (succ Y)))=> (x (((succ_injective X) Y) x0))) as proof of (forall (Y:fofType), ((not (((eq fofType) X) Y))->(not (((eq fofType) (succ X)) (succ Y)))))
% 0.80/16.74  Found (fun (X:fofType) (Y:fofType) (x:(not (((eq fofType) X) Y))) (x0:(((eq fofType) (succ X)) (succ Y)))=> (x (((succ_injective X) Y) x0))) as proof of (forall (X:fofType) (Y:fofType), ((not (((eq fofType) X) Y))->(not (((eq fofType) (succ X)) (succ Y)))))
% 0.80/16.74  Got proof (fun (X:fofType) (Y:fofType) (x:(not (((eq fofType) X) Y))) (x0:(((eq fofType) (succ X)) (succ Y)))=> (x (((succ_injective X) Y) x0)))
% 0.80/16.74  Time elapsed = 0.476822s
% 0.80/16.74  node=93 cost=112.000000 depth=10
% 0.80/16.74::::::::::::::::::::::
% 0.80/16.74  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.80/16.74  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.80/16.74  (fun (X:fofType) (Y:fofType) (x:(not (((eq fofType) X) Y))) (x0:(((eq fofType) (succ X)) (succ Y)))=> (x (((succ_injective X) Y) x0)))
% 0.80/16.74  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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