%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM672^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n027.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:01 PM UTC 2025 % Result : Theorem 3.52s 3.71s % Output : Proof 3.52s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.11/0.12 % Problem : NUM672^1 : TPTP v9.2.0. Released v3.7.0. % 0.11/0.13 % Command : duper %s % 0.13/0.34 % Computer : n027.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 08:37:08 EDT 2025 % 0.13/0.34 % CPUTime : % 3.52/3.71 SZS status Theorem for theBenchmark.p % 3.52/3.71 SZS output start Proof for theBenchmark.p % 3.52/3.71 Clause #0 (by assumption #[]): Eq (less x y) True % 3.52/3.71 Clause #1 (by assumption #[]): Eq (∀ (Xx Xy : nat), more Xx Xy → less Xy Xx) True % 3.52/3.71 Clause #2 (by assumption #[]): Eq (∀ (Xx Xy Xz : nat), more Xx Xy → more (pl Xx Xz) (pl Xy Xz)) True % 3.52/3.71 Clause #3 (by assumption #[]): Eq (∀ (Xx Xy : nat), less Xx Xy → more Xy Xx) True % 3.52/3.71 Clause #4 (by assumption #[]): Eq (Not (less (pl x z) (pl y z))) True % 3.52/3.71 Clause #5 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy : nat), less a Xy → more Xy a) True % 3.52/3.71 Clause #6 (by clausification #[5]): ∀ (a a_1 : nat), Eq (less a a_1 → more a_1 a) True % 3.52/3.71 Clause #7 (by clausification #[6]): ∀ (a a_1 : nat), Or (Eq (less a a_1) False) (Eq (more a_1 a) True) % 3.52/3.71 Clause #8 (by superposition #[7, 0]): Or (Eq (more y x) True) (Eq False True) % 3.52/3.71 Clause #9 (by clausification #[8]): Eq (more y x) True % 3.52/3.71 Clause #10 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xy : nat), more a Xy → less Xy a) True % 3.52/3.71 Clause #11 (by clausification #[10]): ∀ (a a_1 : nat), Eq (more a a_1 → less a_1 a) True % 3.52/3.71 Clause #12 (by clausification #[11]): ∀ (a a_1 : nat), Or (Eq (more a a_1) False) (Eq (less a_1 a) True) % 3.52/3.71 Clause #14 (by clausification #[2]): ∀ (a : nat), Eq (∀ (Xy Xz : nat), more a Xy → more (pl a Xz) (pl Xy Xz)) True % 3.52/3.71 Clause #15 (by clausification #[14]): ∀ (a a_1 : nat), Eq (∀ (Xz : nat), more a a_1 → more (pl a Xz) (pl a_1 Xz)) True % 3.52/3.71 Clause #16 (by clausification #[15]): ∀ (a a_1 a_2 : nat), Eq (more a a_1 → more (pl a a_2) (pl a_1 a_2)) True % 3.52/3.71 Clause #17 (by clausification #[16]): ∀ (a a_1 a_2 : nat), Or (Eq (more a a_1) False) (Eq (more (pl a a_2) (pl a_1 a_2)) True) % 3.52/3.71 Clause #18 (by superposition #[17, 9]): ∀ (a : nat), Or (Eq (more (pl y a) (pl x a)) True) (Eq False True) % 3.52/3.71 Clause #19 (by clausification #[4]): Eq (less (pl x z) (pl y z)) False % 3.52/3.71 Clause #20 (by clausification #[18]): ∀ (a : nat), Eq (more (pl y a) (pl x a)) True % 3.52/3.71 Clause #21 (by superposition #[20, 12]): ∀ (a : nat), Or (Eq True False) (Eq (less (pl x a) (pl y a)) True) % 3.52/3.71 Clause #23 (by clausification #[21]): ∀ (a : nat), Eq (less (pl x a) (pl y a)) True % 3.52/3.71 Clause #24 (by superposition #[23, 19]): Eq True False % 3.52/3.71 Clause #26 (by clausification #[24]): False % 3.52/3.71 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------