↑ Up

cocATP---0.2.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : NUM672^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n090.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:23 EST 2018

% Result   : Theorem 0.40s
% Output   : Proof 0.40s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.04  % Problem  : NUM672^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.04  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.24  % Computer : n090.star.cs.uiowa.edu
% 0.02/0.24  % Model    : x86_64 x86_64
% 0.02/0.24  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.24  % Memory   : 32218.625MB
% 0.02/0.24  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.24  % CPULimit : 300
% 0.02/0.24  % DateTime : Fri Jan  5 12:30:04 CST 2018
% 0.02/0.24  % CPUTime  : 
% 0.07/0.25  Python 2.7.13
% 0.40/0.60  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.40/0.60  FOF formula (<kernel.Constant object at 0x2b086cb4fb48>, <kernel.Type object at 0x2b086cb4b248>) of role type named nat_type
% 0.40/0.60  Using role type
% 0.40/0.60  Declaring nat:Type
% 0.40/0.60  FOF formula (<kernel.Constant object at 0x2b086cc2b5f0>, <kernel.Constant object at 0x2b086cb4b440>) of role type named x
% 0.40/0.60  Using role type
% 0.40/0.60  Declaring x:nat
% 0.40/0.60  FOF formula (<kernel.Constant object at 0x2b086cb4f248>, <kernel.Constant object at 0x2b086cb4b710>) of role type named y
% 0.40/0.60  Using role type
% 0.40/0.60  Declaring y:nat
% 0.40/0.60  FOF formula (<kernel.Constant object at 0x2b086cb4fb48>, <kernel.Constant object at 0x2b086cb4b710>) of role type named z
% 0.40/0.60  Using role type
% 0.40/0.60  Declaring z:nat
% 0.40/0.60  FOF formula (<kernel.Constant object at 0x2b086cb4fb48>, <kernel.DependentProduct object at 0x2b086cb4b7e8>) of role type named less
% 0.40/0.60  Using role type
% 0.40/0.60  Declaring less:(nat->(nat->Prop))
% 0.40/0.60  FOF formula ((less x) y) of role axiom named l
% 0.40/0.60  A new axiom: ((less x) y)
% 0.40/0.60  FOF formula (<kernel.Constant object at 0x2b086cb4b710>, <kernel.DependentProduct object at 0x2b086cb4b758>) of role type named pl
% 0.40/0.60  Using role type
% 0.40/0.60  Declaring pl:(nat->(nat->nat))
% 0.40/0.60  FOF formula (<kernel.Constant object at 0x2b086cb4bd40>, <kernel.DependentProduct object at 0x2b086cb4b830>) of role type named more
% 0.40/0.60  Using role type
% 0.40/0.60  Declaring more:(nat->(nat->Prop))
% 0.40/0.60  FOF formula (forall (Xx:nat) (Xy:nat), (((more Xx) Xy)->((less Xy) Xx))) of role axiom named satz11
% 0.40/0.60  A new axiom: (forall (Xx:nat) (Xy:nat), (((more Xx) Xy)->((less Xy) Xx)))
% 0.40/0.60  FOF formula (forall (Xx:nat) (Xy:nat) (Xz:nat), (((more Xx) Xy)->((more ((pl Xx) Xz)) ((pl Xy) Xz)))) of role axiom named satz19a
% 0.40/0.60  A new axiom: (forall (Xx:nat) (Xy:nat) (Xz:nat), (((more Xx) Xy)->((more ((pl Xx) Xz)) ((pl Xy) Xz))))
% 0.40/0.60  FOF formula (forall (Xx:nat) (Xy:nat), (((less Xx) Xy)->((more Xy) Xx))) of role axiom named satz12
% 0.40/0.60  A new axiom: (forall (Xx:nat) (Xy:nat), (((less Xx) Xy)->((more Xy) Xx)))
% 0.40/0.60  FOF formula ((less ((pl x) z)) ((pl y) z)) of role conjecture named satz19c
% 0.40/0.60  Conjecture to prove = ((less ((pl x) z)) ((pl y) z)):Prop
% 0.40/0.60  We need to prove ['((less ((pl x) z)) ((pl y) z))']
% 0.40/0.60  Parameter nat:Type.
