%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM666^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n186.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:22 EST 2018 % Result : Theorem 0.35s % Output : Proof 0.35s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM666^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.03/0.24 % Computer : n186.star.cs.uiowa.edu % 0.03/0.24 % Model : x86_64 x86_64 % 0.03/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.03/0.24 % Memory : 32218.625MB % 0.03/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.03/0.24 % CPULimit : 300 % 0.03/0.24 % DateTime : Fri Jan 5 12:13:07 CST 2018 % 0.03/0.24 % CPUTime : % 0.03/0.25 Python 2.7.13 % 0.35/0.60 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89ea8>, <kernel.Type object at 0x2ac0f8a89b90>) of role type named nat_type % 0.35/0.60 Using role type % 0.35/0.60 Declaring nat:Type % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8730998>, <kernel.Constant object at 0x2ac0f8a89f80>) of role type named x % 0.35/0.60 Using role type % 0.35/0.60 Declaring x:nat % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8730998>, <kernel.Constant object at 0x2ac0f8a89f80>) of role type named y % 0.35/0.60 Using role type % 0.35/0.60 Declaring y:nat % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89ea8>, <kernel.Constant object at 0x2ac0f8a89f80>) of role type named z % 0.35/0.60 Using role type % 0.35/0.60 Declaring z:nat % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89f38>, <kernel.DependentProduct object at 0x2ac0f8a89d40>) of role type named some % 0.35/0.60 Using role type % 0.35/0.60 Declaring some:((nat->Prop)->Prop) % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89b48>, <kernel.DependentProduct object at 0x2ac0f8a89b00>) of role type named diffprop % 0.35/0.60 Using role type % 0.35/0.60 Declaring diffprop:(nat->(nat->(nat->Prop))) % 0.35/0.60 FOF formula (some (fun (Xu:nat)=> (((diffprop x) y) Xu))) of role axiom named m % 0.35/0.60 A new axiom: (some (fun (Xu:nat)=> (((diffprop x) y) Xu))) % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89b48>, <kernel.DependentProduct object at 0x2ac0f8a89b00>) of role type named moreis % 0.35/0.60 Using role type % 0.35/0.60 Declaring moreis:(nat->(nat->Prop)) % 0.35/0.60 FOF formula ((moreis y) z) of role axiom named n % 0.35/0.60 A new axiom: ((moreis y) z) % 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89830>, <kernel.DependentProduct object at 0x2ac0f8a893f8>) of role type named lessis % 0.35/0.60 Using role type % 0.35/0.60 Declaring lessis:(nat->(nat->Prop)) % 0.35/0.60 FOF formula (forall (Xx:nat) (Xy:nat) (Xz:nat), (((lessis Xx) Xy)->((some (fun (Xv:nat)=> (((diffprop Xz) Xy) Xv)))->(some (fun (Xv:nat)=> (((diffprop Xz) Xx) Xv)))))) of role axiom named satz16a % 0.35/0.60 A new axiom: (forall (Xx:nat) (Xy:nat) (Xz:nat), (((lessis Xx) Xy)->((some (fun (Xv:nat)=> (((diffprop Xz) Xy) Xv)))->(some (fun (Xv:nat)=> (((diffprop Xz) Xx) Xv)))))) % 0.35/0.60 FOF formula (forall (Xx:nat) (Xy:nat), (((moreis Xx) Xy)->((lessis Xy) Xx))) of role axiom named satz13 % 0.35/0.60 A new axiom: (forall (Xx:nat) (Xy:nat), (((moreis Xx) Xy)->((lessis Xy) Xx))) % 0.35/0.60 FOF formula (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) of role conjecture named satz16d % 0.35/0.60 Conjecture to prove = (some (fun (Xu:nat)=> (((diffprop x) z) Xu))):Prop % 0.35/0.60 We need to prove ['(some (fun (Xu:nat)=> (((diffprop x) z) Xu)))'] % 0.35/0.60 Parameter nat:Type. % 0.35/0.60 Parameter x:nat. % 0.35/0.60 Parameter y:nat. % 0.35/0.60 Parameter z:nat. % 0.35/0.60 Parameter some:((nat->Prop)->Prop). % 0.35/0.60 Parameter diffprop:(nat->(nat->(nat->Prop))). % 0.35/0.60 Axiom m:(some (fun (Xu:nat)=> (((diffprop x) y) Xu))). % 0.35/0.60 Parameter moreis:(nat->(nat->Prop)). % 0.35/0.60 Axiom n:((moreis y) z). % 0.35/0.60 Parameter lessis:(nat->(nat->Prop)). % 0.35/0.60 Axiom satz16a:(forall (Xx:nat) (Xy:nat) (Xz:nat), (((lessis Xx) Xy)->((some (fun (Xv:nat)=> (((diffprop Xz) Xy) Xv)))->(some (fun (Xv:nat)=> (((diffprop Xz) Xx) Xv)))))). % 0.35/0.60 Axiom satz13:(forall (Xx:nat) (Xy:nat), (((moreis Xx) Xy)->((lessis Xy) Xx))). % 0.35/0.60 Trying to prove (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) % 0.35/0.60 Found m:(some (fun (Xu:nat)=> (((diffprop x) y) Xu))) % 0.35/0.60 Found m as proof of (some (fun (Xv:nat)=> (((diffprop x) y) Xv))) % 0.35/0.60 Found n:((moreis y) z) % 0.35/0.60 Found n as proof of ((moreis y) z) % 0.35/0.60 Found (satz1300 n) as proof of ((lessis z) y) % 0.35/0.60 Found ((satz130 z) n) as proof of ((lessis z) y) % 0.35/0.60 Found (((satz13 y) z) n) as proof of ((lessis z) y) % 0.35/0.60 Found (((satz13 y) z) n) as proof of ((lessis z) y) % 0.35/0.60 Found ((satz16a000 (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) % 0.35/0.60 Found (((satz16a00 y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) % 0.35/0.60 Found ((((fun (Xy:nat)=> ((satz16a0 Xy) x)) y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) % 0.35/0.60 Found ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) % 0.35/0.60 Found ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) % 0.35/0.60 Got proof ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m) % 0.35/0.61 Time elapsed = 0.064590s % 0.35/0.61 node=17 cost=387.000000 depth=9 % 0.35/0.61:::::::::::::::::::::: % 0.35/0.61 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.35/0.61 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.35/0.61 ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m) % 0.35/0.61 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------