%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : NUM684^1 : TPTP v7.0.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n084.star.cs.uiowa.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz % Memory : 32218.625MB % OS : Linux 3.10.0-693.2.2.el7.x86_64 % CPULimit : 300s % DateTime : Mon Jan 8 13:11:26 EST 2018 % Result : Theorem 3.91s % Output : Proof 3.91s % Verified : % SZS Type : None (Parsing solution fails) % Syntax : Number of formulae : 0 % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.03 % Problem : NUM684^1 : TPTP v7.0.0. Released v3.7.0. % 0.00/0.03 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.02/0.23 % Computer : n084.star.cs.uiowa.edu % 0.02/0.23 % Model : x86_64 x86_64 % 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz % 0.02/0.23 % Memory : 32218.625MB % 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64 % 0.02/0.23 % CPULimit : 300 % 0.02/0.23 % DateTime : Fri Jan 5 12:44:04 CST 2018 % 0.02/0.23 % CPUTime : % 0.07/0.25 Python 2.7.13 % 3.91/4.10 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 3.91/4.10 FOF formula (<kernel.Constant object at 0x2aae63fb9ef0>, <kernel.Type object at 0x2aae642a7a28>) of role type named nat_type % 3.91/4.10 Using role type % 3.91/4.10 Declaring nat:Type % 3.91/4.10 FOF formula (<kernel.Constant object at 0x2aae63fb97e8>, <kernel.Constant object at 0x2aae63fb9c20>) of role type named x % 3.91/4.10 Using role type % 3.91/4.10 Declaring x:nat % 3.91/4.10 FOF formula (<kernel.Constant object at 0x2aae63fb9830>, <kernel.Constant object at 0x2aae642a7a70>) of role type named y % 3.91/4.10 Using role type % 3.91/4.10 Declaring y:nat % 3.91/4.10 FOF formula (<kernel.Constant object at 0x2aae63fb9c20>, <kernel.Constant object at 0x2aae642a7ef0>) of role type named z % 3.91/4.10 Using role type % 3.91/4.10 Declaring z:nat % 3.91/4.10 FOF formula (<kernel.Constant object at 0x2aae63fb9830>, <kernel.DependentProduct object at 0x2aae642a79e0>) of role type named pl % 3.91/4.10 Using role type % 3.91/4.10 Declaring pl:(nat->(nat->nat)) % 3.91/4.10 FOF formula (((eq nat) ((pl z) x)) ((pl z) y)) of role axiom named i % 3.91/4.10 A new axiom: (((eq nat) ((pl z) x)) ((pl z) y)) % 3.91/4.10 FOF formula (forall (Xx:nat) (Xy:nat) (Xz:nat), ((((eq nat) ((pl Xx) Xz)) ((pl Xy) Xz))->(((eq nat) Xx) Xy))) of role axiom named satz20b % 3.91/4.10 A new axiom: (forall (Xx:nat) (Xy:nat) (Xz:nat), ((((eq nat) ((pl Xx) Xz)) ((pl Xy) Xz))->(((eq nat) Xx) Xy))) % 3.91/4.10 FOF formula (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))) of role axiom named satz6 % 3.91/4.10 A new axiom: (forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))) % 3.91/4.10 FOF formula (((eq nat) x) y) of role conjecture named satz20e % 3.91/4.10 Conjecture to prove = (((eq nat) x) y):Prop % 3.91/4.10 We need to prove ['(((eq nat) x) y)'] % 3.91/4.10 Parameter nat:Type. % 3.91/4.10 Parameter x:nat. % 3.91/4.10 Parameter y:nat. % 3.91/4.10 Parameter z:nat. % 3.91/4.10 Parameter pl:(nat->(nat->nat)). % 3.91/4.10 Axiom i:(((eq nat) ((pl z) x)) ((pl z) y)). % 3.91/4.10 Axiom satz20b:(forall (Xx:nat) (Xy:nat) (Xz:nat), ((((eq nat) ((pl Xx) Xz)) ((pl Xy) Xz))->(((eq nat) Xx) Xy))). % 3.91/4.10 Axiom satz6:(forall (Xx:nat) (Xy:nat), (((eq nat) ((pl Xx) Xy)) ((pl Xy) Xx))). % 3.91/4.10 Trying to prove (((eq nat) x) y) % 3.91/4.10 Found i0:=(i (fun (x0:nat)=> (P x))):((P x)->(P x)) % 3.91/4.10 Found (i (fun (x0:nat)=> (P x))) as proof of (P0 x) % 3.91/4.10 Found (i (fun (x0:nat)=> (P x))) as proof of (P0 x) % 3.91/4.10 Found