% 0.40/0.60  Parameter x:nat.
% 0.40/0.60  Parameter y:nat.
% 0.40/0.60  Parameter z:nat.
% 0.40/0.60  Parameter less:(nat->(nat->Prop)).
% 0.40/0.60  Axiom l:((less x) y).
% 0.40/0.60  Parameter pl:(nat->(nat->nat)).
% 0.40/0.60  Parameter more:(nat->(nat->Prop)).
% 0.40/0.60  Axiom satz11:(forall (Xx:nat) (Xy:nat), (((more Xx) Xy)->((less Xy) Xx))).
% 0.40/0.60  Axiom satz19a:(forall (Xx:nat) (Xy:nat) (Xz:nat), (((more Xx) Xy)->((more ((pl Xx) Xz)) ((pl Xy) Xz)))).
% 0.40/0.60  Axiom satz12:(forall (Xx:nat) (Xy:nat), (((less Xx) Xy)->((more Xy) Xx))).
% 0.40/0.60  Trying to prove ((less ((pl x) z)) ((pl y) z))
% 0.40/0.60  Found satz12000:=(satz1200 l):((more y) x)
% 0.40/0.60  Found (satz1200 l) as proof of ((more y) x)
% 0.40/0.60  Found ((satz120 y) l) as proof of ((more y) x)
% 0.40/0.60  Found (((satz12 x) y) l) as proof of ((more y) x)
% 0.40/0.60  Found (((satz12 x) y) l) as proof of ((more y) x)
% 0.40/0.60  Found (satz19a000 (((satz12 x) y) l)) as proof of ((more ((pl y) z)) ((pl x) z))
% 0.40/0.60  Found ((satz19a00 z) (((satz12 x) y) l)) as proof of ((more ((pl y) z)) ((pl x) z))
% 0.40/0.60  Found (((satz19a0 x) z) (((satz12 x) y) l)) as proof of ((more ((pl y) z)) ((pl x) z))
% 0.40/0.60  Found ((((satz19a y) x) z) (((satz12 x) y) l)) as proof of ((more ((pl y) z)) ((pl x) z))
% 0.40/0.60  Found ((((satz19a y) x) z) (((satz12 x) y) l)) as proof of ((more ((pl y) z)) ((pl x) z))
% 0.40/0.60  Found (satz1100 ((((satz19a y) x) z) (((satz12 x) y) l))) as proof of ((less ((pl x) z)) ((pl y) z))
% 0.40/0.60  Found ((satz110 ((pl x) z)) ((((satz19a y) x) z) (((satz12 x) y) l))) as proof of ((less ((pl x) z)) ((pl y) z))
% 0.40/0.60  Found (((satz11 ((pl y) z)) ((pl x) z)) ((((satz19a y) x) z) (((satz12 x) y) l))) as proof of ((less ((pl x) z)) ((pl y) z))
% 0.40/0.60  Found (((satz11 ((pl y) z)) ((pl x) z)) ((((satz19a y) x) z) (((satz12 x) y) l))) as proof of ((less ((pl x) z)) ((pl y) z))
% 0.40/0.60  Got proof (((satz11 ((pl y) z)) ((pl x) z)) ((((satz19a y) x) z) (((satz12 x) y) l)))
% 0.40/0.60  Time elapsed = 0.061792s
% 0.40/0.60  node=14 cost=193.000000 depth=12
% 0.40/0.60::::::::::::::::::::::
% 0.40/0.60  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.40/0.60  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.40/0.60  (((satz11 ((pl y) z)) ((pl x) z)) ((((satz19a y) x) z) (((satz12 x) y) l)))
% 0.40/0.60  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
%------------------------------------------------------------------------------