%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM669^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n060.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:22 EST 2018 % Result : Theorem 0.09s % Output : Proof 0.09s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM669^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.03 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.03/0.23 % Computer : n060.star.cs.uiowa.edu % 0.03/0.23 % Model : x86_64 x86_64 % 0.03/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.03/0.23 % Memory : 32218.625MB % 0.03/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.03/0.23 % CPULimit : 300 % 0.03/0.23 % DateTime : Fri Jan 5 12:13:49 CST 2018 % 0.03/0.23 % CPUTime : % 0.03/0.25 Python 2.7.13 % 0.09/0.56 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.09/0.56 FOF formula (<kernel.Constant object at 0x2ab07800d3f8>, <kernel.Type object at 0x2ab07800de60>) of role type named nat_type % 0.09/0.56 Using role type % 0.09/0.56 Declaring nat:Type % 0.09/0.56 FOF formula (<kernel.Constant object at 0x2ab078704ea8>, <kernel.Constant object at 0x2ab07800df80>) of role type named x % 0.09/0.56 Using role type % 0.09/0.56 Declaring x:nat % 0.09/0.56 FOF formula (<kernel.Constant object at 0x2ab07800d3b0>, <kernel.DependentProduct object at 0x2ab07800dcb0>) of role type named more % 0.09/0.56 Using role type % 0.09/0.56 Declaring more:(nat->(nat->Prop)) % 0.09/0.56 FOF formula (<kernel.Constant object at 0x2ab07800d5f0>, <kernel.DependentProduct object at 0x2ab07800da28>) of role type named suc % 0.09/0.56 Using role type % 0.09/0.56 Declaring suc:(nat->nat) % 0.09/0.56 FOF formula (<kernel.Constant object at 0x2ab07800df80>, <kernel.DependentProduct object at 0x2ab07800dfc8>) of role type named pl % 0.09/0.56 Using role type % 0.09/0.56 Declaring pl:(nat->(nat->nat)) % 0.09/0.56 FOF formula (<kernel.Constant object at 0x2ab07800dcb0>, <kernel.Constant object at 0x2ab07800dfc8>) of role type named n_1 % 0.09/0.56 Using role type % 0.09/0.56 Declaring n_1:nat % 0.09/0.56 FOF formula (forall (Xx:nat) (Xy:nat), ((more ((pl Xx) Xy)) Xx)) of role axiom named satz18 % 0.09/0.56 A new axiom: (forall (Xx:nat) (Xy:nat), ((more ((pl Xx) Xy)) Xx)) % 0.09/0.56 FOF formula (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))) of role axiom named satz4a % 0.09/0.56 A new axiom: (forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))) % 0.09/0.56 FOF formula ((more (suc x)) x) of role conjecture named satz18b % 0.09/0.56 Conjecture to prove = ((more (suc x)) x):Prop % 0.09/0.56 We need to prove ['((more (suc x)) x)'] % 0.09/0.56 Parameter nat:Type. % 0.09/0.56 Parameter x:nat. % 0.09/0.56 Parameter more:(nat->(nat->Prop)). % 0.09/0.56 Parameter suc:(nat->nat). % 0.09/0.56 Parameter pl:(nat->(nat->nat)). % 0.09/0.56 Parameter n_1:nat. % 0.09/0.56 Axiom satz18:(forall (Xx:nat) (Xy:nat), ((more ((pl Xx) Xy)) Xx)). % 0.09/0.56 Axiom satz4a:(forall (Xx:nat), (((eq nat) ((pl Xx) n_1)) (suc Xx))). % 0.09/0.56 Trying to prove ((more (suc x)) x) % 0.09/0.56 Found satz1800:=(satz180 n_1):((more ((pl x) n_1)) x) % 0.09/0.56 Found (satz180 n_1) as proof of ((more ((pl x) n_1)) x) % 0.09/0.56 Found ((satz18 x) n_1) as proof of ((more ((pl x) n_1)) x) % 0.09/0.56 Found ((satz18 x) n_1) as proof of ((more ((pl x) n_1)) x) % 0.09/0.56 Found (satz4a00 ((satz18 x) n_1)) as proof of ((more (suc x)) x) % 0.09/0.56 Found ((satz4a0 (fun (x1:nat)=> ((more x1) x))) ((satz18 x) n_1)) as proof of ((more (suc x)) x) % 0.09/0.56 Found (((satz4a x) (fun (x1:nat)=> ((more x1) x))) ((satz18 x) n_1)) as proof of ((more (suc x)) x) % 0.09/0.56 Found (((satz4a x) (fun (x1:nat)=> ((more x1) x))) ((satz18 x) n_1)) as proof of ((more (suc x)) x) % 0.09/0.56 Got proof (((satz4a x) (fun (x1:nat)=> ((more x1) x))) ((satz18 x) n_1)) % 0.09/0.56 Time elapsed = 0.041541s % 0.09/0.56 node=11 cost=-136.000000 depth=6 % 0.09/0.56:::::::::::::::::::::: % 0.09/0.56 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.09/0.56 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.09/0.56 (((satz4a x) (fun (x1:nat)=> ((more x1) x))) ((satz18 x) n_1)) % 0.09/0.56 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------