%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM640^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n183.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:15 EST 2018 % Result : Theorem 0.52s % Output : Proof 0.52s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM640^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.02/0.23 % Computer : n183.star.cs.uiowa.edu % 0.02/0.23 % Model : x86_64 x86_64 % 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.23 % Memory : 32218.625MB % 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.23 % CPULimit : 300 % 0.02/0.23 % DateTime : Fri Jan 5 11:22:11 CST 2018 % 0.02/0.23 % CPUTime : % 0.08/0.26 Python 2.7.13 % 0.52/0.86 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.52/0.86 FOF formula (<kernel.Constant object at 0x2b6a4a1665a8>, <kernel.Type object at 0x2b6a4a160830>) of role type named nat_type % 0.52/0.86 Using role type % 0.52/0.86 Declaring nat:Type % 0.52/0.86 FOF formula (<kernel.Constant object at 0x2b6a496e3830>, <kernel.Constant object at 0x2b6a4a1605a8>) of role type named x % 0.52/0.86 Using role type % 0.52/0.86 Declaring x:nat % 0.52/0.86 FOF formula (<kernel.Constant object at 0x2b6a4a1663f8>, <kernel.Constant object at 0x2b6a4a160b48>) of role type named y % 0.52/0.86 Using role type % 0.52/0.86 Declaring y:nat % 0.52/0.86 FOF formula (<kernel.Constant object at 0x2b6a4a1665a8>, <kernel.DependentProduct object at 0x2b6a4a160320>) of role type named suc % 0.52/0.86 Using role type % 0.52/0.86 Declaring suc:(nat->nat) % 0.52/0.86 FOF formula (<kernel.Constant object at 0x2b6a4a1665a8>, <kernel.DependentProduct object at 0x2b6a4a160b00>) of role type named pl % 0.52/0.86 Using role type % 0.52/0.86 Declaring pl:(nat->(nat->nat)) % 0.52/0.86 FOF formula (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) (suc Xy))) (suc ((pl Xx) Xy)))) of role axiom named satz4b % 0.52/0.86 A new axiom: (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) (suc Xy))) (suc ((pl Xx) Xy)))) % 0.52/0.86 FOF formula (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))) of role conjecture named satz4f % 0.52/0.86 Conjecture to prove = (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))):Prop % 0.52/0.86 We need to prove ['(((eq nat) (suc ((pl x) y))) ((pl x) (suc y)))'] % 0.52/0.86 Parameter nat:Type. % 0.52/0.86 Parameter x:nat. % 0.52/0.86 Parameter y:nat. % 0.52/0.86 Parameter suc:(nat->nat). % 0.52/0.86 Parameter pl:(nat->(nat->nat)). % 0.52/0.86 Axiom satz4b:(forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) (suc Xy))) (suc ((pl Xx) Xy)))). % 0.52/0.86 Trying to prove (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))) % 0.52/0.86 Found eq_ref00:=(eq_ref0 ((pl x) (suc y))):(((eq nat) ((pl x) (suc y))) ((pl x) (suc y))) % 0.52/0.86 Found (eq_ref0 ((pl x) (suc y))) as proof of (((eq nat) ((pl x) (suc y))) ((pl x) (suc y))) % 0.52/0.86 Found ((eq_ref nat) ((pl x) (suc y))) as proof of (((eq nat) ((pl x) (suc y))) ((pl x) (suc y))) % 0.52/0.86 Found ((eq_ref nat) ((pl x) (suc y))) as proof of (((eq nat) ((pl x) (suc y))) ((pl x) (suc y))) % 0.52/0.86 Found (satz4b000 ((eq_ref nat) ((pl x) (suc y)))) as proof of (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))) % 0.52/0.86 Found ((satz4b00 (fun (x1:nat)=> (((eq nat) x1) ((pl x) (suc y))))) ((eq_ref nat) ((pl x) (suc y)))) as proof of (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))) % 0.52/0.86 Found (((satz4b0 y) (fun (x1:nat)=> (((eq nat) x1) ((pl x) (suc y))))) ((eq_ref nat) ((pl x) (suc y)))) as proof of (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))) % 0.52/0.86 Found ((((satz4b x) y) (fun (x1:nat)=> (((eq nat) x1) ((pl x) (suc y))))) ((eq_ref nat) ((pl x) (suc y)))) as proof of (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))) % 0.52/0.86 Found ((((satz4b x) y) (fun (x1:nat)=> (((eq nat) x1) ((pl x) (suc y))))) ((eq_ref nat) ((pl x) (suc y)))) as proof of (((eq nat) (suc ((pl x) y))) ((pl x) (suc y))) % 0.52/0.86 Got proof ((((satz4b x) y) (fun (x1:nat)=> (((eq nat) x1) ((pl x) (suc y))))) ((eq_ref nat) ((pl x) (suc y)))) % 0.52/0.86 Time elapsed = 0.170079s % 0.52/0.86 node=27 cost=-103.000000 depth=7 % 0.52/0.86:::::::::::::::::::::: % 0.52/0.86 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.52/0.86 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.52/0.86 ((((satz4b x) y) (fun (x1:nat)=> (((eq nat) x1) ((pl x) (suc y))))) ((eq_ref nat) ((pl x) (suc y)))) % 0.52/0.86 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------