%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : NUM695^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n012.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 07:57:06 PM UTC 2025 % Result : Theorem 3.43s 3.60s % Output : Proof 3.43s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.12 % Problem : NUM695^1 : TPTP v9.2.0. Released v3.7.0. % 0.07/0.13 % Command : duper %s % 0.14/0.34 % Computer : n012.cluster.edu % 0.14/0.34 % Model : x86_64 x86_64 % 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.34 % Memory : 8042.1875MB % 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.34 % CPULimit : 300 % 0.14/0.34 % WCLimit : 300 % 0.14/0.34 % DateTime : Fri Oct 3 06:54:08 EDT 2025 % 0.14/0.35 % CPUTime : % 3.43/3.60 SZS status Theorem for theBenchmark.p % 3.43/3.60 SZS output start Proof for theBenchmark.p % 3.43/3.60 Clause #3 (by assumption #[]): Eq (∀ (Xx Xy : nat), more (pl Xx Xy) Xx) True % 3.43/3.60 Clause #4 (by assumption #[]): Eq (∀ (Xx : nat), Eq (suc Xx) (pl n_1 Xx)) True % 3.43/3.60 Clause #5 (by assumption #[]): Eq (Not (more (suc x) n_1)) True % 3.43/3.60 Clause #10 (by clausification #[5]): Eq (more (suc x) n_1) False % 3.43/3.60 Clause #13 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy : nat), more (pl a Xy) a) True % 3.43/3.60 Clause #14 (by clausification #[13]): ∀ (a a_1 : nat), Eq (more (pl a a_1) a) True % 3.43/3.60 Clause #15 (by clausification #[4]): ∀ (a : nat), Eq (Eq (suc a) (pl n_1 a)) True % 3.43/3.60 Clause #16 (by clausification #[15]): ∀ (a : nat), Eq (suc a) (pl n_1 a) % 3.43/3.60 Clause #17 (by superposition #[16, 14]): ∀ (a : nat), Eq (more (suc a) n_1) True % 3.43/3.60 Clause #30 (by superposition #[17, 10]): Eq True False % 3.43/3.60 Clause #33 (by clausification #[30]): False % 3.43/3.60 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------