%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM669^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n031.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:00 PM UTC 2025 % Result : Theorem 3.78s 3.95s % Output : Proof 3.78s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.13/0.13 % Problem : NUM669^1 : TPTP v9.2.0. Released v3.7.0. % 0.13/0.15 % Command : duper %s % 0.14/0.36 % Computer : n031.cluster.edu % 0.14/0.36 % Model : x86_64 x86_64 % 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.36 % Memory : 8042.1875MB % 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.36 % CPULimit : 300 % 0.14/0.36 % WCLimit : 300 % 0.14/0.36 % DateTime : Fri Oct 3 08:09:23 EDT 2025 % 0.14/0.36 % CPUTime : % 3.78/3.95 SZS status Theorem for theBenchmark.p % 3.78/3.95 SZS output start Proof for theBenchmark.p % 3.78/3.95 Clause #0 (by assumption #[]): Eq (∀ (Xx Xy : nat), more (pl Xx Xy) Xx) True % 3.78/3.95 Clause #1 (by assumption #[]): Eq (∀ (Xx : nat), Eq (pl Xx n_1) (suc Xx)) True % 3.78/3.95 Clause #2 (by assumption #[]): Eq (Not (more (suc x) x)) True % 3.78/3.95 Clause #3 (by clausification #[2]): Eq (more (suc x) x) False % 3.78/3.95 Clause #4 (by clausification #[0]): ∀ (a : nat), Eq (∀ (Xy : nat), more (pl a Xy) a) True % 3.78/3.95 Clause #5 (by clausification #[4]): ∀ (a a_1 : nat), Eq (more (pl a a_1) a) True % 3.78/3.95 Clause #6 (by clausification #[1]): ∀ (a : nat), Eq (Eq (pl a n_1) (suc a)) True % 3.78/3.95 Clause #7 (by clausification #[6]): ∀ (a : nat), Eq (pl a n_1) (suc a) % 3.78/3.95 Clause #8 (by superposition #[7, 5]): ∀ (a : nat), Eq (more (suc a) a) True % 3.78/3.95 Clause #9 (by superposition #[8, 3]): Eq True False % 3.78/3.95 Clause #10 (by clausification #[9]): False % 3.78/3.95 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------