%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM683^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n177.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:25 EST 2018 % Result : Theorem 0.64s % Output : Proof 0.64s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM683^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.02/0.23 % Computer : n177.star.cs.uiowa.edu % 0.02/0.23 % Model : x86_64 x86_64 % 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.23 % Memory : 32218.625MB % 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.23 % CPULimit : 300 % 0.02/0.23 % DateTime : Fri Jan 5 12:39:48 CST 2018 % 0.02/0.23 % CPUTime : % 0.02/0.25 Python 2.7.13 % 0.64/0.88 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.64/0.88 FOF formula (<kernel.Constant object at 0x2b34c0eb9248>, <kernel.Type object at 0x2b34c0eb9d40>) of role type named nat_type % 0.64/0.88 Using role type % 0.64/0.88 Declaring nat:Type % 0.64/0.88 FOF formula (<kernel.Constant object at 0x2b34c0b61fc8>, <kernel.Constant object at 0x2b34c0eb9128>) of role type named x % 0.64/0.88 Using role type % 0.64/0.88 Declaring x:nat % 0.64/0.88 FOF formula (<kernel.Constant object at 0x2b34c0eb9ef0>, <kernel.Constant object at 0x2b34c0eb9128>) of role type named y % 0.64/0.88 Using role type % 0.64/0.88 Declaring y:nat % 0.64/0.88 FOF formula (<kernel.Constant object at 0x2b34c0eb9248>, <kernel.Constant object at 0x2b34c0eb9128>) of role type named z % 0.64/0.88 Using role type % 0.64/0.88 Declaring z:nat % 0.64/0.88 FOF formula (<kernel.Constant object at 0x2b34c0eb9bd8>, <kernel.DependentProduct object at 0x2b34c15cb098>) of role type named more % 0.64/0.88 Using role type % 0.64/0.88 Declaring more:(nat->(nat->Prop)) % 0.64/0.88 FOF formula (<kernel.Constant object at 0x2b34c0eb9128>, <kernel.DependentProduct object at 0x2b34c15cb170>) of role type named pl % 0.64/0.88 Using role type % 0.64/0.88 Declaring pl:(nat->(nat->nat)) % 0.64/0.88 FOF formula ((more ((pl z) x)) ((pl z) y)) of role axiom named m % 0.64/0.88 A new axiom: ((more ((pl z) x)) ((pl z) y)) % 0.64/0.88 FOF formula (forall (Xx:nat) (Xy:nat) (Xz:nat), (((more ((pl Xx) Xz)) ((pl Xy) Xz))->((more Xx) Xy))) of role axiom named satz20a % 0.64/0.88 A new axiom: (forall (Xx:nat) (Xy:nat) (Xz:nat), (((more ((pl Xx) Xz)) ((pl Xy) Xz))->((more Xx) Xy))) % 0.64/0.88 FOF formula (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))) of role axiom named satz6 % 0.64/0.88 A new axiom: (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))) % 0.64/0.88 FOF formula ((more x) y) of role conjecture named satz20d % 0.64/0.88 Conjecture to prove = ((more x) y):Prop % 0.64/0.88 We need to prove ['((more x) y)'] % 0.64/0.88 Parameter nat:Type. % 0.64/0.88 Parameter x:nat. % 0.64/0.88 Parameter y:nat. % 0.64/0.88 Parameter z:nat. % 0.64/0.88 Parameter more:(nat->(nat->Prop)). % 0.64/0.88 Parameter pl:(nat->(nat->nat)). % 0.64/0.88 Axiom m:((more ((pl z) x)) ((pl z) y)). % 0.64/0.88 Axiom satz20a:(forall (Xx:nat) (Xy:nat) (Xz:nat), (((more ((pl Xx) Xz)) ((pl Xy) Xz))->((more Xx) Xy))). % 0.64/0.88 Axiom satz6:(forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))). % 0.64/0.88 Trying to prove ((more x) y) % 0.64/0.88 Found m:((more ((pl z) x)) ((pl z) y)) % 0.64/0.88 Instantiate: Xz:=z:nat % 0.64/0.88 Found m as proof of ((more ((pl Xz) x)) ((pl Xz) y)) % 0.64/0.88 Found (satz6010 m) as proof of ((more ((pl x) Xz)) ((pl Xz) y)) % 0.64/0.88 Found ((satz601 (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m) as proof of ((more ((pl x) Xz)) ((pl Xz) y)) % 0.64/0.88 Found (((satz60 x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m) as proof of ((more ((pl x) Xz)) ((pl Xz) y)) % 0.64/0.88 Found (((satz60 x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m) as proof of ((more ((pl x) Xz)) ((pl Xz) y)) % 0.64/0.88 Found (satz6000 (((satz60 x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m)) as proof of ((more ((pl x) Xz)) ((pl y) Xz)) % 0.64/0.88 Found ((satz600 (more ((pl x) Xz))) (((satz60 x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m)) as proof of ((more ((pl x) Xz)) ((pl y) Xz)) % 0.64/0.88 Found (((satz60 y) (more ((pl x) Xz))) (((satz60 x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m)) as proof of ((more ((pl x) Xz)) ((pl y) Xz)) % 0.64/0.88 Found ((((satz6 Xz) y) (more ((pl x) Xz))) ((((satz6 Xz) x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m)) as proof of ((more ((pl x) Xz)) ((pl y) Xz)) % 0.64/0.88 Found ((((satz6 Xz) y) (more ((pl x) Xz))) ((((satz6 Xz) x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m)) as proof of ((more ((pl x) Xz)) ((pl y) Xz)) % 0.64/0.88 Found (satz20a000 ((((satz6 Xz) y) (more ((pl x) Xz))) ((((satz6 Xz) x) (fun (x1:nat)=> ((more x1) ((pl Xz) y)))) m))) as proof of ((more x) y) % 0.64/0.88 Found ((satz20a00 z) ((((satz6 z) y) (more ((pl x) z))) ((((satz6 z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) m))) as proof of ((more x) y) % 0.64/0.88 Found (((satz20a0 y) z) ((((satz6 z) y) (more ((pl x) z))) ((((satz6 z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) m))) as proof of ((more x) y) % 0.64/0.88 Found ((((satz20a x) y) z) ((((satz6 z) y) (more ((pl x) z))) ((((satz6 z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) m))) as proof of ((more x) y) % 0.64/0.88 Found ((((satz20a x) y) z) ((((satz6 z) y) (more ((pl x) z))) ((((satz6 z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) m))) as proof of ((more x) y) % 0.64/0.88 Got proof ((((satz20a x) y) z) ((((satz6 z) y) (more ((pl x) z))) ((((satz6 z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) m))) % 0.64/0.88 Time elapsed = 0.354606s % 0.64/0.88 node=99 cost=655.000000 depth=14 % 0.64/0.88:::::::::::::::::::::: % 0.64/0.88 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.64/0.88 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.64/0.88 ((((satz20a x) y) z) ((((satz6 z) y) (more ((pl x) z))) ((((satz6 z) x) (fun (x1:nat)=> ((more x1) ((pl z) y)))) m))) % 0.64/0.88 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------