eq_ref00:=(eq_ref0 x):(((eq nat) x) x) % 3.91/4.10 Found (eq_ref0 x) as proof of (((eq nat) x) b) % 3.91/4.10 Found ((eq_ref nat) x) as proof of (((eq nat) x) b) % 3.91/4.10 Found ((eq_ref nat) x) as proof of (((eq nat) x) b) % 3.91/4.10 Found ((eq_ref nat) x) as proof of (((eq nat) x) b) % 3.91/4.10 Found eq_ref00:=(eq_ref0 b):(((eq nat) b) b) % 3.91/4.10 Found (eq_ref0 b) as proof of (((eq nat) b) y) % 3.91/4.10 Found ((eq_ref nat) b) as proof of (((eq nat) b) y) % 3.91/4.10 Found ((eq_ref nat) b) as proof of (((eq nat) b) y) % 3.91/4.10 Found ((eq_ref nat) b) as proof of (((eq nat) b) y) % 3.91/4.10 Found i:(((eq nat) ((pl z) x)) ((pl z) y)) % 3.91/4.10 Instantiate: Xz:=z:nat % 3.91/4.10 Found i as proof of (((eq nat) ((pl Xz) x)) ((pl Xz) y)) % 3.91/4.10 Found (satz6010 i) as proof of (((eq nat) ((pl Xz) x)) ((pl y) Xz)) % 3.91/4.10 Found ((satz601 ((eq nat) ((pl Xz) x))) i) as proof of (((eq nat) ((pl Xz) x)) ((pl y) Xz)) % 3.91/4.10 Found (((satz60 y) ((eq nat) ((pl Xz) x))) i) as proof of (((eq nat) ((pl Xz) x)) ((pl y) Xz)) % 3.91/4.10 Found (((satz60 y) ((eq nat) ((pl Xz) x))) i) as proof of (((eq nat) ((pl Xz) x)) ((pl y) Xz)) % 3.91/4.10 Found (satz6000 (((satz60 y) ((eq nat) ((pl Xz) x))) i)) as proof of (((eq nat) ((pl x) Xz)) ((pl y) Xz)) % 3.91/4.10 Found ((satz600 (fun (x1:nat)=> (((eq nat) x1) ((pl y) Xz)))) (((satz60 y) ((eq nat) ((pl Xz) x))) i)) as proof of (((eq nat) ((pl x) Xz)) ((pl y) Xz)) % 3.91/4.10 Found (((satz60 x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) Xz)))) (((satz60 y) ((eq nat) ((pl Xz) x))) i)) as proof of (((eq nat) ((pl x) Xz)) ((pl y) Xz)) % 3.91/4.10 Found ((((satz6 Xz) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) Xz)))) ((((satz6 Xz) y) ((eq nat) ((pl Xz) x))) i)) as proof of (((eq nat) ((pl x) Xz)) ((pl y) Xz)) % 3.91/4.10 Found ((((satz6 Xz) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) Xz)))) ((((satz6 Xz) y) ((eq nat) ((pl Xz) x))) i)) as proof of (((eq nat) ((pl x) Xz)) ((pl y) Xz)) % 3.91/4.10 Found (satz20b000 ((((satz6 Xz) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) Xz)))) ((((satz6 Xz) y) ((eq nat) ((pl Xz) x))) i))) as proof of (((eq nat) x) y) % 3.91/4.10 Found ((satz20b00 z) ((((satz6 z) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) z)))) ((((satz6 z) y) ((eq nat) ((pl z) x))) i))) as proof of (((eq nat) x) y) % 3.91/4.13 Found (((satz20b0 y) z) ((((satz6 z) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) z)))) ((((satz6 z) y) ((eq nat) ((pl z) x))) i))) as proof of (((eq nat) x) y) % 3.91/4.13 Found ((((satz20b x) y) z) ((((satz6 z) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) z)))) ((((satz6 z) y) ((eq nat) ((pl z) x))) i))) as proof of (((eq nat) x) y) % 3.91/4.13 Found ((((satz20b x) y) z) ((((satz6 z) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) z)))) ((((satz6 z) y) ((eq nat) ((pl z) x))) i))) as proof of (((eq nat) x) y) % 3.91/4.13 Got proof ((((satz20b x) y) z) ((((satz6 z) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) z)))) ((((satz6 z) y) ((eq nat) ((pl z) x))) i))) % 3.91/4.13 Time elapsed = 3.577773s % 3.91/4.13 node=616 cost=432.000000 depth=14 % 3.91/4.13:::::::::::::::::::::: % 3.91/4.13 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p % 3.91/4.13 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p % 3.91/4.13 ((((satz20b x) y) z) ((((satz6 z) x) (fun (x1:nat)=> (((eq nat) x1) ((pl y) z)))) ((((satz6 z) y) ((eq nat) ((pl z) x))) i))) % 3.91/4.13 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------