%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM673^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n067.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:24 EST 2018 % Result : Theorem 0.90s % Output : Proof 0.90s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.04 % Problem : NUM673^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.05 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.03/0.25 % Computer : n067.star.cs.uiowa.edu % 0.03/0.25 % Model : x86_64 x86_64 % 0.03/0.25 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.03/0.25 % Memory : 32218.625MB % 0.03/0.25 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.03/0.25 % CPULimit : 300 % 0.03/0.25 % DateTime : Fri Jan 5 12:29:49 CST 2018 % 0.03/0.25 % CPUTime : % 0.03/0.28 Python 2.7.13 % 0.90/1.30 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.90/1.30 FOF formula (<kernel.Constant object at 0x2b65799e82d8>, <kernel.Type object at 0x2b65799e8f38>) of role type named nat_type % 0.90/1.30 Using role type % 0.90/1.30 Declaring nat:Type % 0.90/1.30 FOF formula (<kernel.Constant object at 0x2b65799e8ab8>, <kernel.Constant object at 0x2b65799e8518>) of role type named x % 0.90/1.30 Using role type % 0.90/1.30 Declaring x:nat % 0.90/1.30 FOF formula (<kernel.Constant object at 0x2b657a438f80>, <kernel.Constant object at 0x2b65799e8518>) of role type named y % 0.90/1.30 Using role type % 0.90/1.30 Declaring y:nat % 0.90/1.30 FOF formula (<kernel.Constant object at 0x2b65799e82d8>, <kernel.Constant object at 0x2b65799e8ab8>) of role type named z % 0.90/1.30 Using role type % 0.90/1.30 Declaring z:nat % 0.90/1.30 FOF formula (<kernel.Constant object at 0x2b65799e8950>, <kernel.DependentProduct object at 0x2b6579d413f8>) of role type named more % 0.90/1.30 Using role type % 0.90/1.30 Declaring more:(nat->(nat->Prop)) % 0.90/1.30 FOF formula ((more x) y) of role axiom named m % 0.90/1.30 A new axiom: ((more x) y) % 0.90/1.30 FOF formula (<kernel.Constant object at 0x2b65799e8518>, <kernel.DependentProduct object at 0x2b6579d413b0>) of role type named pl % 0.90/1.30 Using role type % 0.90/1.30 Declaring pl:(nat->(nat->nat)) % 0.90/1.30 FOF formula (forall (Xx:nat) (Xy:nat) (Xz:nat), (((more Xx) Xy)->((more ((pl Xx) Xz)) ((pl Xy) Xz)))) of role axiom named satz19a % 0.90/1.30 A new axiom: (forall (Xx:nat) (Xy:nat) (Xz:nat), (((more Xx) Xy)->((more ((pl Xx) Xz)) ((pl Xy) Xz)))) % 0.90/1.30 FOF formula (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))) of role axiom named satz6 % 0.90/1.30 A new axiom: (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))) % 0.90/1.30 FOF formula ((more ((pl z) x)) ((pl z) y)) of role conjecture named satz19d % 0.90/1.30 Conjecture to prove = ((more ((pl z) x)) ((pl z) y)):Prop % 0.90/1.30 We need to prove ['((more ((pl z) x)) ((pl z) y))'] % 0.90/1.30 Parameter nat:Type. % 0.90/1.30 Parameter x:nat. % 0.90/1.30 Parameter y:nat. % 0.90/1.30 Parameter z:nat. % 0.90/1.30 Parameter more:(nat->(nat->Prop)). % 0.90/1.30 Axiom m:((more x) y). % 0.90/1.30 Parameter pl:(nat->(nat->nat)). % 0.90/1.30 Axiom satz19a:(forall (Xx:nat) (Xy:nat) (Xz:nat), (((more Xx) Xy)->((more ((pl Xx) Xz)) ((pl Xy) Xz)))). % 0.90/1.30 Axiom satz6:(forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))). % 0.90/1.30 Trying to prove ((more ((pl z) x)) ((pl z) y)) % 0.90/1.30 Found satz19a0000:=(satz19a000 z):((more ((pl x) z)) ((pl y) z)) % 0.90/1.30 Found (satz19a000 z) as proof of ((more ((pl x) z)) ((pl y) z)) % 0.90/1.30 Found ((fun (Xz:nat)=> ((satz19a00 Xz) m)) z) as proof of ((more ((pl x) z)) ((pl y) z)) % 0.90/1.30 Found ((fun (Xz:nat)=> (((satz19a0 y) Xz) m)) z) as proof of ((more ((pl x) z)) ((pl y) z)) % 0.90/1.30 Found ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z) as proof of ((more ((pl x) z)) ((pl y) z)) % 0.90/1.30 Found ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z) as proof of ((more ((pl x) z)) ((pl y) z)) % 0.90/1.30 Found (satz6000 ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z)) as proof of ((more ((pl x) z)) ((pl z) y)) % 0.90/1.30 Found ((satz600 (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z)) as proof of ((more ((pl x) z)) ((pl z) y)) % 0.90/1.30 Found (((satz60 z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z)) as proof of ((more ((pl x) z)) ((pl z) y)) % 0.90/1.30 Found ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z)) as proof of ((more ((pl x) z)) ((pl z) y)) % 0.90/1.30 Found ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z)) as proof of ((more ((pl x) z)) ((pl z) y)) % 0.90/1.30 Found (satz6__eq_sym000 ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z))) as proof of ((more ((pl z) x)) ((pl z) y)) % 0.90/1.30 Found ((satz6__eq_sym00 (fun (x1:nat)=> ((more x1) ((pl z) y)))) ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z))) as proof of ((more ((pl z) x)) ((pl z) y)) % 0.90/1.30 Found (((satz6__eq_sym0 x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z))) as proof of ((more ((pl z) x)) ((pl z) y)) % 0.90/1.30 Found ((((satz6__eq_sym z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z))) as proof of ((more ((pl z) x)) ((pl z) y)) % 0.90/1.30 Found ((((satz6__eq_sym z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z))) as proof of ((more ((pl z) x)) ((pl z) y)) % 0.90/1.30 Got proof (((((fun (Xx:nat) (Xy:nat)=> ((((eq_sym nat) ((pl Xx) Xy)) ((pl Xy) Xx)) ((satz6 Xx) Xy))) z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z))) % 0.90/1.30 Time elapsed = 0.554870s % 0.90/1.30 node=172 cost=904.000000 depth=14 % 0.90/1.30:::::::::::::::::::::: % 0.90/1.30 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.90/1.30 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.90/1.30 (((((fun (Xx:nat) (Xy:nat)=> ((((eq_sym nat) ((pl Xx) Xy)) ((pl Xy) Xx)) ((satz6 Xx) Xy))) z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) ((((satz6 y) z) (more ((pl x) z))) ((fun (Xz:nat)=> ((((satz19a x) y) Xz) m)) z))) % 0.90/1.30 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------